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## Algebra 1

### Course: Algebra 1 > Unit 14

Lesson 2: Solving and graphing with factored form# Zero product property

The zero product property states that if a⋅b=0 then either a or b equal zero. This basic property helps us solve equations like (x+2)(x-5)=0.

## Want to join the conversation?

- how could you use the zero product property if the equation wasn't equal to 0?(28 votes)
- I assume you're dealing with a quadratic?

If yes, then you can**force the equation equal to 0**. Well, maybe not "force" but you can rearrange the equation such that you will have the quadratic in the form`Ax^2 + Bx^2 + C = 0`

.

Example:

Solve for`5 = x^2 + 4x + 8`

.`5 = x^2 + 4x + 8`

0 = x^2 + 4x + 3 { subtract 5 from both sides }

0 = (x + 3)(x + 1) { factorise }

x = -3 or x = -1 {zero product property}(68 votes)

- I still don't understand about which is the smaller x. In the practice after this video, it talks about the smaller x and the larger x. Which one is which? Is the smaller one the first one? I don't know if it's being literal or not.(22 votes)
- I'm pretty sure that he is being literal, saying that the smaller x has a value less than the larger x.(18 votes)

- how would you work out the equation...a^2-6a=-8? how would you find a?(5 votes)
- a^2-6a=-8

a^2-6a+8 = -8+8---------------add 8 to both sides

a^2-6a+8 = 0------------------- (-8) and 8 cancel out

(you might want to know "grouping", which is a way of factoring before you read the next steps.)

(a-2)(a-4) = 0-------------------factor using "grouping"

a-2=0, or a-4=0----------------solve for a

a=2, or a=4(22 votes)

- How do you write an equation in standard form if you’re only given a point and a vertex(7 votes)
- The standard form of quadratic functions is f(x) = a(x - h) ^ 2 + k. Since (h, k) is the vertex, you will just have to solve the equation for 'a' by changing f(x) and x into the coordinates of the point.(9 votes)

- Is it possible to have a zero-product equation with no solution? (such as when one or both values of x is a nonreal number)(6 votes)
- The solution x = 0 means that the value 0 satisfies

the equation, so there is a solution. "No solution"

means that there is no value, not even 0, which would satisfy the equation.(10 votes)

- I understood the concept of this no problem, and calculated all the values correctly, but....

For some reason the practice questions required we were asked to put the values in order, and on one question I put them in reverse order.

Is there is a mathematical reason for this order requirement? If so, I'll hold my hands up and say I should have concentrated more.

If it's because the web developer found it easier to test for a single specific value in each box, then I despair.(7 votes)- I believe the reason is the later. Who ever designed the page found it easier to check the answers in order (easier programming). So, pay attention to the directions in the exercise set. They always tell you if they want the smallest result first.(4 votes)

- In the second example given in the video, how will you graph that example?(6 votes)
- This might help https://www.khanacademy.org/math/algebra/quadratics/factored-form-alg1/v/graphing-quadratics-in-factored-form

this above is actually the next video XD

maybe you've already figured it out, but still...

hope you find this helpful! happy learning:)(6 votes)

- So what would you do to solve if it was for example, 2x^2-11x-21=0 ??(4 votes)
- Factor your trinomial using grouping. If you have forgotten this factoring technique, see the lessons at this link: https://www.khanacademy.org/math/algebra/polynomial-factorization/factoring-quadratics-2/v/factor-by-grouping-and-factoring-completely

Once the quadratic is factored, you can use the zero product rule as demonstrated in this video.(7 votes)

- 0 times anything equals 0.....what if i did 90 X 0 + 1 = 1?(4 votes)
- yees, anything times 0 is 0, and u r adding 1 to zero.(2 votes)

- Isn't the zero product property finding the x-intercepts? Wouldn't the two x values that we found be the x-intercepts of a parabola-shaped graph?(3 votes)
- Yep!

