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## Algebra 1

### Course: Algebra 1 > Unit 8

Lesson 12: Average rate of change word problems# Average rate of change word problem: graph

CCSS.Math:

Average rate of change tells us how much the function changed per a single time unit, over a specific interval. It has many real-world applications. In this video, we find the average rate of descent of a skydiver over a specific time interval.

## Want to join the conversation?

- How do you know to do 375 - 650, and not the reverse?(8 votes)
- It doesnt matter. If you chose 375-650 you should put its correspondig x coordinate values in the same order (8-3) and viceversa (650-375)/(3-8).

The signs do the work(22 votes)

- why we didn't take average of 700-200 ?

(200-700)/(10-0) = -50m/s(3 votes)- Because we were asked the average rate of change between 3 and 8 seconds after she jumped, not between 0 and 10 seconds.(17 votes)

- At1:46and2:27, why does Sal approximate that h(3) is 650? We can clearly see that when x is 3, y is 650!(3 votes)
- If you look at the graph closely, you will see h(3) is actually slightly above 650. The graph is not crossing directly at y=650. So, it is an approximation.(14 votes)

- Why was H (8) used first in the formula? What are the rules in what goes in what order?(1 vote)
- It does seem confusing but after understanding it it's quite simple.

First, let's redo the calc.

1. change of H/change of Time

2. H(8) - H(3)/8 - 3

3. 375 - 650/5

4. -275/5

5. -55

And now let's do this the other way.

1. change of H/change of Time

2. H(3) - H(8)/3 - 8

3. 650 - 375/-5

4. 275/-5

5. -275/5 ( Hmmm... something seems similar )

6. -55

So basically no matter which one we put first we always get the same answer. This is one of the special things about maths. When we are calculating the rate of change of things no matter which value you put first you always get the same answer!

Hope this helped ( even if help came after 2 years )!(9 votes)

- There are two sections of the graph, x^2 and x. It's hard to believe Theresa slowed down to terminal velocity. I can imagine something speeding up to terminal velocity but not slowing down. What's going on?(3 votes)
- It's just the problem they use. It bugs me to, but sometimes you just have to ignore the setting of the question, and focus on the type and numbers.(2 votes)

- how would you do a line that goes up and down(1 vote)
- These "lines" represent data, or cause and effect information gathered about the world. To get a vertical line from an experiment would mean that when you test a single situation (x) that the response of the world is that everything and anything can happen (range is plus/minus infinity). Also, because there's only a single value of x, we are doing an experiment at only one data point, which is not an experiment. A vertical line cannot happen in real life and is not considered a "function". There is, however, a way to express a vertical line, but not in y=mx+b format. Just write an equation that says x never changes and y can be anything. For example, x=2.(2 votes)

- What is the rate of change of the profit eaned with respect to the nuber of bras of soap sold(0 votes)

## Video transcript

Teresa went skydiving. The graph below discribes Teresa's height, measured in meters, as a function of time, measured in seconds. So let's look at this graph over here. It's actually quite large, so let me zoom out a little bit. And we can see that at time zero her height is seven hundred meters and then as time increases, as we move to the right her height is decreasing. And her height is decreasing at faster and faster rates as we move to the right so her- her- the rate of decline of her height is quite steep as we approach ten seconds after she jumps And then we can see all of a sudden, then we can see all of a sudden her rate of decline slows down She's still declining as -as we move forward in time, but she's declining at a slower rate. And so we can say she's declining at a --- or she is --- her height is changing at a less negative rate It's -It's quite a negative rate right over here --- seems roughly a fairly negative rate but then it becomes a less negative rate right over here her height is changing at a less negative rate and it makes sense that this is when she deploys the parachute, so after 10 seconds she deploys the parachute so she jumps at 0 seconds, 10 seconds she deploys the parachute. Alright so let's see what they're asking --- actually asking us. They say Complete the following sentence Between 3 seconds and 8 seconds after Teresa jumped, her height decreased, on average, by approximately blank meters per second. So between 3 seconds, and 8 seconds, so at 3 seconds --- so time is 3 right over there So, Let's see what H(3) is. what is her height at 3 seconds and I'm just looking
at a graph so I'm going to have to Ballpark it so at 3 seconds at 3 seconds
her height looks pretty close it's pretty close we just have to approximate
it so her height at the height after 3 seconds it looks like it's about halfway
between 600 and 700 so it looks like it's about 650 meters and then we care
between 3 seconds and 8 seconds so our height at 8 seconds let's look at that
at 8 seconds let's see this looks about halfway it looks about halfway between
350 between 350 and 400 so I'll say her height at 8 seconds actually since I'm
approximating it let me put a little squiggly equal sign here her height
after 8 seconds looks like it's approximately 300 and looks
approximately 375 meters 375 meters so what is her average rate of change her
height decreased on average by approximately so we what we want to do
is we forgot to figure out the average rate of change which you could view as
the slope of the line that connects these two points the slope of this line
is going to be her average rate of change so let's think about that her
average rate of change her change in height over the change in time for that
interval well her change in height after at 8 seconds she is at let me write it
this way her height at 8 seconds - her height at 3 seconds so this is going to
be her change in height and the change in time is 8 seconds she finishes at 8
seconds - where she started or the interval that we care about starting at
3 seconds and so H of 8 we already said this is approximately 375 H of 3 this is
650 and then of course 8 minus 3 is going to be equal to 5
I just want emphasize this is just her average rate of change for approximate
average rate of change over this interval as we as we go from 3 to 8
seconds our height goes from H of 3 to H of 8 so this is going to be let's see
375 - 650 let's see if it was 375 - 675 it would
be negative 300 and so this is going to be but then we're not subtracting 675
we're subtracting 650 so it's going to be 25 it's going to be 25 more so this
is going to be negative 275 over 5 let me make sure I did that math right let
me make sure I did that math right so it's 375 - 650 is
negative 275 does that make sense let's see 275 plus 375 would be 2 650
yeah that is right all right so let's just figure out what this is so 5 I'll
just figure out what 5 goes into 275 and then we can remember the negative 5 goes
into 27 5 times 5 times 5 is 25 subtract we get a to bring down to 5 5
goes into 25 five times and then we're not going to have a remainder so this is
going to be equal to negative 55 negative 55 and the unit's our height is
given in meters so this part up here this is in meters up here meters per
second so her change in height or average change in height over or the
average rate of change of height over this five seconds over this five seconds
is negative 55 meters per second one way to think about it the slope right over
here the slope is equal to negative 55 now it might be tempting to just
write negative 55 right over here but let's just think about whether that
would be right between 3 seconds and 8 seconds after Teresa jumped her height
decreased on average by approximately negative 55 meters per second and
decrease is important because they're already saying that it's decreased when
this negative is telling us that we're decreasing we're decreasing at a rate of
55 meters per second our average rate of change is a decrease our average rate of
high a change of height over time is a decrease of 55 meters per second well
the negative is already saying the decrease so we're not decreasing at a
negative rate of change we would be decreasing at 55 meters per second so
let me just write it 55 meters per second if they asked if they asked her
height if we asked her height if we if they asked the average change of height
average rate of change let me write this the average rate of change of change of
H over or let me say of H from 3 seconds 3 seconds
to 8 seconds well now this would be negative 55
meters per second but when they're saying that her height decrease that's
re taking the negative into consideration they're saying it's
definitely decreasing that's what the negatives already telling us it's
decreasing by a rate of 55 meters per second hopefully that makes some sense