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## 6th grade

### Unit 6: Lesson 6

Expression value intuition# Expression value intuition

Explore how the values of algebraic expressions like 100-x, 5/x + 5, and (3y)/(2y) change as the values of the variables change.

## Want to join the conversation?

- so now the problem decreses? im confused(9 votes)
- If x increases, then 100-x decreases. For example, say that x=10. That means 100-x=90. If x=20, then 100-x=80. If x=30, then 100-x=70, and so on. If you have a constant first number in a subtraction problem, then the answer will get bigger as the second number gets smaller, and vise versa.(12 votes)

- For everyone who is confused:

If x increases, then 100-x decreases. For example, say that x=10. That means 100-x=90. If x=20, then 100-x=80. If x=30, then 100-x=70, and so on. If you have a constant first number in a subtraction problem, then the answer will get bigger as the second number gets smaller, and vise versa.(11 votes) - The last problem i am having a little bit of trouble understanding why the value would stay the same.(7 votes)
- You have the fraction 3y/2y and you’re trying to figure out what will happen if y increases, assuming that y is a number greater than 0. Since any non-zero number divided by itself is equal to 1, we know that no matter what the value of y is, y/y is equal to 1. And any number multiplied by 1 stays the same, so the value of 3y/2y isn’t going to change.(5 votes)

- would it be different answers if the numbers were negative?(3 votes)
- Yes... even one different sign will generally create a different result(4 votes)

- Can someone give me formula for this?

Thank you(1 vote)- The point of this lesson is not a formula; not everything in math is a formula. The point of this lesson is improving your number sense, your understanding of effects of math operations, and your overall mathematical intuition. Usually, the difference between strong and average math students is that strong students have a more developed and more accurate intuition.

Accurate mathematical intuition is important on some types of college entrance exam math questions, especially quantitative comparison questions.(6 votes)

- I'm still pretty confused...(2 votes)
- what do you need help with zippyding6(4 votes)

- At0:18why is x being increased? Shouldn't it be less so you can subtract without having it be a negative?(3 votes)
- what is the point how does it help us in later life?(2 votes)
- It helps the people who will work with calculating using formulas for example producing a bottle.(2 votes)

- Solve for the missing term in this proportion problem 7/30 = x/9(2 votes)
- At around0:43he said If So, if I'm going to subtract larger and larger values, I'm going to get smaller and smaller values. Isn't he saying the same thing?(2 votes)
- I'm not quite sure what you mean by this question. To clarify, he is saying that if you subtract a large value from a variable or a number, you will get smaller and smaller values for the answer.(1 vote)

## Video transcript

- [Voiceover] What I wanna do
in this video is think about how does the value of an expression change as a variable that makes
up that expression changes? So, let's start with a
pretty simple expression. Let's say we have the
expression 100 minus x. We wanna know how does
this expression change as x increases? As x increases and like always, try to work it out for yourself. Pause the video before I
try to have a go at it. Well, there's a couple of
ways you could think about it. You say, "Okay, I have 100
and I'm subtracting x." So, as x increases, as
x increases over here, I'm going to be subtracting
larger and larger values. So, if I'm subtracting
larger and larger values, I'm going to get smaller
and smaller values. So, this whole thing, this whole
thing is going to decrease. This whole thing is going to decrease and if you wanna make it a
little bit more concrete, you can actually try
out some values there. So, you can make a little table here. X and then, what is 100 - x going to be? I'm just gonna pick some values of x. I'm gonna make them increase. Say, x is zero, x is 50, x is 100. Well, when an x is zero,
100 - x is 100 - zero. So, it's 100. When x is 50, it's going be 100 - 50, so it's going to be 50. When x is 100, it's 100
- 100, so it's zero. So, it's pretty clear here
that as x is increasing, as x is increasing, I'll just
write incr. for increasing, we see that 100 - x is decreasing. We see that that is decreasing. Let's do this with a
couple more expressions that have different forms. So, let's say that I have the expression. Let's say that I have the
expression five over x plus five and x is decreasing, x is decreasing, but we also know that it is positive and even
while it's decreasing, it's staying above zero. So, we're saying x is
staying greater than zero. So, in this case, so ya know,
this could be a situation where x is decreasing from 10 to nine or a million to 100,000,
but it's staying positive while it's decreasing. Let's think about that. We are going to be dividing
by smaller and smaller positive values. So, as you have smaller
and smaller positive values of the denominator, you're
dividing by smaller and smaller positive values. So, if you're dividing by
smaller positive values, you're going to know that this
thing is going to get larger. This entire expression
is going to get larger as you divide by smaller
and smaller positive values. So, if that expression gets larger, then you're just adding five to it. The whole thing is going to increase. The whole thing is going to increase as, the whole thing is going
to increase as x decreases while staying positive. And once again, we can
make a little table to take a look at that. So, this is x, this is
five over x plus five. Now, let's see. I'll just try out some. Let's see, I'll go from
x 100 to x is five, to x is one. So, this is clearly x is decreasing. X is decreasing. When x is 100, you're gonna have five divided by 100, which
would be five hundredths plus five, so it would be 5.05. When x is five, you're gonna
have five divided by five, which is one plus five, which is six. When x is one, you're gonna
have five divided by one, which is five plus five. You just, it's 10. So notice, when x is staying
positive, but decreasing, the whole expression,
five over x plus five, this thing right over here is increasing. Let's do one more of these. So, let's say that we have the expression and we'll change up the variable here. 3y over 2y and I'm curious what happens to the value of this expression as y increases, as y increases. Well, as you have larger
y's here on the numerator, you're also going to have larger y's here in the denominator and one way you could think about this, this is the same thing as three halves times y over y. And no matter what y you have here, as long as it's not equal to zero and actually, let's just
assume that it doesn't cross zero because at that point, at that point, this thing
would become undefined. Let's just say that y increases and y is greater than
zero just for simplicity. So, y is a positive value here and actually, for any non-zero value, you take y, you divide by y, you're just gonna get one. So, it doesn't matter what y is. Y could be a million over a million. This thing is just gonna be one. Y could be five over five, it's still just going to be one. The value of the expression
is not going to change. It's just going to be three halves. So, the expression is
just going to be the same. You're not going to have any change as y increases, as y is
positive and it increases.