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Area of a parallelogram on the coordinate plane

Learn how to find the area of a parallelogram on the coordinate plane.

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  • starky ultimate style avatar for user ✐®oman
    This is a great video; everything is explained very well, but the exercise does not have visual aid like how this is taught. That would be okay if it was explained how to solve without a visual grid, but it wasn't. Sal, could you please give an additional explanation on how to do this in your head? It's a bit confusing without it.
    Much appreciated! :)

    *Please, vote up! Please don't misunderstand me and flag this, because it's not for me, but so that we can keep it emphasized and get this explained!
    (64 votes)
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  • aqualine ultimate style avatar for user Dylan J. Dess
    I'm so confused. The question doesn't let us do this
    (13 votes)
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  • hopper cool style avatar for user Angela
    no fair you get all these colors and tools and we don't
    (9 votes)
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  • blobby green style avatar for user tehzeebsultan
    With the height, how is it 4? there was one square that was 1/2. shouldn't it be 3/2?
    (5 votes)
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  • winston baby style avatar for user rivertompkins
    What about perimeter not area?
    (8 votes)
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  • starky tree style avatar for user MeheretElias
    how do we do things like that without having the shape in front of us do we just guess
    (6 votes)
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  • aqualine tree style avatar for user Acp!!
    it doesn't help me :(
    (5 votes)
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  • marcimus purple style avatar for user Lily
    I don't understand this
    (5 votes)
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  • spunky sam red style avatar for user Kadin Jelany Abdul-Qadir
    Aren't we supposed to divide the area of each of the two triangles by two and add those to the area of the parallelogram?
    (3 votes)
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  • starky seedling style avatar for user BentleyB
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    (2 votes)
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Video transcript

- [Voiceover] Let's see if we can find the area of this parallelogram, and I encourage you to pause the video and see if you can figure it out on your own. Well, we just have to remind ourselves that the area of a parallelogram is just going to be the base -- let me do this in different colors -- it's going to be the base of the parallelogram, so I want to do that in a different color, so let me write: the base of the parallelogram times the height of the parallelogram, times the height of the parallelogram. Area is equal to base times height. So, what could we consider to be the base of this parallelogram? Well, we could imagine it to be one of these sides. So, we could go from here, and so, I could say... well, I could consider this to be the base. So, what's the length of that base? Well, we're just going in the vertical direction. We go from "y" equals five, to "y" is equal to negative seven, so this has length 12. We have five above the x-axis, and seven below the x-axis, adding up to 12. Or, you could count it: One, two, three, four, five, six, seven, eight, nine, ten, 11, 12. So, this is our base, and we could say that base is equal to 12. And, now, what could we view as our height? Well, we could view this dimension, right over here, as our height. And, what is that going to be? Well, you can see very clearly that the height is equal to four. And, it might be a little counter-intuitive, 'cause normally, when you're talking about height, you're used to thinking about how high something is, but you could imagine rotating this around so that the base is laying flat, and then the height is the height, in the traditional sense of the word. But, we could say "h" is equal to four, and now, it's pretty straightforward. Our area is going to be equal to 12, the length of our base times our height, times four, times four, which is clearly just 48. 48, whatever, square, 48 square units.