Main content

## Algebra 2

### Course: Algebra 2 > Unit 3

Lesson 6: Polynomial identities# Polynomial identities introduction

CCSS.Math: ,

Polynomial identities are equations that are true for all possible values of the variable. For example, x²+2x+1=(x+1)² is an identity. This introduction video gives more examples of identities and discusses how we prove an equation is an identity.

## Want to join the conversation?

- I am a bit confused here. I came up with two after working my way through the second example. If I entered two as (n) it would make the polynomial even on both sides. Wouldn't that make the second example an identity?(0 votes)
- A polynomial identity is when it is equal for ALL values of n(17 votes)

- is it just me or do a lot of people just come walkin up to sal and say 'hey you factor this?'(4 votes)
- Tell me if my definition of a mathematical identity is correct: an equality between two expressions in which they are not the same but, upon manipulating one or the other or both, they can be the same.(2 votes)
- You have to be careful about using phrases like "the same" in math. You need to be very precise in math for good reasons. If two expressions are equal, that means they are always "the same." They might look different, but an identity can be expressed as an equation which is always true. For example 5 + 1 = 4 + 2.(5 votes)

- Is there a real-world purpose to this concept? I tend to retain this type of information better if I know how it is used in the world.(1 vote)
- One example I can think of is that polynomial identities are used to find variable(s) to find where to support a curve in a bridge or building for an engineer. Statistics in graphs could also use polynomials in general to find trends in stocks or other economic related topics.(5 votes)

- @3:10, Sal subtracts 2n on both sides and continues to solve it, but I expanded (n+3)^2 to a quadratic form and solved for n, which equals 4... Then substituted 4 into the equation and solved for finding the identity... This also concludes that its not a polynomial identity... This method is correct right??(2 votes)
- It does not matter if you subtract or not, either way the ns will cancel out on both sides.(3 votes)

- 3:40Where'd the 6n come from?? Wouldn't it just be n^2 + 9?(0 votes)
- (𝑛 + 3)² = (𝑛 + 3)(𝑛 + 3)

Using the distributive property twice, aka "FOIL",

we get 𝑛² + 3𝑛 + 3𝑛 + 9, which simplifies to 𝑛² + 6𝑛 + 9(3 votes)

- And, two polynomial expressions having infinite solutions is a polynomial identity?(1 vote)
- So, it's just a fancier name of equivalent expressions in polynomials just as the circumference of the perimeter in a circle?(1 vote)
- how do you solve something like this (1/x)-(1/3)=-1/3x(1 vote)
- Get rid of fractions by multiplying by 3x, this gives 3 - x = -x^2, add x^2 to both sides, x^2 - x + 3= 0 . Then looking at b^2-4ac = (-1)^2 -4(1)(3) = - 11, thus there are no real solutions.(1 vote)

- Can someone explain what happened in question 3, because I don't really get it?(1 vote)
- Not sure what you do not get. In the first two examples. the right side and the left side were the same, just different forms, so they are polynomial identities (if you moved everything to one side, you would end up with 0=0). The third example is not a polynomial identity becuase when you simplified it, the two sides are not the same, so it is not a polynomial identity (only one value works, not all real numbers).(1 vote)

## Video transcript

- [Instructor] What we're
going to do in this video is talk a little bit about
polynomial identities, and this is really just a fancy way of seeing whether an expression that involves a polynomial is
equal to another expression. So for example, you're familiar with x squared plus two x plus one, we've seen polynomials
like this multiple times, this is a quadratic,
and you might recognize that this would be equal
to x plus one squared, that for any value of x, x squared plus two x plus one is the same thing as adding one to that x, and then squaring the whole thing. And we saw this when we first got, when we first learned
how to multiply binomials and we took the square of binomials, but now we're going to do this with slightly complicated expressions, things that aren't just simple quadratics or that might not be as obvious as this. And the way that we're gonna
prove whether they are true or not is just with a little
bit of algebraic manipulation. So for example, if someone
walked up to you on the street and said, all right, m
to the third minus one, is it equal to m minus one
times one plus m plus m squared? Pause this video and see what
you would tell that person, whether you could prove whether it is or is not a true polynomial identity. Okay, let's do it together, and the way I would tackle
this is I would expand out, I would multiply out what we
have on the right-hand side, so this is going to be equal to, so first, I could take this m and then multiply it times every term in this second expression, so m times one is m, m
times m is m squared, and then m times m squared
is m to the third power, and then I would take this negative one, and then multiply and then
distribute that times every term in that other expression, so negative one times one is negative one, negative one times m is negative m, and negative one times m
squared is negative m squared, and now let's see if we can simplify this. We have an m and a negative m, so those are going to cancel out, we have an m squared and
a negative m squared, so those cancel out, and so we are going to be left with m to
the third power, minus one. Now, clearly, m to the
third power minus one is going to be equal to m to the third power minus one for any value of m, these are identical expressions. So this is, this is indeed
a polynomial identity. Let's do another example. Let's say someone were to
walk up to you on the street and said, quick, n plus
three squared plus two n, is that equal to eight n plus 13, is this a polynomial identity? Pause this video and see
if you can figure that out. All right, now we're gonna
work on that together. And I would do it the exact same way. I would try to simplify with
a little bit of algebra, maybe the easiest thing to do first, and you could do this in multiple ways is, I have this, I have these n terms, two n's here, eight n's over here, well, what if I were to
get these two n's out of the left-hand side, so if I were to just subtract two n from
both sides of this equation, I'm going to get on the left-hand side, n plus three squared, and
on the right-hand side, I'm going to get six n,
eight n minus two n, plus 13. Now, what's n plus three squared? Well, that's going to be n squared plus two times three times n. And if what I just did does
not seem familiar to you, I encourage you to look at the videos about squaring binomials, but this is going to be plus six n, plus three squared, which is nine, and is this going to be
equal to six n plus 13? Well, already this is
starting to look a little bit, a little bit sketchy, but let's just keep going with the algebra. So let's see if we subtract six n from both sides, what do you get? Well, on the left-hand side, you're just going to
have n squared plus nine, and on the right-hand side,
you're going to get 13. Now, are there values of n for which this is not always true? Well, sure. I can find a lot of values of n for which this is not always true. If n is a zero, this is
not going to be true. If n is one, this is not going to be true. If n is two, this actually would be true, but if n is three, this
is not going to be true. If n is four, five, et cetera, so for actually most values of n, this is not going to be true. So in order for it to be
a polynomial identity, it has to be true for all of the values that are legitimate values that
you can evaluate for those, for the variable in question. So this one right over
here is not a polynomial, polynomial identity, and we are done.