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## Differential Calculus

### Course: Differential Calculus > Unit 4

Lesson 2: Straight-line motion- Introduction to one-dimensional motion with calculus
- Interpreting direction of motion from position-time graph
- Interpreting direction of motion from velocity-time graph
- Interpreting change in speed from velocity-time graph
- Interpret motion graphs
- Worked example: Motion problems with derivatives
- Motion problems (differential calc)
- Total distance traveled with derivatives

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# Introduction to one-dimensional motion with calculus

AP.CALC:

CHA‑3 (EU)

, CHA‑3.B (LO)

, CHA‑3.B.1 (EK)

Straight-line motion can be modeled by giving position as a function of time. Calculus helps us learn about velocity, speed, and acceleration, all from our knowledge about the change in position.

## Want to join the conversation?

- 5:38: Why acceleration is -6 at t = 0?

At time 0 there is no change in velocity of the object then how can acceleration would have any value ?(5 votes)- This comes back to the whole definition of derivative as "instantaneous rate of change", which is a little difficult to deal with in physical contexts. The best way to think about it would be perhaps thinking of it as the acceleration being -6 on an infinitesimally short interval around t = 0, instead of at an exact instant.(11 votes)

- Still don't understand the point at the end about velocity. It's a -2 change from 5 to 3 and 3 to 1 so why does it become positive after 1 second(5 votes)
- velocity is dependant on direction, so it can be positive or negative. So if you go in the opposite direction the velocity will be negative(8 votes)

- I don't understand how velocity becomes less negative between the 1st and the 2nd seconds. You're going left from
**5 to 3**between**0 and 1**seconds, and then further left from**3 to 1**between**1 and 2 seconds**, so how does it become less negative?(4 votes)- you are slowing down to prepare for a turn, so your velocity will decrease. In this case the velocity was negative in the first place, so it becomes less negative, hence it is slowing down and acceleration is positive(5 votes)

- I am feeling lost after5:38

Can somebody provide alternate explanation ?(4 votes)- What Sal is saying at5:38is that acceleration is negative when t < 1, zero at t = 1, and positive when t > 1. When acceleration is negative, velocity becomes more negative (which is the same thing as less positive); when acceleration is positive, velocity becomes more positive (less negative).(6 votes)

- Why velocity is the derivative of time?(2 votes)
- It's not. Velocity is the derivative of position with respect to time. That is, if x(t) is your position as a function of time, then x'(t) is the velocity.(4 votes)

- does physics graphs always have time in the x axis?(2 votes)
- In physics, time is the
**independent**variable. Thinking of it this way can help "visualize" why things are the way they are dependingly(3 votes)

- is the third derivative the jerk?(2 votes)
- Yes! s'= velocity s''= acceleration s'''=jerk

4th-6th can be called snap, crackle and pop(3 votes)

- Let say I set a point in the middle. If my car is on the right of the point and accelerating to the right, its velocity is positive. What if my car is heading toward the right on the left hand side of the point? Is the velocity negative?(2 votes)
- Velocity is a vector. Its sign is given by the direction, not the relative position of the vector. Here, displacement is (at that instant) negative, but velocity is positive.(2 votes)

- I know this is more about math but how can i turn f(x) into f'(x)and the same as how can i turen f'(x) into f''(x)?(2 votes)
- first question after three years.(0 votes)

