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## Geometry (all content)

### Course: Geometry (all content) > Unit 14

Lesson 8: Inscribed shapes problem solving- Proof: Right triangles inscribed in circles
- Inscribed shapes: find diameter
- Inscribed shapes: angle subtended by diameter
- Inscribed shapes: find inscribed angle
- Inscribed shapes
- Challenge problems: Inscribed shapes
- Inscribed quadrilaterals proof
- Solving inscribed quadrilaterals
- Inscribed quadrilaterals

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# Challenge problems: Inscribed shapes

Solve three challenging problems that apply properties of inscribed shapes to find an arc length or a missing angle.

## Problem 1

## Problem 2

## Problem 3

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- I don't get the last one. Where did the 1/10 pi and 3/10 pi come from? I'm so confused.(12 votes)
- Before going into the detail of the problem, here's an overview of how to approach solving it..

We want to find the measure of angle AED.

That angle is a vertical angle with angle BEC (so they're equal).

And angle BEC is one of the 3 angles in triangle BEC.

The other 2 angles are inscribed angles for which we're given their arc lengths.

So we can find the measure of those 2 angles, then use the fact that the sum of the angles of any triangle is 180 degrees ( pi radians) to find angle BEC which equals angle AED (because they're vertical angles).

Now, for the detail!

1. We'll use the fact that, because the radius is given as 5, the circumference (2pi*r) can be calculated to be 10pi

2. So, now ask yourself : the length of arc BA (given as pi) is what part of the circumference of 10pi?

This gives the fraction of pi / 10pi which equals 1 / 10 .

3. Do the same for arc CD (given as 3pi).

This gives the fraction of 3pi / 10pi which equals 3 / 10.

4. Now that we have the "arc length to circumference" ratios, we use those same ratios to proportion the inscribed angles (which by definition are half the arc length)

So, dividing 1 / 10 by 2 gives 1 / 20 for angle BCA and dividing 3 / 10 by 2 gives 3 / 20 for angle CBD.

In other words, angle BCA has 1 / 20 of the angles in a circle (360 degrees or 2pi)

and angle CBD has 3 / 20 of them.

So, angle BCA = ( 1 / 20 ) * 2pi = ( 1 / 10 ) * pi

and angle CBD = ( 3 / s0 ) * 2pi = ( 3 / 10 ) * pi

5. The 3 angles in triangle BCE add up to pi radians ( = 10/10 pi),

( 1 / 10 ) * pi + ( 3 / 10 ) * pi + angle BEC = ( 10 / 10 ) * pi

so, the missing angle (which angle AED equals) must be ( 6 / 10 ) * pi = 3pi /5

This is a lengthy reply, but I hope it helps you to be less confused (instead of more confused!).(35 votes)

- Can someone explain how I can intuitively know when I read a problem like these to know whether I should be looking for a result in Radians or in Degrees? I keep trying to answers these by what I think should be the approach and keep using the wrong one. I must be missing something obvious. Thank you.(6 votes)
- Let's look at question 3 as an example. While we could convert our radian measurements to degrees, we are asked to find the answer in radians. If they had mixed/matched some of the information in degrees and radians, then we would have to consider them both in our computation. Also, again in question 3, we are given measurements that reference pi; that is a dead give away that we will at least have to consider computing with radians. Hope this helps a bit.(13 votes)

- In problem 2 I set up the problem in such a way that the: Total circumference - BAD = BCD. So I got 10"pi"-BAD = BCD. Then I solved for BCD using Arc length method that sal taught us with the proportions a few videos back.

BAD/10"pi"= 9"pi"/20/2"pi"

BAD/10"pi"= 9/40

(I cross multiplied)

90"pi"= 40BAD

BAD = 90"pi"/40

BAD=9"pi"/4

Then I subtracted that from the total circumference

10"pi"-(9"pi")/4=31"pi"/4

So BCD is 31"pi"/4

Could you please tell me where i went wrong?(4 votes)- You went wrong in the second paragraph: BAD/10"pi"= 9"pi"/20/2"pi".

9𝜋 ∕ 20 is the angle at 𝐶, but we want the angle at 𝑃, which is 2 ∙ 9𝜋 ∕ 20 = 9𝜋 ∕ 10.

