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Algebra 1
Course: Algebra 1 > Unit 14
Lesson 3: Solving by taking the square root- Solving quadratics by taking square roots
- Solving quadratics by taking square roots
- Quadratics by taking square roots (intro)
- Solving quadratics by taking square roots examples
- Quadratics by taking square roots
- Quadratics by taking square roots: strategy
- Quadratics by taking square roots: strategy
- Solving quadratics by taking square roots: with steps
- Quadratics by taking square roots: with steps
- Solving simple quadratics review
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Solving quadratics by taking square roots
Learn how to solve quadratic equations like x^2=36 or (x-2)^2=49.
What you should be familiar with before taking this lesson
What you will learn in this lesson
So far you have solved linear equations, which include constant terms—plain numbers—and terms with the variable raised to the first power, x, start superscript, 1, end superscript, equals, x.
You will now learn how to solve quadratic equations, which include terms where the variable is raised to the second power, x, squared.
Here are a few examples of the types of quadratic equations you will learn to solve:
left parenthesis, x, minus, 2, right parenthesis, squared, equals, 49
Now let's get down to business.
Solving x, squared, equals, 36 and similar equations
Suppose we want to solve the equation x, squared, equals, 36. Let's first verbalize what the equation is asking us to find. It is asking us which number, when multiplied by itself, equals 36.
If this question sounds familiar to you, it's because this is the definition of the square root of 36, which is expressed mathematically as square root of, 36, end square root.
Now, this is how the complete solution of the equation looks:
Let's review what went on in this solution.
What the plus minus sign means
Note that every positive number has two square roots: a positive square root and a negative square root. For example, both 6 and minus, 6, when squared, equal 36. Therefore, this equation has two solutions.
The plus minus is just an efficient way of representing this concept mathematically. For example, plus minus, 6 means "either 6 or minus, 6".
A note about inverse operations
When we solved linear equations, we isolated the variable by using inverse operations: If the variable had 3 added to it, we subtracted 3 from both sides. If the variable was multiplied by 4, we divided both sides by 4.
The inverse operation of taking the square is taking the square root. However, unlike the other operations, when we take the square root we must remember to take both the positive and the negative square roots.
Now solve a few similar equations on your own.
Solving left parenthesis, x, minus, 2, right parenthesis, squared, equals, 49 and similar equations
Here is how the solution of the equation left parenthesis, x, minus, 2, right parenthesis, squared, equals, 49 goes:
Therefore, the solutions are x, equals, 9 and x, equals, minus, 5.
Let's review what went on in this solution.
Isolating x
Using the inverse operation of taking the square root, we removed the square sign. This was important in order to isolate x, but we still had to add 2 in the last step in order to really isolate x.
Understanding the solutions
Our work ended with x, equals, plus minus, 7, plus, 2. How should we understand that expression? Remember that plus minus, 7 means "either plus, 7 or minus, 7." Therefore, we should split our answer according to the two cases: either x, equals, 7, plus, 2 or x, equals, minus, 7, plus, 2.
This gives us the two solutions x, equals, 9 and x, equals, minus, 5.
Now solve a few similar equations on your own.
Why we shouldn't expand the parentheses
Let's go back to our example equation, left parenthesis, x, minus, 2, right parenthesis, squared, equals, 49. Suppose we wanted to expand the parentheses there. After all, this is what we do in linear equations, right?
Expanding the parentheses results in the following equation:
If we wanted to take the square root in this equation, we would have to take the square root of the expression x, squared, minus, 4, x, plus, 4, but it's not clear if square root of, x, squared, minus, 4, x, plus, 4, end square root can be rewritten as a nice expression.
In contrast, taking the square roots of expressions like x, squared or left parenthesis, x, minus, 2, right parenthesis, squared gives us nice expressions like x or left parenthesis, x, minus, 2, right parenthesis.
Therefore, it's actually helpful in quadratic equations to keep things factored, because this allows us to take the square root.
Solving 2, x, squared, plus, 3, equals, 131 and similar equations
Not all quadratic equations are solved by immediately taking the square root. Sometimes we have to isolate the squared term before taking its root.
For example, to solve the equation 2, x, squared, plus, 3, equals, 131 we should first isolate x, squared. We do this exactly as we would isolate the x term in a linear equation.
Now solve a few similar equations on your own.
Want to join the conversation?
- what do you do if you have a hard time remembering big formulas?(25 votes)
- Create random codes that will be easier to remember. For example "Q = I x t" is formula for charge used in a circuit for a given time. I call it "Quit" where Qu is Charge, i is Current and t is time.
Build your own logic that makes no sense. Australia has more letters than Europa, so it cannot fit in Europa. Australia is not located in Europa.(57 votes)
- when looking at the quadratic equation with the (x-#)^2
what if the ^2 was next to the (x) in the equation?(15 votes) - Wouldn't expanding the parenthesis make it easier? For example: (x-2)^2 = 81 be x^2- 2^2=81, thus making it easier to solve?(17 votes)
- No!
(x-2)² = (x-2)(x-2) = x²-2x-2x+4 = x²-4x-4
That means, now you gotta solve forx²-4x+4 = 81
.x²-4x+4 = 81
(splitting the middle term)
x²-4x+4-81 = 81-81
x²-4x-77 = 0
x²-11x+7x-77 = 0x(x-11)+7(x-11) = 0
(x+7)(x-11) = 0
(factoring out (x-11))
Using the zero product property,x = -7 or x = 11
This way, as you can see, is much, much longer than the square root method. Why bother going the long way, when you can have the solution in just a few seconds?
Hope this helps! :)(22 votes)
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I realize
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When our guard is down
I think we'll both agree
That violence breeds violence
But in the end it has to be this way
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But nobody is to blame
Yet staring across this barren wasted land
I feel new life will be born
Beneath the blood stained sand
Beneath the blood stained sand(17 votes)- Rules of nature!(4 votes)
- "Note that every positive number has two square roots: a positive square root and a negative square root. For example, both 6 and -6 when squared, equal 36. Therefore, this equation has two solutions."
In my calculator I tried squaring -6 but I got -36?(9 votes)- I know you posted this a while ago and may not see this but:
Your calculator (like mine) interprets "-6", as "-1 * 6".
Meaning it interprets "-6^2" as "-1 * 6^2", and since calculators obey the order of operations, it squares the 6 first, then multiplies that by -1.
If you want to square a negative number, then type "(-6)^2", which the calculator interprets as "(-1 * 6)^2", meaning it preforms the multiplication before squaring the number.
I hope that helped.(16 votes)
- i wish people were on these when i am i feel like im always a little behind, if anyone is out there, i would like to talk. yours truly, baconator(14 votes)
- for the very last challenge question:
how does the equation go from x^2 + 8x + 16 --> (x + 4) ^2 ?
is it because 4*4 = 16 and 4+4=8 thus, (x+4)^2 ?(9 votes)- Yes. If you factor x^2 + 8x + 16 it becomes (x + 4)(x + 4), which is the same as (x + 4) ^2(13 votes)
- Do you always work on the left side of the equal sign first in problems like the challenge question?(8 votes)
- You don't need to... but it kind of goes over there later.(5 votes)
- bees bees bees(12 votes)
- Help. I hate math. The last time someone has ever ask a question was 7 years ago. I don't understand the bottem part of this page. its 2023(10 votes)
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