## Video transcript

- [Instructor] What we're going to do in this video is start to think about how we describe position in one dimension as a function of time. So we could say our position, and we're gonna think about position on the x-axis as a function of time. And we could define it by some expression, let's say, in this situation, it is going to be our
time to the third power minus three times our
time squared plus five. And this is going to apply for our time being non-negative 'cause the idea of negative time, at least for now, is a bit strange. So let's think about what this right over here is describing. And to help us do that, we could set up a little bit of a table to understand that depending
on what time we are, let's say that time is in seconds, what is going to be our
position along our x-axis? So at time equals zero, x of
zero is just going to be five. At time one, you're gonna have
one minus three plus five. So that is going to be, let's see, one minus
three is negative two, plus five is going to be, we're going to be at position three. And then at time two, we are going to be at eight minus 12 plus five, so we're going to be at position one. And then at time t equals three, it's gonna be 27 minus 27 plus five, we're gonna be back at five. And so, this can at
least help us understand what's going on for the
first three seconds. So let me draw our positive x-axis. So, say it looks something like that. And this is x equals zero. This is our x-axis. X equals one, two, three, four, and five. And now let's play out how this particle that's being described is
moving along the x-axis. So we're gonna start here, and we're gonna go one, two, three. Let's do it again. We're going to go one, two, three, the way I just moved
my mouse, if we assume that I got the time roughly right, is how that particle would move. And we can graph this as well. So for example, it would look like this. We are starting at time t equals zero. Our position, this is our
vertical axis, our y-axis, but we're just saying
y is going to be equal to our position along the x-axis. So that's a little bit counterintuitive because we're talking about our position in the left-right dimension, and here you're seeing it start off in the vertical dimension, but you see the same thing. At time t equals one, our
position has gone down to three. Then it goes down further. At time equals two, our
position is down to one. And then, we switch direction and then over the next, if we
say that time is in seconds, over the next second, we get back to five. Now an interesting thing to think about in the context of calculus is, well, what is our velocity
at any point in time? And velocity as you might remember, is the derivative of position. So let me write that down. So we're gonna be thinking about velocity as a function of time. And you could view velocity
as the first derivative of position with respect to time which is just going to be equal to, or we're gonna apply the power rule and some derivative
properties multiple times. If this is unfamiliar to you, I encourage you to review it. But this is going to be three t squared minus six t and then plus zero, and we're gonna restrict
the domain as well for t is greater than or equal to zero. And then, we can plot that. It would look like that. Now let's see if this curve
makes intuitive sense. We mentioned that one second, two seconds, three seconds. So we're starting moving to the left. And the convention is if
you're moving to the left, you have negative velocity, and if you're moving to the right, you have positive velocity. And you can see here our velocity immediately gets more and more negative until we get to one second, and then it stays negative
but it's getting less and less negative until
we get to two seconds. And at two seconds, our
velocity becomes positive. And that makes sense,
because at two seconds was when our velocity switched directions to the rightward direction. So, our velocity is getting
more and more negative, less and less negative, and
then we switch directions and we go just like that. And we see it right over here. Now one thing to keep in mind when we're thinking about
velocity as a function of time is that velocity and speed
are two different things. Speed, speed, let me write it over here. Speed is equal to, if you think about it in one dimension, you could think about it as the absolute value of your velocity as a function of time or
your magnitude of velocity as a function of time. So in the beginning,
even though your velocity is becoming more and more negative, your speed is actually increasing. Your speed is increasing to the left, then your speed is
decreasing, you slow down, and then your speed is increasing as we go to the right. And we'll do some worked examples that work through that a little bit more. Now the last concept we
will touch on in this video is the idea of acceleration. And acceleration you can view as the rate of change of
velocity with respect to time. So acceleration as a function of time is just going to be the first derivative of velocity with respect to time which is equal to the second derivative of position with respect to time. It's just going to be the
derivative of this expression. So once again, using the power rule here, that's going to be six t. And then using the power rule here, minus six, and once again,
we will restrict the domain. And we can graph that as well. And we would see right over here, this is y is equal to acceleration
as a function of time. And you can see at time equals zero, our acceleration is quite negative. It is negative six. And then it becomes less
and less and less negative. And then, our acceleration actually becomes positive at t equals one. Now, does that makes sense? Well, we're going one, two, three. You might say, "Wait, we
didn't switch directions "until we get to the second second." But remember, after we
get to the first second, our velocity in the negative direction becomes less negative which means that our acceleration is positive. If that's a little confusing, pause the video and
really think through that. So, our acceleration is
negative, then positive, and then positive continues. And so, this is just to
give you an intuition. In the next few videos, we'll
do several worked examples that help us dive deeper into this idea of studying motion and position, into this idea of studying
motion in one dimension.