Sal expresses (x-4)(x+7) as the standard trinomial x²+3x-28 and discusses how the general product (x+a)(x+b) can be written as x²+(a+b)x+a*b.
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- At0:22he said "standard Quadratic form". Previously he spoke about standard from and just said you order in from greatest degree to lowest degree and didn't mention the Quadratic part, is standard Quadratic form more specific?? And what does the 'Quadratic' part explain?(7 votes)
- He's just specifying the type of equation he's working with.
Extra info: There are four specific ways to reference the degree (the greatest exponent) of an expression:
Linear: degree of 1; (x+2),(x)
Quadratic: degree of 2; (x^2-5x+2),(x^2+3),(x^2+8x),(x^2)
Cubic: degree of 3; (x^3+x^2+x+1)
Quartic: degree of 4; (x^4)
It doesn't matter how many terms are in an expression when you're trying to determine its degree.
Information related to the kind of examples given: The number of terms in an expression has three specific words, and one general word.
Monomial: Only one term
Binomial: Two terms
Trinomial: Three terms
Polynomial (general): More than three terms(30 votes)
- Why plus seven at the start?(9 votes)
- I think the idea was that you take the two terms, here being x and positive 7 and distributing each term to (x-4) and once you get the binomial products, you add them together to get the answer of x^2+3x-28. Another method to multiply binomials is FOIL or First Outside Inside Last. Both of these methods will give you the same answers but FOIL is typically faster. Hope this helps!(7 votes)
- The general product can be written as shown above because he is basically taking steps instead of doing it at once .(8 votes)
- I distributed the (x+7) instead of distributing (x-4). Would that be wrong? or is the outcome the same all the time?(3 votes)
I know how to do these kind of problems but what i don't understand is how to figure out what signs to use in the answer...
I know this answer is...
My question is where they would squeeze in an addition sign if its all subtraction...
- You need to review the rules for multiplying signed numbers.
A negative * a negative = a positive.
So, the +12 comes from -3 (-4) = +12
Hope this helps.(4 votes)
- So, when multiplying binomials does it matter which one you multiply by? For example in this video could Sal have done x(x-7)-4(x-7)?(2 votes)
- What about multiplying binomials with two terms with numbers subtracted from the Xs? At3:11, Sal finishes the only problem he solves in this video, which involves a st of both operations used in the Practice tab, but it is the only problem addressed in the video. Could someone pleas help me?(2 votes)
- Do you mean something like: (x-4)(x-7)?
You follow the same steps as in the video, except you'll have some different signs coming out of the multiplication.
(x-4)(x-7) = x(x-4)-7(x-4)
= x^2 - 4x - 7x + 28
= x^2 - 11x + 28
Hope this helped. If this wasn't what you were looking for, give a specific example.(1 vote)
- At1:00. Why say you are going to multiply it one way and then multiply it the totally opposite way? TOTAL OPPOSITE from the way you drew the arrows.(1 vote)
- It's not the opposite way of multiplying it. He is actually doing exactly what he says. I can see why you think that, but what he is doing is multiply the number (x-4) by x and then multiplying (x-4) by 7 and adding the sum, which is exactly what he stated.(3 votes)
- I felt bad as soon as he says Standard Quadratic Form at0:06mins in the video, and then he tells me the "simplified definition" with a bunch of complicated terms (second degree term, coefficient etc) I have to google anyway despite having worked through Early Maths, Arithmetic and Pre-algebra in that respective order to be here to learn this lesson... I feel like I'm missing some info.… ((2 votes)
- For some reason the introduction to polynomial is in the section algebra 2 that is why you have not seen it. (Note; the 2 is in a roman numeral form)(1 vote)
- [Voiceover] Let's see if we can figure out the product of x minus four and x plus seven. And we want to write that product in standard quadratic form which is just a fancy way of saying a form where you have some coefficient on the second degree term, a x squared plus some coefficient b on the first degree term plus the constant term. So this right over here would be standard quadratic form. So that's the form that we want to express this product in and encourage you to pause the video and try to work through it on your own. Alright, now let's work through this. And the key when we're multiplying two binomials like this, or actually when you're multiplying any polynomials, is just to remember the distributive property that we all by this point know quite well. So what we could view this is as is we could distribute this x minus four, this entire expression over the x and the seven. So we could say that this is the same thing as x minus four times x plus x minus four times seven. So let's write that. So x minus four times x, or we could write this as x times x minus four. That's distributing, or multiplying the x minus four times x that's right there. Plus seven times x minus four. Times x minus four. Notice all we did is distribute the x minus four. We took this whole thing and we multiplied it by each term over here. We multiplied x by x minus four and we multiplied seven by x minus four. Now, we see that we have these, I guess you can call them two seperate terms. And to simplify each of them, or to multiply them out, we just have to distribute. In this first we're going to have to distribute this blue x. And over here we have to distribute this blue seven. So let's do that. So here we can say x times x is going to be x squared. X times, we have a negative here, so we can say negative four is going to be negative four x. And just like, that we get x squared minus four x. And then over here we have seven times x so that's going to be plus seven x. And then we have seven times the negative four which is negative 28. And we are almost done. We can simplify it a little bit more. We have two first degree terms here. If I have negative four xs and to that I add seven xs, what is that going to be? Well those two terms together, these two terms together are going to be negative four plus seven xs. Negative four plus, plus seven. Negative four plus seven xs. So all I'm doing here, I'm making it very clear that I'm adding these two coefficients, and then we have all of the other terms. We have the x squared. X squared plus this and then we have, and then we have the minus, and then we have the minus 28. And we're at the home stretch! This would simply to x squared. Now negative four plus seven is three, so this is going to be plus three x. That's what these two middle terms simplify to, to three x. And then we have minus 28. Minus 28. And just like that, we are done! And a fun thing to think about, since it's in the same form. If we were to compare a is one, b is three, and c is -28, but it's interesting here to look at the pattern when we multiplied these two binomials. Especially these two binomials where the coefficient on the x term was a one. Notice we have x times x, that what actually forms the x squared term over here. We have negative four, let me do this in a new color. We have negative four times, that's not a new color. We have, we have negative four times seven, which is going to be negative 28. And then how did we get this middle term? How did we get this three x? Well, you had the negative four x plus the seven x. Or the negative four plus the seven times x. You had the negative four plus the seven, plus the seven times x. So I hope you see a little bit of a pattern here. If you're multiplying two binomials where the coefficients on the x term are both one. It's going to be x squared. And then the last term, the constant term, is going to be the product of these two constants. Negative four and seven. And then the first degree term right over here, it's coefficient is going to be the sum of these two constants, negative four and seven. Now this might, you could do this pattern if you practice it. It's just something that will help you multiply binomials a little bit faster. But it's super important that you realize where this came from. This came from nothing more than applying the distributive property twice.