However, calling it the "zero-product property" helps explain WHY it works. If I have something like (x-2)(x+8)=0, either (x-2) or (x+8) must be 0. Why? Because the only time a product of numbers is 0 is when at least one of those numbers is 0.(4 votes)

## Video transcript

- [Instructor] Let's say
that we've got the equation two X minus one times X plus four is equal to zero. Pause this video and see
if you can figure out the X values that would
satisfy this equation, essentially our solutions
to this equation. Alright, now let's work
through this together. So at first, you might be tempted to multiply these things out, or there's multiple ways that you might have tried to approach it, but the key realization here is that you have two
things being multiplied, and it's being equal to zero. So you have the first
thing being multiplied is two X minus one. This is expression is being multiplied by X plus four, and to get it to be equal to zero, one or both of these expressions needs to be equal to zero. Let me really reinforce that idea. If I had two variables, let's say A and B, and I told you A times B is equal to zero. Well, can you get the
product of two numbers to equal zero without at least one of them being equal to zero? And the simple answer is no. If A is seven, the only way that you would get zero is if B is zero, or if B was five, the only way to get zero is if A is zero. So you see from this example, either, let me write this down, either A or B or both, 'cause zero times zero is zero, or both must be zero. The only way that you get the
product of two quantities, and you get zero, is if one or both of
them is equal to zero. I really wanna reinforce this idea. I'm gonna put a red box around it so that it really gets
stuck in your brain, and I want you to think about why that is. Try to come up with two numbers. Try to multiply them so that you get zero, and you're gonna see
that one of those numbers is going to need to be zero. So we're gonna use this
idea right over here. Now this might look a
little bit different, but you could view two
X minus one as our A, and you could view X plus four as our B. So either two X minus one
needs to be equal to zero, or X plus four needs to be equal to zero, or both of them needs to be equal to zero. So I could write that as two X minus one needs to be equal to zero, or X plus four, or X, let me do that orange. Actually, let me do the two X minus one in that yellow color. So either two X minus
one is equal to zero, or X plus four is equal to zero. X plus four is equal to zero, and so let's solve each of these. If two X minus one could be equal to zero, well, let's see, you could
add one to both sides, and we get two X is equal to one. Divide both sides by two, and this just straightforward solving a linear equation. If this looks unfamiliar, I encourage you to watch videos on solving linear
equations on Khan Academy, but you'll get X is equal
to 1/2 as one solution. This is interesting 'cause we're gonna have
two solutions here, or over here, if we wanna solve for X, we can subtract four from both sides, and we would get X is
equal to negative four. So it's neat. In an equation like this, you can actually have two solutions. X could be equal to 1/2, or X could be equal to negative four. I think it's pretty interesting to substitute either one of these in. If X is equal to 1/2, what is going to happen? Well, this is going to be
two times 1/2 minus one, two times 1/2 minus one. That's going to be our first expression, and then our second expression
is going to be 1/2 plus four. And so what's this going to be equal to? Well, two times 1/2 is one. One minus one is zero, so I don't care what you have over here. Zero times anything is
going to be equal to zero. So when X equals 1/2, the first thing becomes zero, making everything, making
the product equal zero. And likewise, if X equals negative four, it's pretty clear that
this second expression is going to be zero, and even though this first expression isn't going to be zero in that case, anything times zero is going to be zero. Let's do one more example here. So let me delete out everything
that I just wrote here, and so I'm gonna involve a function. So let's say someone told you that F of X is equal to X minus five, times five X, plus two, and someone said, "Find
the zeros of F of X." Well, the zeros are, what are the X values that make F of X equal to zero? When does F of X equal zero? For what X values does F of X equal zero? That's what people are really asking when they say, "Find the zeros of F of X." So to do that, well, when
does F of X equal zero? Well, F of X is equal to zero when this expression right over here is equal to zero, and so it sets up just like
the equation we just saw. X minus five times five X plus two, when does that equal zero? And like we saw before, well, this is just like
what we saw before, and I encourage you to pause the video, and try to work it out on your own. So there's two situations where this could happen, where either the first
expression equals zero, or the second expression, or maybe in some cases, you'll have a situation where
both expressions equal zero. So we could say either X
minus five is equal to zero, or five X plus two is equal to zero. I'll write an, or, right over here. Now if we solve for X, you add five to both
sides of this equation. You get X is equal to five. Here, let's see. To solve for X, you could subtract two from both sides. You get five X is equal to negative two, and you could divide both sides by five to solve for X, and you get X is equal to negative 2/5. So here are two zeros. You input either one of these into F of X. If you input X equals five, if you take F of five, if you try to evaluate F of five, then this first
expression's gonna be zero, and so a product of
zero and something else, it doesn't matter that
this is gonna be 27. Zero times 27 is zero, and if you take F of negative 2/5, it doesn't matter what
this first expression is. The second expression right over here is gonna be zero. Zero times anything is zero.