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Interpreting change in exponential models: with manipulation

Sal analyzes the rate of change of various exponential models, where the function that models the situation needs some manipulation.

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• i watched this so many times and still dont get none of it
• you see 1.35^t/6+5=1.35^5times 1.35^t/6, this is logical, because 1.35^5 times 1.35^t/6=1.35^t/6+5
and (1.35^1/6）^t is also logical, bacause he moved the t outside the parentheses, and so the answer is the same, for example if t=5, 5/6= 0.83, and 1/6 times 5/1=5/6,so this is also logical,
but I don't really understand the last step
• At , I repeated the last part many times yet I still don't get it, I just don't understand how 5% is the answer
• The common ratio is 1.051, which means that every time t is increased by 1, M(t) is multiplied by 1.051. Since 1.051 is larger than 0, M(t) will be increasing. 1.051 = 105.1%, and since anything multiplied by 100% is itself, M(t) will increase by 5.1% (105.1-100) every day. Hope this helps!
• At , Did Sal forget to write 1.35^5? Or was that on purpose?
• He did, but it doesn't matter. 1.35^5 = ~4.484. Whether you are raising a sunfish weighing 4.484 grams by 5.1% of its weight or a sunfish weighing 1.35 grams by 5.1% of its weight, you're still increasing its weight by 5.1%. Regardless of whether he played that exponent, the answer to the problem is still 5.1%.
• can someone please explain this video in simpler terms? like a step-by-step process? thank you.
• So basically what we want to find in the video is the common ratio for 1 day but we are given the common ratio for t/5 +6 days. By using the properties of exponents. we already know, Sal simplifies it in a way such that the power of the common ratio is 1. Hope you find this helpful.
• at this point the hardest part isnt the math but just reading the problem and answering in the correct units lol
• Does this mean that the initial mass of the sunfish is 1.35^5 = 4.48...?
• Yes. It t=0 (no time since birth), then the sunfish weighs 1.35^5
• Anyone who doesn't understand this lesson needs to go back to Unit 6 and fully master Lesson 4 of Unit 6 (may seem frustrating at first, but you will get the hang of it).
• Can someone give me a few examples of how to solve problems like this? Im kinda-very stuck on it...

Thankyou!🙂
• Here is an example taken from the exercise following this video:
A sample of an unknown chemical element naturally loses its mass over time.
The relationship between the elapsed time t, in days, since the mass of the sample was initially measured, and its mass, M(t), in grams, is modeled by the following function:
M(t)=900⋅(8/27)^t
The sample loses 1/3 of its mass every ____ days.
Let's look at the different parts of the equation.
900 grams is the sample's initial mass.
Multiplying that by (8/27)^t means that by the end of each day only 8/27 of the amount that was there at the beginning of that day is left. In other words, the sample loses 19/27 of its mass over the course of one day. This is more than 1/3, so it must be that the sample loses 1/3 of its mass in less than one day.
For the purpose of this exercise, we can mostly ignore the original mass, 900.
If we can change the common ratio from 8/27 to 2/3 somehow, then we will be able to find out how long it takes for the sample to lose 1/3 of its mass.
8/27=2/3^3, so:
(8/27)^t=
((2/3)^3)^t=
(2/3)^3t
This means that after about 1/3 of a day 2/3 of the mass that was there at the beginning of the day remains. In other words, the sample loses 1/3 of its mass approximately every 0.33 days.
• I feel like this section needs more than just this lesson...
The techniques required to score on the follow up exercise are not trivial.
Anyone else?
• I wanna share this to people who struggle in the exercise for this lesson because I think their explanation for the question is not exactly clear(for me at least).

For example: A question ask you what t should be if we want a rate of change of (1/2), so you try to do exponent manipulation to turn 1000 ⋅ (1/64)^t into 1000 ⋅ (1/2)^6t.

1000 ⋅ (1/64)^t
1000 ⋅ （(1/2)^6）t
=1000 ⋅ (1/2)^6t

And you instinctively know or at have some idea what t is, you know the answer but not sure what the process is. And you look for the explanation given by the question which is kinda unclear.

The method I came up with which i wanna share is: think of original t as t① and think of the t the question trying to ask as t②

1000 ⋅ (1/64)^t①

1000 ⋅ (1/2)^6t②

You know from this, for one power(t①=1) you get a rate of 1/64. And you also know from the exponent manipulation you do earlier, one t② you get a rate of 1/2 which is what we are looking for.

What should we do to make 1000 ⋅ (1/2)^6t② become true while looking for t②? Algebra, you can express it in an algebraic expression.

Think of it this way, what 6t② should be in order to make the equation true? One. So if 6t②=1, what is t②? (divide both side by 6) t②=1/6. So there you have it, for power of 1/6 you a get rate of 1/2)

Whenever you get to this step, and wonder why if its the case, you can try to think it algebraically.

(Im not a teacher or anything, if i made any mistakes here, feel free to correct me.)