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High school geometry

Course: High school geometry > Unit 5

Lesson 6: Solving for a side in a right triangle using the trigonometric ratios
Math
High school geometry
Right triangles & trigonometry
Solving for a side in a right triangle using the trigonometric ratios
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Solving for a side in right triangles with trigonometry

Google Classroom
Learn how to use trig functions to find an unknown side length in a right triangle.
We can use trig ratios to find unknown sides in right triangles.

Let's look at an example.

Given △ABC, find AC.
A right triangle A B C. Angle A C B is a right angle. Angle A B C is fifty degrees. Side A C is unknown. Side A B is six units.

Solution

Step 1: Determine which trigonometric ratio to use.
Let's focus on angle B since that is the angle that is explicitly given in the diagram.
A right triangle A B C. Angle A C B is a right angle. Angle A B C is fifty degrees and is highlighted. Side A C is unknown. Side A B is six units.
Note that we are given the length of the hypotenuse, and we are asked to find the length of the side opposite angle B. The trigonometric ratio that contains both of those sides is the sine.
Step 2: Create an equation using the trig ratio sine and solve for the unknown side.
sin⁡(B)= opposite  hypotenuse        Define sine.sin⁡(50∘)=AC6                       Substitute.6sin⁡(50∘)=AC                         Multiply both sides by 6.4.60≈AC                         Evaluate with a calculator.

Now let's try some practice problems.

Problem 1

Given △DEF, find DE.
Round your answer to the nearest hundredth.
A right triangle D E F. Angle D F E is a right angle. Angle D E F is fifty degrees. Side D E is unknown. Side E F is four units.
  • Your answer should be
  • an integer, like 6
  • a simplified proper fraction, like 3/5
  • a simplified improper fraction, like 7/4
  • a mixed number, like 1 3/4
  • an exact decimal, like 0.75
  • a multiple of pi, like 12 pi or 2/3 pi

Problem 2

Given △DOG, find DG.
Round your answer to the nearest hundredth.
A right triangle D O G. Angle D O G is a right angle. Angle D G O is seventy-two degrees. Side D G is unknown. Side D O is eight point two units.
  • Your answer should be
  • an integer, like 6
  • a simplified proper fraction, like 3/5
  • a simplified improper fraction, like 7/4
  • a mixed number, like 1 3/4
  • an exact decimal, like 0.75
  • a multiple of pi, like 12 pi or 2/3 pi

Problem 3

Given △TRY, find TY.
Round your answer to the nearest hundredth.
A right triangle T R Y. Angle R T Y is a right angle. Angle T R Y is thirty-seven degrees. Side T Y is unknown. Side R T is three units.
  • Your answer should be
  • an integer, like 6
  • a simplified proper fraction, like 3/5
  • a simplified improper fraction, like 7/4
  • a mixed number, like 1 3/4
  • an exact decimal, like 0.75
  • a multiple of pi, like 12 pi or 2/3 pi

Challenge problem

In the triangle below, which of the following equations could be used to find z?
A right triangle M I X. Angle I M X is a right angle. Angle I X M is twenty-eight degrees. Side I X is unknown. Side I M is twenty units.
Choose all answers that apply:

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  • starky seed style avatar for user PP
    Posted 8 years ago. Direct link to PP's post “please can someone just e...”
    please can someone just explain q.2 really slowly and simply? Thanks :) it's totally confusing me!
    (33 votes)
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    • starky ultimate style avatar for user Seunghyun Nam
      Posted 7 years ago. Direct link to Seunghyun Nam's post “- You are given the side ...”
      Incredible Answer
      Great Answer
      Good Answer
      - You are given the side OPPOSITE the 72 degree angle, which is 8.2.
      - You are solving for the HYPOTENUSE.
      Therefore you need the trig function that contains both the OPPOSITE and the HYPOTENUSE, which would be SINE, since sin = OPPOSITE / HYPOTENUSE.

      "Let's input the value into the equation."
      sin (deg) = opposite/hypotenuse
      sin (72) = 8.2/DG

      "Since we're solving for DG, the hypotenuse, we have to move it so that it is on the numerator. Thus, you multiply both sides of the equation by DG"
      DG sin(72) = 8.2

      "Again because we're solving for DG, we have to isolate DG so that it alone is on the left side of the equation. To do so, we have to move sin(72) to the other side, or in other words divide both sides of the equation by sin(72)."
      DG = 8.2/sin(72)

      "Now use the calculator"
      8.2/sin(72) = 8.621990.....

      "Round you're answer to the nearest hundred, and you get your answer."
      8.62

