Class 10 math (India)
- Age word problem: Ben & William
- Age word problems
- System of equations word problem: walk & ride
- Systems of equations word problems
- Systems of equations with elimination: TV & DVD
- Forming equations with two variables
- Word problems involving pair of linear equations (advanced)
Age word problem: Ben & William
Sal solves the following age word problem: William is 4 times as old as Ben. 12 years ago, William was 7 times as old as Ben. How old is Ben now? Created by Sal Khan.
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- i don't understand age word problems please if you have any advice ,recommendations answer this question because I've tried many different websites but i don't seem to get how to solve age word problems .(27 votes)
- what do you not get about it?(0 votes)
- I feel the crux to understanding Sal in this is that 4b-12 is already 7 times as old as Ben's b-12.
That is why he multiplied Ben's (b-12) by 7, so it can equal to William.
I guess I'm sorta saying the 7 times is already applied to the equation right from the beginning. So you have to compensate by multiplying Ben's past age by 7 to equal William's.
Therefore 7*(b-12) = 4b-12(21 votes)
- Can someone help explain this to me? I need help with these kinds of things.(8 votes)
- Does anyone have a quick way to calculate division with big numbers like 256/4? (I know its 64 so don't JUST give me the answer) I could do the 72/3 in my head but if there is a good way to do those types of division mentally I'd be glad to hear it.(3 votes)
- There are many tips and tricks to dividing numbers in your head.
In your example, 256/4 is the same as 256/2/2 (you can plug this into your calculator to check). So, in reality all you have to do is halve the number twice. Ex: 256->128->64, which is easier to do in your head than doing brute force dividing. There is no quick way to divide by 3 other than just doing it the long way in your head, but there is a divisibility rule (a rule that tells you if 3 can evenly go into a number) for it. If you add up the digits of the number you are trying to divide by 3, and the sum of the digits is divisible by 3, the entire number is divisible by 3. With your number, 72 you can add the digits. 7+2=9. 9, we know, is divisible by 3, so 72 is divisible by 3. This divisibility rule works for all numbers.(10 votes)
- Couldn't you make an equation differently and end up with the same answer? Like I got the equations w=4b and w-12=7b and solved using substitution but didn't get the correct answer? Why?(0 votes)
- You have a mistake in your 2nd equation.
"b" represents Ben's current age. When you create the 2nd equation, both Williams and Ben's ages need to be 12 years younger. So, your 2nd equation need to be:
w-12 = 7(b-12)
Hope this helps.(14 votes)
- At2:32; I don't understand why for William (12 years ago column) it's 4b-12 and not just 7b?(4 votes)
- Think of it this way: Pretend William is 6 years old and Ben is 2, so Will is 3 times the age as Ben, so the equation is (3)2=6, the 2 is Ben's age, the 3 is how many times Ben's age goes into Wills, and the 6 is Will's age. Now, since the real question says that William is 7 times as old as ben, we can set up the equation as this: 7(b-12) = 4b-12. B-12 is Ben's age 12 years ago and 4b-12 is Will's age 4 years ago.(0 votes)
- Wait a sec...if 12 yrs ago, William was 7x as old as Ben, and they both have a birthday every year, shouldn't he stay 7 times older? And, i would understand if the 7 was instead an even number. But 7? I don't really get that.(1 vote)
- If I am 12 now, and my younger brother is 4 years old, then next year, I will be 13 (at the end of the year), and my brother will be 5. Before, I was 3 times as old as my brother, now, I am only 2.6 times as old as him. So the ratio of the ages will change over time; however, the difference between 2 peoples ages will stay the same.(9 votes)
- I still have ZERO idea on how to do this. Can u suggest other videos that might help and include the link?(4 votes)
- I've been trying to figure this out for the past couple of months and I'm nowhere near to understanding what variables to plug in. I've been trying to figure this particular problem out with no success:
John is twice as old as his friend Peter. Peter is 5 years older than Alice. In 5 years, John will be three times as old as Alice. How old is Peter now?
