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Sal solves a word problem about the weights of TVs and DVDs by creating a system of equations and solving it. Created by Sal Khan and Monterey Institute for Technology and Education.
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- Does It matter what numer you multiply the equation to? You multiplied the second equation by -1. what if it was -2 or 3 how do you determine what to multiply by?(14 votes)
- A more in depth look at the question. Could you have multiplied the 2nd equation by -2, or -3, and what would happen? Well, the answer is yes, you could multipy by either. As long as you multiply both sides, you are within the boundries of algebra. However, you would have to then take a second step. Lets look at -2.
1st Equation: 3t + 5d = 62.5
2nd Equation: 3t + 2d = 52, -2(3t + 2d) = -2 (52), -6t - 4d = -104
We are still left with coefficient sets that don't cancel out when added. This simply means we need further manipulation. You could multply the second equation again, by 1/2 which would be equivilent to having simply multiplied it by -1 in the first place (-2*1/2 = -1). OR... we can manipulate the 1st equation by multiplying it by 2 to elimate t, OR... by 4/5 to eliminate d.
So what happens? You end up with a more rigorous problem, more steps, and a higher risk of making simple calculation mistakes.(35 votes)
- 2:51Why do you have to multiply the equation by -1? Can't you just subtract the 2nd from the first equation? It's much easier that way than multiplying the 2nd equation by -1 and adding it to the first equation.
Subtracting is the same thing as adding something negative.(7 votes)
- Yes that is completely true. You can definitely do that. But you see, the reason most people don't do this however is because it's very easy to forget which parts of the term should be negative or not; it's very easy to forget if a + or - sign should be assigned(it really depends on the person and how they do it). That's why people multiply by *-1* and then add, but you can definitely resort to just subtracting.(10 votes)
- sal says that 3t+2d is the same thing as 52, so, with that being said, can you divide 3t=52 and that giving you the answer for "t" and 52=2d giving you the answer for "d"?(3 votes)
- anyone please do tell me the logic behind adding two equations to derive the unknown variables. is the logic similar to x + 1 =2 => x = 2 - 1 therefore, x=1 ?(3 votes)
- This is called collecting like terms and then isolating the variable x.
In your example we subtract both sides by 1 to isolate x on the other side alone.(4 votes)
- how would you solve the equation via substitution?
- What you can do is x=5/2 because you want the x by itself then sub into equation #2 like this
Since we know x=5/2 we can do 5/2+y=7. no subtract 5/2 from both sides which will be:y=7-5/2=4.5
you can also check:
- When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ? ineed answer and explanation plezzzzzz...(1 vote)
- All you have to do is plug in the giving x and y values into both equations and solve.
I assume the 2 is an exponent on 3x2.
3(3)^2-2(5) = 17
2(3)^2-3(5) = 3
So it exceeds the value by 14.(5 votes)
- how do I solve 3x+2y=-17
- To solve a system of equations by elimination, you have to manipulate one or both of the equations so that when you add them together, one of the variables drops out.
3x + 2y = -17
1x - 3y = 9
If you were to multiply both sides of the second equation by -3, you would get:
3x + 2y = -17
-3x + 9y = -27
When you add the two equations together, you get:
0x + 11y = -44
11y = -44
Divide both sides by 11 and you get:
y = -44/11 = -4
Now, substitute the value for y into either equation and solve for x:
x -3(-4) = 9
x -(-12) = 9
x + 12 = 9
x = 9 - 12 = -3
Check your answer...
3(-3) + 2(-4) = -17
-9 + -8 = -17
-17 = -17
-3 - 3(-4) = 9
-3 + 12 = 9
9 = 9
Therefore: x=-3, and y=-4 is the solution to the system of equations.(3 votes)
- I am having trouble with this one : Given a word problem, how do you set it up in algebraic form and then solve it ?
