Equations and functions are not the same thing, but they can be related in several ways. In this video, we obtain a function from an equation. The function represents the same relationship between the quantities in the equation.
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- Hi, there is this one problem in the exercise "Write function rules from equations" that I am having a hard time with. It wants me to enter the greek letter upsilon as part of the answer, but I don't know how. How can I do that??(2 votes)
- The input is b, so, f(b), the output is a, so f(b)=a, whatever input b we plug into our function, it's gonna output a.
Therefore, to satisfy the equation we need to solve the equation in terms of a, and then just replace the a in f(b)=a, and that's our function, bellow is a summary of the steps.
f(b)=a // whatever b we input, the function outputs a
4a+7b = -52 // this is the equation our a has to satisfy
a = -13-(7/4)*b // therefore we solve for a, so the equation stands true
f(b) = -13-(7/4)*b // we replace the a in f(b)=a with whatever a equals to(8 votes)
- Why would you solve for A if you are trying to figure out a formula for B ? In other words trying to get B by it self. For this problem I subtracted 4a by itself and -52 which then simplified to 7b= -52-4a / 7 which simplified even more to which b = -52-4a / 7(15 votes)
- You solve for a because a is the output or in other words a is the f(B). I think this is right. Any other ideas?(5 votes)
- In school, I have a teacher that doesn't explain anything. I am a 6th grader so in Algebra 1 and I am having a lot of trouble with functions. I can solve functions but creating a linear function equation is difficult for me. Could anyone help explain it to me in an easy way that I could understand?(16 votes)
- In a normal linear equation you might have something like this: a = 2b + 6
You can find out what a is for any value of b by imputing the b value into the equation. For example, what is a when b is 4?
a = 2 x 4 + 6
a = 8 + 6
a = 14
In a linear function equation instead of finding a for any value of b, you find the f(b) for any value of b. You can input any value of b and get you're answer without worrying about a.
Basically, f(b) = a = 2b + 6 or f(b) = 2b + 6(2 votes)
- So basically -13 - (7/4b) is the same as a, which is the same as f(b). Am I right?(8 votes)
- Yes, you are correct.
When f(b) is given a "b" value we get an "a" value which is the same as "f(b)".
For example if we're given the "b" value of 0, then f(0) = -13 and that is what "a" would be if "b" is zero. "f(b)" is a more concise way to say this since it says what value of "b" was used to get the "f(b)" value - to get a particular "a" value.
I hope this helps.(11 votes)
- I was starting to understand this until I ran into a problem on the exercises.
a - 7 = 3(b+2)
I was able to get a by itself
a = 3(b+2)+7
in the hints it said it would simplify down to
a = 3b + 13.
My question is how do you get 13?(1 vote)
- Look at the second line:
a=3(b+2)+7 ---> a=3*b+3*2+7 ---> a=3b+6+7 ----> a=3b+13
That is how you get 13!
- so technically an equation in two variables is a function and equation in one variable is just an equation(3 votes)
- Not necessarily.
A function is a relationship where each input value (X) will create only one output value (Y). Basically, a single input value, can't create 2 different output values.
Any equation with one or two variables that meet this definition would be a function.
y = 5 is the equation for a horizontal line. It is a function where all values of X have a y-value = 5. Yet it has one variable.
x = 5 is the equation for a vertical line. It is not a function because in this situation, the input value (x=5) has an infinite number of output values.
All other equations of lines (Ax + By = C) are functions because the meet the definition of a function.
But, the equation of a circle, which also uses 2 variables, would not be a function because each input value (x) creates 2 output values (y).
If an equation is not a function, sometimes we can still change it into a function if we restrict its inputs or outputs.
Hope this makes sense.(7 votes)
- The practice problems are asking my to rearrange the problem so one of the variables is the independent variable but I don't understand the whole "independent" variable thing. What makes it independent? What does that even mean?
Ex: Rearrange the equation so q is the independent variable.
-7q+12r=3q-4r (that was one of the practice problems)(4 votes)
- Here is a video about independent varibles in khan academy: https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-equations-and-inequalities/cc-6th-dependent-independent/v/dependent-and-independent-variables-exercise-example-1(2 votes)
- I am doing the exercises now but I haven't gotten a single one right. I don't think Sal gave an adequate enough explanation. He only did a couple examples and when I look at the hints they seem lazy and not very in depth... XD what do I do?(2 votes)
- I am attempting the Function rules from Equations, but it makes so sense. For example, it gives problems like:
Rearrange the equation so x is the independent variable.
- 4 x - 6 = - 5 y - 6
That doesn't make sense at all. Actually, I know that you need to get the variable other than x on the left side (y would be the dependent variable; y's value is solely dependent on the value of x: y = __ + __x), but I don't know what to do with the other numbers. First, how do I get y on the other side?
What do I do with the constants? Here's something that makes me more confused. In the hints, it said that you subtract them or something? Once, I had
- 3 a + 6 b = a + 4 b + 3 a
and it said to subtract the 4b from the 6b to get 2b, but both of those numbers are positive. Why should they be subtracted from one another?(3 votes)
- Your 1st equation: To isolate "y",
1) Add 6 to both sides
2) Divide both sides by -5
"y" will be on the right side, but you can slip the sides of an equation: 5 = 2+3 is the same as saying 2+3 = 5
Your 2nd equation: Remember, to move any item across the "=", you use the opposite operation. You need to get all the "b" on the same side. So, you subtract 4b from both sdies.
Hope this helps.(2 votes)
For a given input value b, the function f outputs a value a to satisfy the following equation 4a plus 7b is equal to negative 52. So for a given input b, the function f, the function f will output an a that satisfies this relationship right over here for the a and the b. Write a formula for f of b in terms of b. So we want to do, we just want to solve for -- if we're given a "b", what "a" does that imply that we have to output? Or another way to think about it is -- let's just solve for a, or we could think about a as being a function of b. So let's write this. So we have 4a plus 7b -- is equal to negative 52. So I can solve for a in terms of b, that any b that I have -- Let's say these b's are on the right hand side I can put it in. I can substitute that value for b and I can just solve for a. I can solve for a that needs to be outputted. So let's do that. Let's solve for a. So I want to get all the a on I wanna just have an a leftover on the left hand side, and have everything else on the right hand side including the b's. So let's get rid of this b on the left hand side. And I can do that by subtracting 7b. Of course I wanna do that to both sides. I can't just do an equation and do an operation only on one side like that. So let's subtract, and we are left with we are left with -- the 7b's add up to zero. 7b minus 7b. We're left with 4a is equal to negative 52 minus 7b, minus 7b. Now, to isolate the a here, just to have an a here instead of 4a, we can divide both sides by 4. We can divide both sides by 4. So I'm gonna divide everything by 4. And on the left hand side, we got our goal. We are left with an a is equal to -- Now what's negative 54 divided by -- What is the negative 52 divided by 4? So let's think about it. 52 is 40 plus 12. 40 divided by 4 is 10. 12 divided by 4 is 3. So it's gonna be 13. Negative 13. So it's negative 13 minus 7/4 b minus 7/4 b. So given a "b", if you give me a "b", I can put that value right over here, and I can calculate what the corresponding a needs to be in order to satisfy this relationship. So if I want a formula for f of b in terms of b, I can say, look, you give me a "b", the output of our function, which is f of a. The output of our function is going to be -- is going to be negative 13 minus 7/4 b, because the output of our function needs to be an "a" that will satisfy -- that will satisfy this equation up here. So hopefully that helped.