How would you solve "1- [cos x squared/1 +sin x]?

I think this is a late answer, but anyway, here you are: 1- [cosX squared/1 +sinX] = [1 + sinX - (cosX)^2]/1 + sinX This is possible because 1 = (1 + sinX)/(1 + sinX) We also know that 1 - (cosX)^2 = (sinX)^2 Now, [1 - (cosX)^2 + sinX]/1 + sinX = [(sinX)^2 + sinX]/1 + sinX Factoring out the sinX, [sinX (sinX + 1)]/1 + sinX = [sinX (1 + sinX)]/1 + sinX = sinX Hope this helped!

I got lost for a brief moment, how did you turn that 1 on the right side into 1^2. Do I have to do anything to the equation to achieve that? Or can I write as 1^2 just because I want to?

Good question! No, you don't have to do anything to the equation to achieve that, since 1 is equal to 1 squared. The only reason it is written like that in the video is to portray the a^2 - b^2 format, which can be simplified into (a + b)(a - b), as was done. Hope this helped!

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Class 10 math (India)

Course: Class 10 math (India) > Unit 8

Lesson 5: Trigonometric identities

Trigonometric identity example proof involving sec, sin, and cos

Name: Trigonometric identity example proof involving sec, sin, and cos
Uploaded: 2018-07-04T11:28:32Z
Description: Let's try to prove a trigonometric identity involving Secant, sine, and cosine of an angle to understand how to think about proofs in trigonometry. There are many ways to prove these identities.

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Let's try to prove a trigonometric identity involving Secant, sine, and cosine of an angle to understand how to think about proofs in trigonometry. There are many ways to prove these identities. Created by Aanand Srinivas.

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Abigail Kennedy
Posted 4 years ago. Direct link to Abigail Kennedy's post “How would you solve "1- [...”
How would you solve "1- [cos x squared/1 +sin x]?
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(6 votes)
Answer
- Exodus37
  Posted 3 years ago. Direct link to Exodus37's post “I think this is a late an...”
  I think this is a late answer, but anyway, here you are:
  1- [cosX squared/1 +sinX]
  = [1 + sinX - (cosX)^2]/1 + sinX
  
  This is possible because 1 = (1 + sinX)/(1 + sinX)
  We also know that 1 - (cosX)^2 = (sinX)^2
  Now,
  
  [1 - (cosX)^2 + sinX]/1 + sinX
  = [(sinX)^2 + sinX]/1 + sinX
  
  Factoring out the sinX,
  
  [sinX (sinX + 1)]/1 + sinX
  = [sinX (1 + sinX)]/1 + sinX
  = sinX
  
  Hope this helped!
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  (5 votes)
Ethan Needham
Posted 3 years ago. Direct link to Ethan Needham's post “I got lost for a brief mo...”
I got lost for a brief moment, how did you turn that 1 on the right side into 1^2. Do I have to do anything to the equation to achieve that? Or can I write as 1^2 just because I want to?
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(2 votes)
Answer
- Exodus37
  Posted 3 years ago. Direct link to Exodus37's post “Good question! No, you do...”
  Good question!
  No, you don't have to do anything to the equation to achieve that, since 1 is equal to 1 squared.
  The only reason it is written like that in the video is to portray the a^2 - b^2 format, which can be simplified into (a + b)(a - b), as was done.
  Hope this helped!
  Button navigates to signup page
  (3 votes)
Arihanth sharma
Posted 3 years ago. Direct link to Arihanth sharma's post “Hey,I don't understand th...”
Hey,I don't understand this part 1+1/cos A/ 1/cos A part
What did they do in this part
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(3 votes)
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Castiel Stouffer
Posted 2 years ago. Direct link to Castiel Stouffer's post “How would you solve (sinx...”
How would you solve (sinx+cosx)^2+(sinx-cosx)^2
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(2 votes)
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jonabelle22.jg
Posted a year ago. Direct link to jonabelle22.jg's post “How would you solve 1+si...”
How would you solve
1+sinx/1+cscx = Tanx/secx
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(2 votes)
Answer

Class 10 math (India)

Course: Class 10 math (India) > Unit 8

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