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## Calculus, all content (2017 edition)

### Course: Calculus, all content (2017 edition) > Unit 2

Lesson 2: Derivative as slope of tangent line# Interpreting derivative challenge

Given that f(-2)=3 and f'(x)≤7, Sal finds the largest possible value of f(10). Created by Sal Khan.

## Want to join the conversation?

- I don't quite see how mean value theorem is related to this question...(22 votes)
- f(b)-f(a)/b-a = f ' (x), which is what was used to find out f(10) at the max f ' (x) of 7(22 votes)

- Is it correct if I solve it as following:

First, since the maximum slope of the function is 7, the largest number in the term of the function must increase with 7 to reach its max y. Thus, saying that the distance is |10 -(-2)| = 12, I could multiply 12 by, the scalar slope, 7;`12*7=84`

. Well, because f(-2) is not zero but 3, I must increase 84 with 3. So, f(10) maximum y value is 87.

Am I fine solving it as above?(25 votes)- Ye, I did the same too! But with a silly mistake i didn't see we start from -2 xD and i made it 7*10 +3 = 73 and then when i looked at your 12.. I got it :O it starts from -2 and not 0(1 vote)

- At1:38, Sal says that "the fastest growing function would be a line." Why couldn't some type of curve also be the fastest growing function? Would it be possible for such a curve to have 7 as the greatest instantaneous speed?(5 votes)
- The problem said that the f'(x) ≤ 7. Thus, the maximum slope is 7. Thus, the function that meets that requirement and increases at the maximum allowed rate would have to have a constant slope of 7 (the maximum slope allowed here). Only straight lines have a slope that is constant.(7 votes)

- According to this scenario, am I safe when assuming the maximum value of
`x`

which you have to find is always the latter endpoint?(3 votes)- No, that is not always the case. You must check f(x) (not the derivative) for the two endpoints, as well as the local extrema within the interval.(2 votes)

- What is the mean value theorem?(3 votes)
- The Mean Value Theorem or MVT is one of the important theorems in calculus.

Here is the video on it

https://www.khanacademy.org/math/calculus-home/derivative-applications-calc/mean-value-theorem-calc/v/mean-value-theorem-1(2 votes)

- (at about2:45) Why is it f(10) - 3 for y? I'm wondering what the logic is behind putting the f(10) there.(1 vote)
- We're trying to find the highest possible value of f(x) when x=10, as stated in the initial problem. Since we have a known point for the function and a bound on the derivative (slope), we can use the highest possible derivative to extrapolate from the known point f(-2)=3 to find the greatest possible value for f(10).(3 votes)

- at1:22what is the mean value theorem??(1 vote)
- Where did you get 84 from?(1 vote)
- In the video at03:58the formula for the slope is presented:

`( f(10)-3 ) / ( 10 - - 2 ) = 7`

.

This simplifies to:`( f(10)-3 ) / ( 12 ) = 7`

. Then multiply both sides of the equation with 12. This results in:`( f(10)-3 ) = 7 * 12 = 84`

.

So`f(10) = 84 + 3 = 87`

!(1 vote)

- Is there any kind of function that cannot be differentiated ?(1 vote)
- Any function that is not continuous cannot be differentiated. Also, if there are any sudden changes in slope (such as a corner), you can't differentiate over the entire interval. You can get around this problem a bit by taking derivatives of different sections of the function's domain.(1 vote)

- a competitive firm has the following production function y=f(x)=400x+60x2+6x3 where y=output,x=input.the firm faces an output and input prices of p=10 and an input prices of w=5440. 1-write a profit function of this firm in term of output and input prices and the input level. 2-what is the profit maximazing level of input for this firms?verify that the input level you choose is the profit maximizing points. 3-find the marginal product (MPx) of the variable input.

4-verify that P(MPx)=W at the profit maximizing input level.(1 vote)

## Video transcript

Let f be a differentiable
function for all x. If f of negative 2
is equal to 3 and f prime of x is less than or
equal to 7 for all x, then what is the largest
possible value of f of 10? And so I encourage you to
think about this on your own, pause the video,
try to figure out the largest possible
value for f of 10. And then we'll work
through it together. So I'm assuming you've
given a go at it. So let's visualize this. So let me draw some axes here. So let's say that's my x-axis. That's my x-axis
right over there. And this right over
here is my y-axis. That's my y-axis [INAUDIBLE]
I'll graph y equals f of x. And they tell us f of
negative 2 is equal to 3. And the two axes aren't
going to be drawn to scale. So let's say this is negative 2. And this right over here is
the point negative 2 comma 3. And they tell us that f prime of
x is a less than or equal to 7, that the instantaneous slope is
always less than or equal to 7. So really, the way to get the
largest possible value of f-- we don't have to necessarily
invoke the mean value theorem, although the mean value theorem
will help us know for sure-- is to say well, look, the
largest possible value of f of 10 is essentially if
we max this thing out. If we assume that the
instantaneous rate of change just stays at the
ceiling right at 7. So if we assumed
that our function, the fastest growing
function here would be a line that has a
slope exactly equal to 7. So the slope of 7 would
look-- and obviously, I'm not drawing this to scale. Visually, this looks
more like a slope of 1, but we'll just assume
this is a slope of 7 because it's not
at the same-- the x and y are not
at the same scale. So slope is equal to 7. And so if our slope
is equal to 7, where do we get to
when x is equal to 10? When x is equal to 10, which
is right over here, well what's our change in x? So what's our change in x? Let's just think
about it this way. Our change in y over change
in x is going to be what? Well our change in y is going
to be f of 10 minus f of 2. f of 2 is 3, so minus
3, over our change in x. Our change in x is
10 minus negative 2. 10 minus negative 2 is
going to be equal to 7. This is the way to max out what
our value of f of 10 might be. If at any point the slope
were anything less than that, because remember, the
instantaneous rate of change can never be more than that. So if we start off even
a little bit lower, than the best we can
do is get to that. Remember, we can't do
something like that. That would get us too steep. So it has to be like that. And then we would get
to a lower f of 10. Every time you have a
slightly lower rate of change, then it kind of limits
what happens to you. So remember, our slope
can never be more than 7. So this part should be parallel. So this should be parallel
to that right over there. This should be parallel. But we can never have a
higher slope than that. So the way to max it out is
to actually have a slope of 7. And so what is f
of 10 going to be? So let's see, 10 minus
negative 2, that is 12. Multiply both sides
by 12, you get 84. So f of 10 minus 3 is
going to be equal to 84. Or f of 10 is going
to be equal to 87. So if you have a slope of 7,
the whole way, you travel 12. That means you're going
to increase by 84. If you started at 3,
you increase by 84, you're going to get to 87.