Main content

## AP®︎/College Calculus AB

### Course: AP®︎/College Calculus AB > Unit 5

Lesson 4: Using the first derivative test to find relative (local) extrema- Introduction to minimum and maximum points
- Finding relative extrema (first derivative test)
- Worked example: finding relative extrema
- Analyzing mistakes when finding extrema (example 1)
- Analyzing mistakes when finding extrema (example 2)
- Finding relative extrema (first derivative test)
- Relative minima & maxima
- Relative minima & maxima review

© 2023 Khan AcademyTerms of usePrivacy PolicyCookie Notice

# Finding relative extrema (first derivative test)

AP.CALC:

FUN‑4 (EU)

, FUN‑4.A (LO)

, FUN‑4.A.2 (EK)

Once you find a critical point, how can you tell if it is a minimum, maximum or neither? Created by Sal Khan.

## Want to join the conversation?

- what does local extrema mean?(14 votes)
- Look at the graph of this function. The graph dips down right at the y-axis, which is an important detail, but it isn't really the minimum value of the function since it goes to negative infinity eventually. Therefore, we call that value of the function a local minimum, since it is the smallest value near x=0.

http://www.khanacademy.org/cs/local-extrema-example/1366493103(69 votes)

- Is it possible to have two local maximums?(10 votes)
- You could have infinitely many, just look at a sine curve for example.(30 votes)

- Are all critical points maximums/minimums and vice versa? Is this the definition of a critical point (max/min)? Thank you.(6 votes)
- All maximums and minimums are critical points, but it does NOT work the other way around. You can have a critical point that is not a maximum or minimum. In this video the point at x sub 3 is a critical point, but it is NOT a maximum nor minimum. This point is called an inflection point, and future videos explain inflection points.(14 votes)

- Could there be more than 1 local maximums or local minimums per function? How about more than 1 global maximums and global minimums?(3 votes)
- You can only have one value for the absolute max or min, (like f(x)=1) but I think that value can appear more than once, as it does in the sine function. In f(x)=sin(x), I think 1 counts as the absolute max even though it occurs at pi/2, 5pi/2, 9pi/2, etc.

(I think global and absolute maximums are the same thing, but absolute is what I studied.)(7 votes)

- How can we calculate whether the critical number is either maxima or minima without graph?(4 votes)
- Use the second derivative or check f'(x) on either side of the critical number.(4 votes)

- What is an inflection point? Is it a critical point?(3 votes)
- An inflection point is a point on a curve where the curve changes from concave up to concave down or the concave down to concave up. A critical point is where possible maxima values and minima values are.(5 votes)

- This whole video seems useless to me because to see if the surrounding derivative is positive or negative you have to look at the graph, but then you might as well see if its the greatest (or least) point in the area?(3 votes)
- You cannot always tell from the graph. You might get a rough approximation of where the max or min is, but you need the derivative to check the exact value. Also, if you have max and min quite close to each other the graph can look like it has fewer max and min than it really has -- so you need the derivative to be sure. For example, could you tell just by looking at this graph how many maxima and minima there are: http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427emr9u8s45l4

Answer: There are 8.(4 votes)

- In order for a point to be maximum or minimum, must the derivatives approaching from both sides be symmetrical? I mean, does the derivative of points leading up to the critical point from the left have to correspond with its additive inverse on the right?(4 votes)
- No, the derivatives approaching from either side of the maximum or minimum do not have to be symmetrical. Try graphing the function y = x^3 + 2x^2 + .2x. You have a local maximum and minimum in the interval x = -1 to x = about .25. By looking at the graph you can see that the change in slope to the left of the maximum is steeper than to the right of the maximum. And the change in slope to the left of the minimum is less steep than that to the right of the minimum.(2 votes)

- what is the trick in identifying a local minimum or maximum by looking at the graph?(3 votes)
- If the graph is descending and then starts ascending, you're at a local minimum where the transition occurs.

With that information, you can probably figure out how to spot a local maximum.(3 votes)

- Quick question, are the endpoints of a closed interval critical points?(2 votes)
- Only if their derivative is 0. When checkign for global extrema you still have to check the end points though just in case their underived value is greater or less than the critical points.(2 votes)

## Video transcript

In the last video we saw
that if a function takes on a minimum or maximum value,
min max value for our function at x equals a, then a
is a critical point. But then we saw that
the other way around isn't necessarily true. x equal
a being a critical point does not necessarily mean
that the function takes on a minimum or maximum
value at that point. So what we're going to
try to do this video is try to come up
with some criteria, especially involving the
derivative of the function around x equals a,
to figure out if it is a minimum or a maximum point. So let's look at what we
saw in the last video. We saw that this
point right over here is where the function
takes on a maximum value. So this critical point in
particular was x naught. What made it a critical point
was that the derivative is 0. You have a critical point where
either the derivative is 0 or the derivative is undefined. So this is a critical point. And let's explore
what the derivative is doing as we approach that point. So in order for this
to be a maximum point, the function is increasing
as we approach it. The function is
increasing is another way of saying that the
slope is positive. The slope is changing
but it stays positive the whole time which means that
the function is increasing. And the slope being
positive is another way of saying that the
derivative is greater than 0 as we approach that point. Now what happens as
we pass that point? Right at that point
the slope is 0. But then as we past
that point, what has to happen in order for
that to be a maximum point? Well the value of the
function has to go down. If the value of the
function is going down, that means the
slope is negative. And that's so
another way of saying that the derivative is negative. So that seems like a
pretty good criteria for identifying whether
a critical point is a maximum point. So let's say that we
have critical point a. We are at a maximum
point if f prime of x switches signs from
positive to negative as we cross x equals a. That's exactly what
happened right over here. Let's make sure it happened at
our other maximum point right over here. So right over here, as
we approach that point the function is increasing. The function increasing means
that the slope is positive. It's a different positive slope. The slope is changing,
it's actually getting more, and
more, and more steep. Or more, and more,
and more positive. But is definitely positive. So it's positive
going into that point. And then it becomes negative
after we cross that point. The slope was undefined
right at the point. But it did switch signs
from positive to negative as we crossed that
critical point. So these both meet our criteria
for being a maximum point. So, so far our criteria
seems pretty good. Now let's make sure that somehow
this point right over here, which we identified in the
last video as a critical point, let's make-- and I think we
called this x0, this was x1, this was x2. So this is x3. Let's make sure that
this doesn't somehow meet the criteria
because we see visually that this is not
a maximum point. So as we approach this,
our slope is negative. And then as we cross it,
our slope is still negative, we're still decreasing. So we haven't switched signs. So this does not meet our
criteria, which is good. Now let's come up with the
criteria for a minimum point. And I think you could see
where this is likely to go. Well we identified in the last
video that this right over here is a minimum point. We can see that. It's a local minimum
just by looking at it. And what's the slope of
doing as we approach it? So the function is
decreasing, the slope is negative as we approach it. f prime of x is less than 0
as we approach that point. And then right
after we cross it-- this wouldn't be a minimum
point if the function were to keep decreasing somehow. The function needs
to increase now. So let me do that same green. So right after
that, the function starts increasing again. f prime of x is greater than 0. So this seems like pretty good
criteria for a minimum point. f prime of x switches signs
from negative to positive as we cross a. If we have some
critical point a, the function takes
on a minimum value at a if the derivative of
our function switches signs from negative to
positive as we cross a, from negative to positive. Now once again, this
point right over here, this critical point x sub 3
does not meet that criteria. We go from negative
to 0 right at that point then go to negative again. So this is not a minimum
or a maximum point.