Walk through deriving a general formula for the distance between two points.
between the points and is given by the following formula:
In this article, we're going to derive this formula!
Deriving the distance formula
Let's start by plotting the points
The length of the segment between the two points is the
We want to find the
. If we draw a right triangle, we'll be able to use the Pythagorean theorem!
An expression for the length of the base is
Similarly, an expression for the length of the height is
Now we can use the Pythagorean theorem to write an equation:
We can solve for
by taking the square root of each side:
That's it! We derived the distance formula!
Interestingly, a lot of people don't actually memorize this formula. Instead, they set up a right triangle, and use the Pythagorean theorem whenever they want to find the distance between two points.
Want to join the conversation?
- who came up with this formula?(35 votes)
- I still don't understand any of this... :I(12 votes)
- I haven't read any of the article on this so I really hope I don't say the exact same thing he says.... here goes:
Here is the graph I am referring to in my explanation: https://www.desmos.com/calculator/juthaysfbl
-- only look at the graph, ignore everything on the sides and bottom --
(intuitive solution, and how I learned this)
Think of the Pythagorean theorem. The formula is a^2 + b^2 = c^2 . Now, imagine two points, let's say they are (0,0) and (3,4) to keep it simple. Look at the blue line going from (0,0) to (3,0). This is the base, with a distance of 3 units. How did we find this? We took one of the x values (3) and subtracted it by the other (0). 3 - 0 = 0. Next, we must find the height. The red line represents it, and it is a length of 4 units. We found this, again, by subtracting the y values (4 - 0 = 0). We can now find the hypotenuse, if we replace a and b with the base height length, so we get 3^2 + 4^2 = c^2 (where c is the orange line, or hypotenuse). The hypotenuse is the distance of the two points.
Of course, we can square root both sides so we get c = sqrt( 3^2 + 4^2). We can expand this even further if we replace the 3 and 4 with how we got there, so c = sqrt( (3 - 0)^2 + (4 - 0)^2). But what do 3 and 0 and 4 and 0 mean? The two x values and y values, respectively. Therefore, we replace the numbers so we get c (hypotenuse) = ( ( x1 - x2) ^2 + (y1 - y2) ^2) .
I really hope this helped you, I spent a long time explaining this lmao...(58 votes)
- bro why do we have to do this(17 votes)
- I cannot say why you have to, but I can say why this might be useful in the future.
Lets say for whatever reason you needed to make a video game, and let’s also say you needed to calculate the distance between a player and an object in order to make an action occur. I imagine this would be useful for those purposes(16 votes)
- okay I understand all you have to do is take your y axis and divide it by your x axis(11 votes)
- If you were to get two perfect squares under the giant square root after subtracting the two points within each parentheses, would you be able to separate them in order to pull them out of the square root and make them rational?
For example, if I got "the square root of (6)^squared + (6)^squared" would I first square them and get "the square root of 36+36?" or could I separate them into "the square root of 36 + the square root of 36"(20 votes)
- how is the formula the same as the Pythagorean theorem(10 votes)
- The x and the y axis are perpendicular, so if you imagine a right triangle when you find a distance, and the hypotenuse is the distance(21 votes)
- Sooooo, if I have two points, (1, 2) and (-1, 4), it does not matter in which order I subtract as long as I do the x with the x, and so on? Because it doesn't look that way.(6 votes)
- I don't get it and I have a test tomorrow it's hard for sixth grade(10 votes)
- I most likely responded wayyyy to late for this, but I thoroughly recommend you go through both the article and video ( maybe the practices!) and study hard.(8 votes)
- what is the formula that is used to find distance between two points(0 votes)
- IS there a more simple way to do this?(7 votes)
- If it helps you, maybe think about the formula as d^2 = (delta x)^2 + (delta y)^2 ... It is just pythagorean theorem!(6 votes)