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Algebra 1
Course: Algebra 1 > Unit 4
Lesson 1: Two-variable linear equations introWorked example: solutions to 2-variable equations
CCSS.Math: ,
How do you check if an ordered pair is a solution to a given equation? You need to plug in the numbers and see what equality results. Watch this video to see a worked example.
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At0:33, would the equation y = -2+ 4/3y be equivalent?(15 votes)
what if you are not given an ordered pair and you have to figure out this equation(7 votes)
How are you going to create an equation if you are not given at least one ordered pair? The ordered pair could be implied by giving the x or y intercept, but it is still an ordered pair.(8 votes)
can't you simplify the equation first? like 4x + 3y = 6?(4 votes)
You sure can - if you think that will help you.
Look what happened in your case: 4x - 1 = 3y + 5 simplifies to 4x - 3y = 6 not 4x + 3y = 6
Keep Studying!
Keep Asking Questions!(6 votes)
does this cover absolute vale equalities and inequalities(3 votes)
I saw nothing here about absolute values which would look like "|x|" or |3|=3 or |-3|=3 OR |-9|=9
The best way to think about absolute values is- "No matter the sign (+ or -) the number remains positive, because the absolute value cannot be negative" Hope that helps. Now inequalities, something simple like....... 1<x<3 where "x" is greater then 1 but less then 3.. The interval notation would be (SET BUILDER NOTATION!)----> {x|x>1, x<3} or (INTERVAL NOTATION(WHICH IS INCLUDING A UNION aka "U"))--> (1,x)U(x,3)...... if the sign was a "greater than or equal to, or less than or equal to" then the interval notation would be [1,x]U[x,3].... I hope this helps.(8 votes)
What is an "ordered" pair?(2 votes)- A point on the coordinate plane that gives the horizontal distance from the origin (x) and the vertical distance (y) that is in the form (x,y). If you create a table from a linear equation, you get a series of ordered pairs.(9 votes)
- solve the following systems of linear equations by elimination
12x+5y=23
2x-7y=39(5 votes)- Add two times the first equation to the second equation to eliminate x:
12x + 5y = 23
2x - 7y = 39
(12x + 5y) + 2(2x - 7y) = 23 + 2 * 39
26x - 18y = 101
So, y = (26x - 101) / -18. Substitute the expression for y back into the first equation to solve for x:
12x + 5y = 23
12x + 5((26x - 101) / -18) = 23
Expand the right side and simplify:
12x + (130x - 505) / -18 = 23
-6x - 505 / -18 = 23
Multiply both sides by -18 to get rid of the fraction:
6x + 505 = -414
Subtract 505 from both sides to isolate x:
6x = -919
Divide both sides by 6 to find x:
x = -153
Finally, substitute the value of x back into the expression for y:
y = (26x - 101) / -18
y = (26 * -153 - 101) / -18
y = 24.
The solution is x = -153 and y = 24.(3 votes)
So my math book says that I should rewrite the equation first, simplify it, then graph it. how do I rewrite it? I keep trying and I keep getting the wrong answer.
P.s. It gives me stuff like, 4X + Y = 6(5 votes)- rewriting for graphing purposes usually means to put in slope intercept form (isolate the y).
Example: 4x + 3y = 9. Subtract 4x to get 3y=-4x+9
Divide all by 3 to get 3/3 y= -4/3 x + 9/3, reduce to get y=-4/3 x + 3. Graph y intercept at (0,3), go down 4 right 3 to get to point (3,-1).(2 votes)
I must be missing something that was already said, or something I don't know. But if the equation is like y = -2x - 5. Could you still be able to do what he is doing in the video? I feel like you can but how?(3 votes)
You can! Anytime you are asked to determine if a point (an ordered pair of (x,y)) is a solution, we use substitution. We use the x-value for "x" in the equation and the y-value for "y" in the equation.
Example: Is (2, 3) a solution to your equation: y = -2x - 5?
Substitute:3 = -2(2) - 5
Simplify the right side:3 = -4 - 53 = -9
Since these are not equal, we know the point (2,3) is not a solution to this equation. Or, is not a point on the line that is created from this equation.
If the 2 sides turn out to be equal, then you know the point is a solution to the equation.
Hope this helps.(6 votes)
Its not clear to me how the fractional values are pointed on graph(3 votes)- Try this video that shows how to find fractions on a number line: https://www.khanacademy.org/math/arithmetic/fraction-arithmetic/arith-review-fractions-on-the-number-line/v/fractions-on-a-number-line
Hope this helps.(3 votes)
Is there an easy way to narrow down the answer besides go through each answer one by one? If so what is it?(1 vote)- No, even if simplified there would be an infinite amount of values for x and y that satisfy the question. This the question is asking which would be a plausible solution so plugging in is the only option in this scenario.(5 votes)
0:33Video transcript
- [Voiceover] "Which of
the ordered pairs is a "solution of the following equation?" 4x minus one is equal to 3y plus five. Now, when we look at an
ordered pair we wanna figure out whether it's a
solution, we just have to remind ourselves that
in these ordered pairs the convention, the standard,
is is that the first coordinate is the x coordinate,
and the second coordinate is the y coordinate. So they're gonna, if this is
a solution, if this ordered pair is a solution, that means
that if x is equal to three and y is equal to two,
that that would satisfy this equation up here. So let's try that out. So, we have four times x. Well we're saying x needs
to be equal to three, minus one, is going to be
equal to three times y. Well, if this ordered
pair is a solution then y is going to be equal
to two, so three times y, y is two, plus five. Notice all I did is wherever I saw the x, I substituted it with three, wherever I saw the y, I
substituted it with two. Now let's see if this is true. Four times three is twelve, minus one. Is this really the same
thing as three times two which is six, plus five? See, 12 minus one is 11, six plus five is also 11. This is true, 11 equals 11. This pair three, two does
satisfy this equation. Now let's see whether
this one does, two, three. So this is saying when x is equal to two, y would be equal to
three for this equation. Let's see if that's true. So four times x, we're
now gonna see if when x is two, y can be three. So four times x, four times two, minus one is equal to three times y, now y we're testing to
see if it can be three. Three times three plus five, let's see if this is true. Four times two is eight, minus one, is this equal to three times three? So that's nine plus five. So is seven equal to 14? No, clearly seven is not equal to 14. So these things are not
equal to each other. So this is not a solution,
when x equals two y cannot be to three and
satisfy this equation. So only three, two is a solution.