      Hope this helped :)
      (138 votes)
  • blobby green style avatar for user rogirlash
    Posted 5 years ago. Direct link to rogirlash's post “why is my calculator givi...”
    why is my calculator giving me the wrong answer?
    (11 votes)
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  • blobby green style avatar for user joelmazda6.rx8
    Posted 7 years ago. Direct link to joelmazda6.rx8's post “I don't understand. How a...”
    I don't understand. How angles that have simple ratios can be discovered? For example, how do you know if sin 30 is 1/2 ?
    (13 votes)
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    • blobby green style avatar for user Andrea O'Keefe
      Posted 4 years ago. Direct link to Andrea O'Keefe's post “When using similar triang...”
      Good Answer
      When using similar triangles, their sides are proportional. If two triangles have two congruent angles, then the triangles are similar. So, if you have a 30-60-90 triangle then the sine ratio is defined as the ratio of the length of the side opposite to the length of the hypotenuse. Doesn't matter how "big" the triangle, those sides will always have the ratio of 1/2.
      (13 votes)
  • blobby green style avatar for user tkford11
    Posted 4 months ago. Direct link to tkford11's post “Ok I'm so lost now like I...”
    Ok I'm so lost now like I get and understand how to break it down and how to set it up to solve it but for some reason with my calculator the answers I'm getting aren't the same. For example 3*tan(37) I'm getting -2.52 yet in the comments I seen Joshua commented to Ben the break down and everything and says 3*tan(37)= 2.26 so why is my calculator showing different then everyone else?
    (7 votes)
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  • duskpin sapling style avatar for user Sophie
    Posted 7 years ago. Direct link to Sophie's post “I really need help with p...”
    I really need help with problem 3
    (6 votes)
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    • eggleston blue style avatar for user Bubble Tea's Incarnation 🧋
      Posted 2 years ago. Direct link to Bubble Tea's Incarnation 🧋's post “Hi! I am not really sure ...”
      Hi! I am not really sure what you need help with but I will try to explain it the best I can.

      To find TY, the side you are looking for, you need to use tan.

      You use tan because of SOH CAH TOA, to use tan you use the opposite and adjacent which you have in the problem.

      Look at the 37 degree. The side across from it, or the opposite, is what you are trying to find so it will be your x or unknown value. You know the adjacent side, it is three.

      So you will set up your equation like this

      tan(37)=x/3

      The 37 comes from the degree you used as a reference point. The x comes from TOA, so you put the opposite side over the adjacent. The opposite side is x in this case and the adjacent is 3 in this case. You then find the value of tan(37) using your calculator and multiply it by three (you are using basic algebra here, treat tan(37) like a number), and you are done!

      Hope that helps!
      (6 votes)
  • blobby green style avatar for user saavedrafrancis1998
    Posted 3 months ago. Direct link to saavedrafrancis1998's post “ez pz lemon squeezy!”
    ez pz lemon squeezy!
    (10 votes)
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  • male robot donald style avatar for user aadityasuri1
    Posted 7 years ago. Direct link to aadityasuri1's post “I don't understand that h...”
    I don't understand that how does one calculate a tangent without a calculator
    (5 votes)
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  • leaf green style avatar for user thelordoftherings713
    Posted 7 months ago. Direct link to thelordoftherings713's post “How do I know whether to ...”
    How do I know whether to use sin, cos, or tan?
    (4 votes)
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    • cacteye blue style avatar for user Jerry Nilsson
      Posted 7 months ago. Direct link to Jerry Nilsson's post “In the example we are giv...”
      In the example we are given right triangle 𝐴𝐵𝐶, with its right angle at 𝐶.
      We are also given that angle 𝐵 measures 50°, and that the length of side 𝐴𝐵 is 6.
      And we are told to find the length of side 𝐴𝐶.

      The trigonometric ratios only work for the non-right angles, in this case either angle 𝐴 or angle 𝐵.
      We know that the measure of angle 𝐵 is 50°, so let's use that.

      – – –

      In a triangle, the side opposite of an angle is the side that does not help form the angle.
      In this case angle 𝐵 is formed by sides 𝐴𝐵 and 𝐵𝐶, which leaves 𝐴𝐶 as the opposite side.

      In a right triangle, the hypotenuse is the side opposite of the right angle.
      In this case the right angle is formed by sides 𝐴𝐶 and 𝐵𝐶, leaving 𝐴𝐵 as the hypotenuse.

      In a right triangle, the side adjacent to a non-right angle is the side that together with the hypotenuse forms the angle.
      We have already established that angle 𝐵 is formed by sides 𝐴𝐵 and 𝐵𝐶, and that 𝐴𝐵 is the hypotenuse.
      Thereby side 𝐵𝐶 must be the adjacent side.

      So, to summarize,
      the measure of angle 𝐵 is 50°.
      Side 𝐴𝐵, the hypotenuse, has a length of 6.
      We want to find the length of side 𝐴𝐶, which is opposite of angle 𝐵.

      – – –

      From SOH-CAH-TOA we have that
      Sine = Opposite∕Hypotenuse
      Cosine = Adjacent∕Hypotenuse
      Tangent = Opposite∕Adjacent

      Since we know the length of the hypotenuse and we want to find the length of the opposite side, it seems that we would want to use the Sine formula.

      Plugging our values into the formula, we get
      sin 50° = 𝐴𝐶∕6

      Multiplying both sides by 6, we get
      𝐴𝐶 = 6 sin 50° ≈ 4.6
      (9 votes)
  • duskpin seed style avatar for user SaraJo Gardner
    Posted 5 years ago. Direct link to SaraJo Gardner's post “What if you have only the...”
    What if you have only the hypotenuse and one angle then what do you do?
    (2 votes)
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    • hopper cool style avatar for user Marian
      Posted 3 years ago. Direct link to Marian's post “It'd depend on what are y...”
      It'd depend on what are you find, the adjacent or the opposite. To find the opposite you'd use the SIN(angle)= opposite you want to find/hypotenuse you have; you'd just have to do the equation with the O/H inverse. Same to find the adjacent, but with COS.

      Hope it helps you. :)
      (8 votes)
  • blobby green style avatar for user tom-moy forbes
    Posted 6 years ago. Direct link to tom-moy forbes's post “can trig ratios be used o...”
    can trig ratios be used on acute triangles
    (5 votes)
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