Main content

## Algebra 1

### Course: Algebra 1 > Unit 9

Lesson 2: Constructing arithmetic sequences- Recursive formulas for arithmetic sequences
- Recursive formulas for arithmetic sequences
- Recursive formulas for arithmetic sequences
- Explicit formulas for arithmetic sequences
- Explicit formulas for arithmetic sequences
- Explicit formulas for arithmetic sequences
- Arithmetic sequence problem
- Converting recursive & explicit forms of arithmetic sequences
- Converting recursive & explicit forms of arithmetic sequences
- Converting recursive & explicit forms of arithmetic sequences
- Arithmetic sequences review

© 2023 Khan AcademyTerms of usePrivacy PolicyCookie Notice

# Arithmetic sequences review

Review arithmetic sequences and solve various problems involving them.

## Parts and formulas of arithmetic sequences

In arithmetic sequences, the difference between consecutive terms is always the same. We call that difference

**the common difference**.For example, the common difference of the following sequence is plus, 2:

start color #ed5fa6, plus, 2, \curvearrowright, end color #ed5fa6 | start color #ed5fa6, plus, 2, \curvearrowright, end color #ed5fa6 | start color #ed5fa6, plus, 2, \curvearrowright, end color #ed5fa6 | |||||
---|---|---|---|---|---|---|---|

3, comma | 5, comma | 7, comma | 9, comma, point, point, point |

Arithmetic sequence formulas give a, left parenthesis, n, right parenthesis, the n, start superscript, start text, t, h, end text, end superscript term of the sequence.

This is the

**explicit**formula for the arithmetic sequence whose first term is start color #11accd, k, end color #11accd and common difference is start color #ed5fa6, d, end color #ed5fa6:This is the

**recursive**formula of that sequence:*Want to learn more about arithmetic sequences? Check out this video.*

## Extending arithmetic sequences

Suppose we want to extend the sequence 3, comma, 8, comma, 13, comma, point, point, point We can see each term is start color #ed5fa6, plus, 5, end color #ed5fa6 from the previous term:

start color #ed5fa6, plus, 5, \curvearrowright, end color #ed5fa6 | start color #ed5fa6, plus, 5, \curvearrowright, end color #ed5fa6 | start color #ed5fa6, plus, 5, \curvearrowright, end color #ed5fa6 | |||||
---|---|---|---|---|---|---|---|

3, comma | 8, comma | 13, comma, point, point, point |

So we simply add that difference to find that the next term is 18:

start color #ed5fa6, plus, 5, \curvearrowright, end color #ed5fa6 | start color #ed5fa6, plus, 5, \curvearrowright, end color #ed5fa6 | start color #ed5fa6, plus, 5, \curvearrowright, end color #ed5fa6 | |||||
---|---|---|---|---|---|---|---|

3, comma | 8, comma | 13, comma | 18, comma, point, point, point |

*Want to try more problems like this? Check out this exercise.*

## Writing recursive formulas

Suppose we want to write a recursive formula for 3, comma, 8, comma, 13, comma, point, point, point We already know the common difference is start color #ed5fa6, plus, 5, end color #ed5fa6. We can also see that the first term is start color #11accd, 3, end color #11accd. Therefore, this is a recursive formula for the sequence:

*Want to try more problems like this? Check out this exercise.*

## Writing explicit formulas

Suppose we want to write an explicit formula for 3, comma, 8, comma, 13, comma, point, point, point We already know the common difference is start color #ed5fa6, plus, 5, end color #ed5fa6 and the first term is start color #11accd, 3, end color #11accd. Therefore, this is an explicit formula for the sequence:

*Want to try more problems like this? Check out this exercise.*

## Want to join the conversation?

- How do you write an explicit formula for the sequence (8,11,16,23,32)(8 votes)
- Notice that the sequence of differences is simply the sequence of odd numbers. So this is the sequence of squares shifted by a constant. Since 8-1=7, we have

a(n) = n^2 +7(7 votes)

- Why was the Arithmetic Sequence review so hard on my mind? It took me to look at the explanation to understand the answers to every darn question. And, I am yet so confused on this section.(8 votes)
- you can check ncert (cbse)textbook math grade 10 and find the chapter Arithmetic progression.That might help.(1 vote)

- When given an arithmetic sequence with a negative term, how do you calculate what term the number will be when it reaches 0?(3 votes)
- Some sequences do not even have 0 as one of the possibilities. So if you start with a negative and have a negative common difference, then there is no zero such as -2, -4, -6, -8, ... Others will have a common difference that skips over zero such as -4, 4, 12, 20, 28, ... If the sequence does include a zero, such as an initial value of - 9 and a common difference of 3, we get an equation f(n) = -9 + 3(n-1). set this equal to zero, 0 = -9 + 3(n-1) move the - 9 by adding and distribute to get 9 = 3n - 3, add 3 to both sides, 3n = 12., divide by 3 to get n = 4. Sequence would be -9, -6, -3, 0 ... which is what we were looking for. So if your equation skipped 0 as above f(n) = -4 +8(n-1) and did the same thing, then 0 = -4 + 8n - 8, add 12 to get 12 = 8n, n = 12/8 = 3/2, but a sequence does not have a 3/2 term, only 1, 2, 3 ... terms.(4 votes)

- How would you find the explicit formula for a problem such as:

"a" subscript 38 =-53.2, while the common difference is -1.1?(2 votes)- You need to know a common difference and one 'value' (sequence) in order to find the general form (formula). Since the common difference is -1.1, it would look like this: -1.1(n-1) + b (if you are starting from n=1).

Then plug in "a" subscript 38 = -53.2 into the formula. Then it would be -1.1(38-1) + b = -53.2

All you have to do is solving for 'b' and it would be -12.5.

Therefore, the general form (formula) would be -1.1(n-1) - 12.5 if you are starting from n=1.(5 votes)

- how are the formulas for arithmetic sequences similar to functions?(2 votes)
- Arithmetic sequences are functions. The difference between a linear function and a arithmetic sequence is that the first is continuous and the second is discrete, but the continuous line would go through all the points of its equivalent sequence.(4 votes)

- how do you write a recursive formula for 1, 1, 0, -1, -1, 0, 1, 1(3 votes)
- Consider the arithmetic sequence 27, 13, -1, ...

The explicit rule for the sequence in terms of n is a(n)= 27-14(n-1). If the nth term is -841, find the value of n.(2 votes)- If the nth term is -841, then you were just given the result. Basically a(n)=-841

So, change the equation into -841=27-14(n-1).

You can now solve for n.

Hope this helps.(1 vote)

- How would you write a explicit formula when f(0)=5, f(x)=f(x-1)+(2x-1)?(2 votes)
- Hi, sup bruuuuhh(2 votes)
- which formula is more suitable to use recursive or explicit?(1 vote)
- Most of the time, explicit has more power, but for a few occasions such as the Fibonacci sequence, the recursive is more applicable. The explicit equation is closer to the slope intercept form of the line that would go through all the poins of a particular arithmetic sequence.(2 votes)