Ten (10) years back, Jack’s father was four (4) times Jack’s age. But ten years from now, the father will be only 2 times Jack’s age. What are their current ages?(1 vote)
- Always start with defining current ages, j for Jack and d for dad. So subtracting 10 gives f-10 = 4(j-10). Adding 10 years gives f+10 = 2(j+10). I assume you are okay with solving from here.(3 votes)
An electronics warehouse ships televisions and DVD players in certain combinations to retailers throughout the country. They tell us that the weight of 3 televisions and 5 DVD players is 62.5 pounds, and the weight of 3 televisions and 2 DVD players-- so they're giving us different combinations-- is 52 pounds. Create a system of equations that represents this situation. Then solve it to find out how much each television and DVD player weighs. Well, the two pieces of information they gave us in each of these statements can be converted into an equation. The first one is is that the weight of 3 televisions and 5 DVD players is 62.5 pounds. Then they told us that the weight of 3 televisions and 2 DVD players is 52 pounds. So we can translate these directly into equations. If we let t to be the weight of a television, and d to be the weight of a DVD player, this first statement up here says that 3 times the weight of a television, or 3 televisions, plus 5 times the weight of a DVD player, is going to be equal to 62.5 pounds. That's exactly what this first statement is telling us. The second statement, the weight of 3 televisions and 2 DVD players, so if I have 3 televisions and 2 DVD players, so the weight of 3 televisions plus the weight of 2 DVD players, they're telling us that that is 52 pounds. And so now we've set up the system of equations. We've done the first part, to create a system that represents the situation. Now we need to solve it. Now, one thing that's especially tempting when you have two systems, and both of them have something where, you know, you have a 3t here and you have a 3t here, what we can do is we can multiply one of the systems by some factor, so that if we were to add this equation to that equation, we would get one of the terms to cancel out. And that's what we're going to do right here. And you can do this, you can do this business of adding equations to each other, because remember, when we learned this at the beginning of algebra, anything you do to one side of an equation, if I add 5 to one side of an equation, I have to add 5 to another side of the equation. So if I add this business to this side of the equation, if I add this blue stuff to the left side of the equation, I can add this 52 to the right-hand side, because this is saying that 52 is the same thing as this thing over here. This thing is also 52. So if we're adding this to the left-hand side, we're actually adding 52 to it. We're just writing it a different way. Now, before we do that, what I want to do is multiply the second, blue equation by negative 1. And I want to multiply it by negative 1. So negative 3t plus-- I could write negative 2d is equal to negative 52. So I haven't changed the information in this equation. I just multiplied everything by negative 1. The reason why I did that is because now if I add these two equations, these 3t terms are going to cancel out. So let's do that. Let's add these two equations. And remember, all we're doing is we're adding the same thing to both sides of this top equation. We're adding essentially negative 52 now, now that we've multiplied everything by a negative 1. This negative 3t plus negative 2d is the same thing as negative 52. So let's add this left-hand side over here. The 3t and the negative 3t will cancel out. That was the whole point. 5d plus negative 2d is 3d. So you have a 3d is equal to 62.5 plus negative 52, or 62.5 minus 52 is 10.5. And now we can divide both sides of this equation by 3. And you get d is equal to 10.5 divided by 3. So let's figure out what that is. 3 goes into 10.5-- it goes into 10 three times. 3 times 3 is 9. Subtract. Get 1. Bring down the 5. Of course, you have your decimal point right here. 3 goes into 15 five times. 5 times 3 is 15. You've got to subtract, and you get a 0. So it goes exactly 3.5 times. So the weight of a DVD player-- that's what d represents-- is 3.5 pounds. Now we can substitute back into one of these equations up here to figure out the weight of a television. We can just use that top equation. So you get 3t plus 5 times the weight of a DVD player, which we just figured out is 3.5. Remember, we're just looking for values that satisfy both of these equations. So 5 times 3.5-- needs to be equal to 62.5. So you get 3t plus-- what is this going to be? This is going to be 15 plus 2.5, right? 5 times 0.5 is 2.5, 5 times 3 is 15. So it's 17.5, is equal to 62.5. Now we can subtract 17.5 from both sides of this equation. And what do we get? The left-hand side is just going to be 3t. This cancels out, that was the whole point of it. 3t is going to be equal to-- let's see. The 0.5 minus 0.5, that cancels out. So this is the same thing as 62 minus 17. 62 minus 7 would be 55. And so we're going to subtract another 10. So it's going to be 45. So this is going to be equal to 45. Now you can divide both sides of this equation by 3. And we get t is equal to 15. So we've solved our system. The weight of a DVD player is 3.5 pounds, and the weight of a television is 15 pounds. And we're done.