So, the equation should read:

(Arc 𝐵𝐴𝐷) ∕ (10𝜋) = (9𝜋 ∕ 10) ∕ (2𝜋) ⇔ (Arc 𝐵𝐴𝐷) = 9𝜋 ∕ 2 ⇒ (Arc 𝐵𝐶𝐷) = 11𝜋 ∕ 2.(9 votes)

- I dont understand how the angles in the last problem could possibly add up to 180 they are all 2 or 3 when multiplied out(4 votes)
- 180° = All interior angles of any triangle

180° = 2 angles that together form a straight line

180 degrees = 1 𝜋 radians

As the problem works with radians, all angles need to add up to 1 𝜋 radians.(4 votes)

- I do not understand a part of the explanation on problem 1, which reads, "The sides line segment AP and line segment PB are congruent because they are radii of the same circle."

Also, is the measure of an angle the same as its arc measure?(3 votes)- A radius of a circle is a straight line drawn from the center to the edge. All radii of a given circle are the same length (this is what it means to be a circle).

So because AP and PB are both radii of circle P, they must be the same length (congruent).

Also, yes, the measure of an arc is the same as the measure of the central angle that contains it. However, this problem asks for the*length*of the arc, not the measure.(5 votes)

- How do we know in question 2 that m< MBD + 9/20 pi equals pi and not 180?(3 votes)
- If you see the angle value as a coefficient of pi and that there is no degree symbol on the number, it's usually enough to conclude that the angle is measured in radians. Supplementary angles sum to 180 degrees, which is the same thing as pi radians. So:

m<MBD + 9/20 pi = pi(3 votes)

- what is the difference between arc length and arc measure ,given one how do you find the other(1 vote)
- The words give a hint. Arc length is a distance around a part of the circle, so this is comparable to the total length around a circle C = 2πr. The arc measure is an angle measure which is compared to the total angle around a circle 360 degrees or 2π radians. Set up a proportion between these two and solve.(6 votes)

- I thought the arc measure was supposed to be equal to the angle that intercepts it or in other words the central angle is equal to the arc it intercepts? However, in the second problem, the explanation states, "The measure of an inscribed angle is half of the measure of the arc it intercepts."(2 votes)
- In problem 2, the vertex of the angle is not positioned at the center of the circle. If it were, the arc that it intercepts would have the same measurement.

However, the vertex of the angle is positioned on the circle itself, making the arc that the inscribed angle intercepts twice as big as the angle itself.(3 votes)

- I saw the circle proportions equated when I thought the problem should have been solved, but was missing that arcMeasure/radiansInCircle is all in radians.
**Overall, I kept missing that I am figuring in radians and converting to units**. "==" is to be read as "is equivalent to". For future me:

(arc length in units/ circumference in units) represents arc length as a proportion of the entire circle's arc length,

(arc measure in radians / circle measure in radians) represents arc measure in radians as a proportion of the entire circle in radians,

(arc measure in degrees / circle measure in degrees) represents arc measure in degrees as a proportion of the entire circle in degrees.

Each proportion is equivalent to the other.

In problem 2: the radius is 5 units. Opposite angles in a quadrilateral add up to 180° (which is equivalent to π radians).

As the measure of angle BCD is (9π/20) radians, the measure of angle BAD must be π radians - (9π/20) radians == (11π/20) radians.

The radian measure of arc BCD is twice its angle: 2*(11π/20) radians == (11π/10) radians.

Convert the radians to the units: (arcLength) Units / (10π) Units == (11π/10) radians / (2π) radians == (11π/2) units.

In problem 3: the radius is 5 units. length of arc BA is π units -- use the proportions to find its equivalency in radians: (π/5) radians; the angle in radians is half the arc length in radians: therefore angle BCA is (π/10) radians.

Length of arc CD is 3π units -- use the proportions to find its equivalency in radians: (3π/5) radians; the angle in radians is half the arc length in radians: therefore angle CBD is (3π/10) radians.

Therefore angle BEC is π radians - (3π/10) radians - (1π/5) radians == (6π/10) radians == (3π/5) radians.

Therefore angle AED is (3π/5) radians.

I think having the units in the answer-explanations would have sped up debugging what I was failing to observe.(2 votes) - In problem 2 Angle C subtends arc BAD which should therefore be 2 x Angle c = 18/20 pi. Circumference of 10 pi - Arc BAD is my logical next step but is wrong. Where is my erro?(2 votes)