Integrated math 1
- Why we do the same thing to both sides: Variable on both sides
- Intro to equations with variables on both sides
- Equations with variables on both sides: 20-7x=6x-6
- Equations with variables on both sides
- Equation with variables on both sides: fractions
- Equations with variables on both sides: decimals & fractions
- Equation with the variable in the denominator
Sal solves the equation 7 - 10/x = 2 + 15/x. Created by Sal Khan.
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- What if you have a fraction in the equation that's like : 7/x-9 and the other side of the equation has -2/x, how would you work that out?(16 votes)
- You will cross multiply and then solve. To cross multiply, multiply the denominator on the left by the numerator on the right. Then do the same for the denominator on the right and the numerator on the left. These new expressions will be equal to each other. For your example, it will look like:
Distribute/multiply to get:
-2x + 18 = 7x
Add 2x to both sides to gather your variables:
18 = 9x
Divide both sides by 9.
2 = x(12 votes)
- I still don't completely understand so can some one please help P.S Please vote me i want that badge(17 votes)
- just multiply everything by that variable to cancel it out from the denominator and then solve for that variable(3 votes)
- What about this equation?
6/x + 3 = 12/2x + 1
We can try to solve it as usual:
Let's multiply both sides on x
6 + 3x = 12/2 + x
Then isolate x (subtract it from the both sides)
6 + 2x = 12/2
This is equals
6 + 2x = 6
Subtract 6 from the both sides
2x = 0
Divide by 2 both sides
x = 0
But we can't substitute zero instead of
xin the equation because it's impossible to have zero as denominator.
So should we care about exclusions for
xwhen it resides in denominator?(8 votes)
- Yes, you should care about exclusions for X. While your work created x=0, it is not a valid solution because it doesn't make the equation be true (both sides equal). Division by 0 is undefined.(6 votes)
- I got the right answer too when I added 10/x both sides of the equation.
- If 19=43+X what is the value of X(0 votes)
- The answer is negative 24, because 43+(-24)=19, or you can solve it by isolating the x, to do this, put the-equation X+43=19, subtract 43 from both sides so it will look like, (X+43)-43=(19)-43, so (x+43)-43 is X, (19)-43 is -24, so X=-24.
Hope this helps.(20 votes)
- In the video, Sal minused the 2x, but couldn't you also minus the 7x to? I(1 vote)
- Yes, you could have subtracted 7x rather than the 2x. If you prefer to work with positive numbers, then moving the 2x keeps the coefficient of x a positive value.(17 votes)
- What if the numerator on both sides is x and the denominator of both fractions does not have a common multiple? Could we still solve for x using this method or some other type?(4 votes)
- Why does multiplying x by 10/x get you 10? Is it because if u multiply you get 10x over x which simplifies into 10?(4 votes)
- Remember that "x" is really "x/1," just like 2 is 2/1.
Let's take a similar problem without variables: 2 • 3/2.
When you multiply 2 (or 2/1) by 3/2, you multiply numerator by numerator, and denominator by denominator. You end up with 6/2. When you reduce (or simplify), you divide both the numerator and the denominator by their GCF (greatest common factor). 6/2 = 3, and 2/2 = 1.
So you're left with 3/1, or 3.
Now look back at your original problem, x • 10/x. When you multiply (remember that x = x/1), you end up with 10x/x. Now we need to simplify. Obviously the only factor between the top and bottom is x, so we divide both the numerator and the denominator by x.
10x/x = 10, and x/x = 1,
so we're left with 10/1, or 10.(3 votes)
So I have the equation 7 minus 10/x is equal to 2 plus 15/x. And so this isn't the type of equation that you might think that you're used to solving. But I'll give you a few moments to see if you can solve it on your own. Well, what we'll see is we can do a quick multiplication of both sides to actually simplify this to a form that we are more used to looking at. So what's probably bothering you, because it's bothering me, is these x's that we have in the denominators right over here. We're like, well, how do we deal with that? Well, whenever we see an x in the denominator, the temptation is to multiply it by x. But we can't just multiply one of the terms by x. We have to multiply the entire side by x. So we could multiply this entire side by x. But we can't just multiply the left-hand side by x. We'd also want to multiply the right-hand side by x. And so what will that give us? Well, we distribute the x. We get x times 7 is 7x. And then x times negative 10/x, well, that's just going to be negative 10. So you get negative 10 right over there. So the left-hand side simplifies to 7x minus 10. And then your right-hand side, once again, distribute the x. x times 2 is 2x. x times 15/x, well, x times something over x is just going to be the something. x times 15/x is just going to be 15-- plus 15. So now we've simplified this to a linear equation. We have the variable on both sides. So we just have to do some of the techniques that we already know. So the first thing that I like to do is maybe get all my x's on the left-hand side. So I want to get rid of this 2x right over here. So I subtract 2x from the right-hand side. Now, and I always remind you, I can't do that just to the right-hand side. If I did it just to the right-hand side, it wouldn't be an equality anymore. You have to do that to the left-hand side as well. And so we are left with-- let me get that pink color again. On the left-hand side, 7x, 7 of something minus 2 of something, well, you're going to have 5 of that something, minus 10. These two x's negate each other. And you're left with equals 15. Now we can get rid of this negative 10 by adding 10 to both sides. You know, I like that green color when I do stuff to both sides. So I can add 10 to both sides. And I'm left with 5x-- these negate each other-- is equal to 25. And this is the home stretch. You see where this is going. We can divide both sides by 5. And we are left with x is equal to 5. Now let's verify that this actually worked. So let's go back to the original equation. We have 7 minus 10/5. This needs to be equal to-- I'm just taking our 5 and substituting it back here. This needs to be equal to 2 plus 15/5. So this is 7 minus 10/5. This is just 2. It needs to be equal to 2 plus 15/5, which is just 3. So 2 plus 3, 7 minus 2 is 5, 2 plus 3 is 5, 5 is indeed equal to 5. And we are done.