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## 6th grade

### Course: 6th grade > Unit 9

Lesson 3: Polygons on the coordinate plane- Drawing a quadrilateral on the coordinate plane example
- Drawing polygons with coordinates
- Area of a parallelogram on the coordinate plane
- Area and perimeter on the coordinate plane
- Coordinates of a missing vertex
- Example of shapes on a coordinate plane
- Dimensions of a rectangle from coordinates
- Coordinates of rectangle example
- Quadrilateral problems on the coordinate plane
- Quadrilateral problems on the coordinate plane
- Parallelogram on the coordinate plane
- Coordinate plane FAQ

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# Quadrilateral problems on the coordinate plane

Try five problems involving quadrilaterals on the coordinate plane.

## Problem 1: Find coordinates of missing vertex

## Problem 2: Area of parallelogram on coordinate plane

## Problem 3: Dimensions of rectangle from coordinates

## Problem 4: Coordinates of rectangle

## Bonus problem: Parallelogram on the coordinate plane

## Want to join the conversation?

- why is the alphabet now on math(20 votes)
- the letters aren't considered as the alphabet in the problems they are just used to show the different points and they also use the letters to name the points so that you don't get confused.(14 votes)

- how do you do the bonus problum?(12 votes)
- First, calculate the length of segment DC. X-axis of point D to C = -1.5 + s = 4.5 and y-axis of point D to C = 4+t=4. Then we got the length s is 6 and the length t is 0.

(Remember length in the segment is length between two-point. s and t is just a variable to represent the length in x-axis and y-axis of segment DC.)

Since the length of segment AB is the same as the length of segment DC---> X-axis of point A to B = 1 + 6 = j and Y-axis of point A to B = 1 + 0 = k ---> B(j , k) =B(7 , 1).

Sorry for my English. Hope this helps.(13 votes)

- what is the answer to life(7 votes)
- 17. The answer is always 17.(9 votes)

- Hey guys

I'm taking Geometry this coming fall, so I'm trying to prepare by taking the Khan courses, "Geometry" and "Get ready for Geometry." The course "Get ready for Geometry" is a bit easy right now, so I'm wondering if I should skip it and jump to the course "Geometry." What do you guys think? Is "Get ready for Geometry" vital for the course "Geometry"?(8 votes)- Sorry, I think I posted in the wrong section, so I'll repeat just in case: I think the "Get ready for Geometry" is pretty useful, but I don't think it's vital if you understand most of the concepts already.🙃(3 votes)

- why is this so increasingly difficult bruh(8 votes)
- i just wanna say hello(8 votes)
- Hello, Mr. Leo...(1 vote)

- How do you do this I don't understand the parraellograms(8 votes)
- To solve it easily, you first have to find the length of the base, or the long side. You also should find the height, and it is the distance from the long side to the other long side. After you find those dimensions, solve the rest like how you would solve for the area of an rectangle and square.(2 votes)

- All qustions should come wit a coordinate grid!(7 votes)
- this was greatly underwelming(6 votes)
- I dont understand the bonus question(2 votes)
- The first thing I noticed is that both sides are horizontal which means the y value has to be 1 (notice you have 2 y values of 4). Then, the x distance from D to C is 4.5-(-1.5)=6. Moving from the x value of A (1) six units gives 7 as the x value, thus point is (7,1). Hope this helps.(7 votes)