Any thoughts?(3 votes)
- Kevin is 4 times as old as Daniel and is also 6 years older than Daniel. How old is Kevin? Could somebody tell me how to solve this problem?(2 votes)
- K = 4d <--- Kevin is 4 times as old as Daniel
K = d + 6 <--- Kevin is 6 years older than Daniel
4d = d + 6 <--- They both equal K, so they are equal
3d = 6 <--- subtracts D from both sides
d=6/3 = 2
If Daniel is 2 then Kevin is 4*2=8
If Daniel is 2 then Kevin is 2+6 = 8
Kevin is 8
Daniel is 2(3 votes)
Let's do some more of these classic age word problems. So we're told that William is 4 times as old as Ben. 12 years ago, William was 7 times as old as Ben. How old is Ben now? Once again, it's a good idea to try to do this on your own first, and then I'll work through it. What's the unknown here? Well, the unknown here is how old is Ben now. So let's set a variable equal to that, and we do x or y. But since Ben starts with a b, let's use b for Ben. So let's let b equal Ben's current age, Ben's age now. Let's see how all of this other information relates to Ben's current age, and then maybe we can set up some equation and then solve for things. I'll do it a little bit more structured in this one. You could have done many of the problems we've been working on in this way. Let's think about Ben, and then let's think about William. I'll do William in blue here. So let's think about William. And then there's two points in time we're talking about. We're talking about now, today, and we're going to talk about 12 years ago. Over here, let's call that now. This will be our now column, and then this will be our 12 years ago. Let's see what we can fill in here. What is Ben's age now? Well, we just defined that as the variable b. That's the unknown. That's what we have to figure out. So let's just stick that there. That's just going to be b. Well, what's Ben's age 12 years ago? So maybe we want to express it in terms of b. If he's b now, 12 years ago, he was just b minus 12. Fair enough. Now what is William's age today? Well, this first sentence gave us the information. William is 4 times as old as Ben. And we can assume that they're talking about today, is 4 times as old as Ben. So if Ben is b, William is going to be 4b. And so how old was William 12 years ago? Well, if he's 4b right now, 12 years ago, he'll just be 12 less than that. So he's 4b now. 12 years ago, he was 4b minus 12. So that's kind of interesting. But we haven't quite yet made use of the second statement. This is William 12 years ago. 12 years ago, William was 7 times as old as Ben. So 12 years ago, this number is going to be 7 times this number. Or another way to think about, take this number and multiply it by 7, and you're going to get this number. 12 years ago, Ben's age is 1/7 of William's age, or William's age is 7 times Ben's age. So let's see if we can set that up as an equation. We can have-- let me write this down-- 7 times Ben's age 12 years ago, b minus 12, is going to be equal to William's age. And it seems like we've done the hard part. We've set up the equation. Now we just use a little bit of our algebraic tools to solve for b. So let's do that. The first thing we might want to do, we could distribute the 7, so 7 times b, 7 times, essentially, a negative 12. We have 7b minus 7 times 12-- let's see. That's 84-- is going to be equal to 4b minus 12. This whole expression is literally 7 times Ben's age 12 years ago. Now what can we do to solve this? Well, we can subtract 4b from both sides, so let's do that. I could do two steps at the same time. Well, actually, let's just keep it simple. I'm going to subtract 4b from both sides. That goes away. On the right-hand side, I have a negative 12. On the left-hand side, I am left with 7b minus 4b is 3b. And then I still have a minus 84. Well, I want to get rid of this negative 84, this minus 84 on the left-hand side. So let's add 84 to both sides. On the left-hand side, I'm just left with 3b. And on the right-hand side, I have negative 12 plus 84, or 84 minus 12, which is 72. Now if I want to solve for b, I just have to divide both sides of that equation by 3. And so I am left with b is equal to-- and now we have our drum roll-- 72/3. And you might be able to do that in your head. It would be 24, I believe. You could work it out on paper if you have trouble. Let's just do it real quick. 72, 3 goes into 7 two times. You get a 2 times 3 is 6, subtract, you bring down the 2, 3 goes into 12 four times. So b is equal to 24. Going back to our question, what is Ben's age now? It is 24. And let's verify that this is actually the case. They're telling us that William is 4 times as old as Ben. So what is William's current age? Well, 4 times 24 is 96, so William is a senior. We should call him Mr. William. He is 96 years old. Maybe he's Ben's grandfather or great-grandfather. Then they say 12 years ago, William-- well, 12 years ago, William was 84 years old. So he was 84 years old. They say that's 7 times as old as Ben. Well, 12 years ago, if he's 24 now, Ben was 12. And indeed, 84 is 7 times 12, so it all worked out.