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### Course: Integrated math 2 > Unit 11

Lesson 13: Constructing a line tangent to a circle# Geometric constructions: circle tangent (example 2)

Sal constructs a line tangent to a circle using compass and straightedge.

## Want to join the conversation?

- How does the fact of line PC being a diameter of the circle make the triangle a right angle?(6 votes)
- This is a theorem for circles where any triangle that has its base on the circle's diameter and another point the circumference, it will form a right triangle. The proof for this theorem is in the link below.

https://www.khanacademy.org/math/geometry/hs-geo-circles/hs-geo-inscribed-shapes/v/right-triangles-inscribed-in-circles-proof(7 votes)

- Are there the exercises for this ?(5 votes)
- at2:24Sal said that "all the points on this circle are equidistant from c" and then later for point p as well but that doesn't seem to be correct because not all the points in a circle are equidistant from the centre only all the points on the CIRCUMFERENCE are. right?(2 votes)
- Listen again carefully to the video at2:24.

Sal says that all the points on the BLUE circle are equidistant from C and that all the points on the YELLOW circle are equidistant from P.

It's only the 2 points of intersection of the blue and yellow circles that are equidistant from both C and P (because the 2 circles have the same radius).(5 votes)

- Where is that "other video"?(3 votes)
- Image actually hanging that on a wall.(3 votes)
- how do i calculate the circle equation, if i only have the radius of the circle, and the tangent line to the circle - (the value of it)?(2 votes)
- So can I prove the supplementary angle rule in tangents through this constructions... Have a presentation tomorrow ....(2 votes)
- Can you also do that by making a circle with a radius equals to CP, then we center it at C and choose another point on the circle so C is equidistant from P and the other point meaning it sits on the perpendicular bisector and we draw the radius ??(2 votes)
- At0:36, didn't Sal say to go through point "P"?

Why did he add a point AT "P"?(2 votes) - Sadly Khan academy removed all the construction exercises because the straight edge or compass might poke someone's eye?(2 votes)

## Video transcript

- [Voiceover] Let's do another example of using a virtual compass
and virtual straight edge to draw a tangent line to a circle. And now we're told to
construct a line going through P tangent to the circle. And in this example, P
doesn't sit on this circle, P is outside of the circle. So we wanna draw something like, and actually let me get
my straight edge out. So my straight edge, and I
have my controls up here, this is on the Kahn Academy exercise Constructing a Line Tangent to a Circle, so I have that up there. So let me add the straight edge. Once again, you could try to eyeball it. We're gonna go through P, going
to be tangent to the circle, so hey yeah, maybe something like that. That looks pretty good,
but like we've said in other geometric constructions videos, that's just eyeballing it, we don't know how precise that actually is. So what if we had a compass
and a straight edge, how do we make something more precise? And actually in the process of doing it, we'll make really fun patterns. So how do we do that? Well, what I'm gonna do is, I'm gonna try to construct a circle that has the segment PC as a diameter. So let me draw that. So I wanna construct a circle that has segment PC as a diameter. And in order to do that, I need to figure out where the
center of that circle is. And you'll see in a second
why it's useful to have this circle that has PC as a diameter. So where is the center? It looks like it's roughly here, but how do we actually construct it? To do that, we're gonna have to figure out the midpoint of segment PC, or CP. And to do that, what I'm gonna do is construct two circles. I'll just make 'em a little bit larger. So one centered at C. I'll make it reasonably
large, maybe that big. Then I'm gonna construct another circle of the same radius as that large one that I just constructed, so it's that same radius. But I'm now going to center it at P. Now why is this interesting? Why is what I just did interesting? Well where these two
larger circles intersect are going to be equidistant to P and C. How do we know that? Well all the points on this
circle are equidistant to C, all the points on this
circle are equidistant to P, and these circles have the same radius. And at this point right over here, they are equidistant to both of them, because it sits on both circles. So this point is
equidistant to both of them, and so is this point right over here. And so they both sit on the perpendicular bisector of this segment. Of the segment CP. So actually let me draw that. So if I draw a line that
looks something like this, this right over here is
a perpendicular bisector of line, of segment CP. Now what we really just care about is that it is bisecting it, 'cause we wanted to find the midpoint. And now that we have found
the midpoint of our segment, we're ready to construct
that circle I talked about. A circle centered at the midpoint, and it has CP as a diameter. So I got that far, but
why did I go through all of this trouble to do that? Well now we're going to use the idea that if you have a triangle
embedded in a circle where one side of the
triangle is a diameter, then you're going to
have a right triangle. Well what am I talking about? Let me actually just draw the triangle. So let me add a straight edge here. So I'm gonna draw a triangle, so it has one side as the diameter, so we're gonna embed it in this circle that I just constructed,
this circle centered at this midpoint, this
circle right over here. CP is clearly our diameter. And I'm gonna embed it
in CP, but I'm gonna put it in this point right over here, 'cause this point sits on
the circle centered at C. And I'm gonna draw another line. So this other line, let me put
that there, and this there. So my claim is that this
is a right triangle. How do I make this claim, and I've proved it in other videos, is it's embedded in a circle, it's embedded in this
circle right over here that's highlighted in yellow. It has a diameter for one of its sides, and that side is actually its hypotenuse. So and we prove it in other videos. So this is a right triangle. Well why is this useful for proving, or why is this useful for
constructing a tangent line to this circle over here? To circle centered at C? Well, this side right over
here that I have in orange, that I'm highlighting right now, that's the radius of C. And if that forms the right angle with this line right over here, then this line right over
here must be tangent. And to really make it look tangent, I'll elongate it a little
bit just like that. And there you go. You feel good that this looks like it's truly intersecting at a right angle, and that this segment
that I'm highlighting in orange right now, is truly tangent. So once again, a lot more trouble than just eyeballing it and trying to draw it and actually,
a lot of you probably could have eyeballed this
segment right over here. But if you're doing
something on a larger scale, you wanna be more precise,
it's useful to be able to do these constructions. And frankly, while you're
in the process here, while you're dealing with the compass and the ruler or the straight edge, you get a new appreciation
for what these tools can do, and you're also making some pretty fun patterns and designs. I almost feel like hanging
this one up on my wall.