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### Course: Integrated math 3>Unit 1

Lesson 6: Special products of polynomials

# Polynomial special products: difference of squares

Dive into the exciting world of special products of polynomials, focusing on the difference of squares. We explore how to expand and simplify algebraic expressions. We also tackle more complex expressions, applying the same principles to make math magic happen!

## Want to join the conversation?

• Do we not need to write these in standard form? I was thinking these would be -25x^8+9 and -4y^10+9y^4
(9 votes)
• It's not "necessary" but it is what is usually done most of the time. Technically either way or any order is correct
(19 votes)
• Why would you not FOIL it? It seems that when you FOIL the problem vs just distributing you get completely different answers.
(3 votes)
• If you foil (x + y)(x - y), you'd get x^2 - xy + yx - y^2. xy and yx are the same thing, so you'd get x^2 - y^2. Hope this helped!
(15 votes)
• i found this tricky question this is as follow

Let N be least positive integer such that whenever a non-zero digit c is written after the last digit of N, the resulting number is divisible by c. The sum of the digits of N is

i really think hard but i can't get it please anyone solve this question step wise step so i can crack it
(3 votes)
• Putting 𝑐 at the end of 𝑁 gives us the number 10𝑁 + 𝑐

Dividing this by 𝑐 gives us
(10𝑁 + 𝑐)∕𝑐,
which we can write as
10𝑁∕𝑐 + 1

From this follows that if 10𝑁 + 𝑐 is divisible by 𝑐,
then 10𝑁 is also divisible by 𝑐.

Now we need to minimize 𝑁 for each possible value of 𝑐, and then find the least common multiple of those 𝑁's:

𝑐 = 1 ⇒ 𝑁 = 1
𝑐 = 2 ⇒ 𝑁 = 1
𝑐 = 3 ⇒ 𝑁 = 3
𝑐 = 4 ⇒ 𝑁 = 2
𝑐 = 5 ⇒ 𝑁 = 1
𝑐 = 6 ⇒ 𝑁 = 3
𝑐 = 7 ⇒ 𝑁 = 7
𝑐 = 8 ⇒ 𝑁 = 4
𝑐 = 9 ⇒ 𝑁 = 9

LCM(1, 2, 3, 4, 7, 9) = 2 ∙ 2 ∙ 3 ∙ 3 ∙ 7 = 252

So, the least positive integer 𝑁 is 252, which has the digit sum 2 + 5 + 2 = 9
(9 votes)
• So it would just be the same thing but expanded?
(3 votes)
• Yes, but the important thing is to notice the pattern when you have difference of squares
(7 votes)
• isn't the last question supposed to be y to the 25th power? are you supposed to multiply them or add them? because the first question sal did multiplication and the second sal did addition.
(3 votes)
• Ok so this might be a dumb question lol but... is the answer (3)^2-(5x^4)^2 or is the answer 9 - 25x^8 I understand both are equal but what I'm asking is which answer should I choose if I were actually doing this problem?? Sal probably specified that, but I didn't hear it and I just wanna be sure...
(0 votes)
• The answer is the second one. 3^2-(5x^4)^2 is the less simplified version, he just uses that to show all his steps and make it easier to understand. This first expression simplifies to 9-25x^8, as shown in the video, which is the correct answer. Always try to get as simple as possible.
(6 votes)
• What software and writing tool did you use to make these videos?
(1 vote)
• Who is Sal? Seeing as when a mistake is made they correct it and say it was Sal so who is he?
(1 vote)
• Sal Khan is the Co-Founder and Executive Director of Khan Academy.
(3 votes)
• what does sal mean by special products
(2 votes)
• Also, these are called conjugates, which are any algebraic expression with (a+b) (a-b), which can be (5+6) (5-6) all the way up to (5x^2+7x)(5x^2 -7x), as those were the types of conjugates shown in the video.
(2 votes)

## Video transcript

- [Instructor] Earlier in our mathematical adventures, we had expanded things like x plus y times x minus y. Just as a but of review, this is going to be equal to x times x, which is x squared; plus x times negative y, which is negative xy; plus y times x, which is plus xy; and then minus y times y. Or you could say y times a negative y, so it's going to be minus y squared. Negative xy, positive xy, so this is just going to simplify to x squared minus y squared. And this is all review. We covered it, and when we thought about factoring things that are differences of squares, we thought about this when we were first learning to multiply binomials. And what we're going to do now is essentially just do the same thing, but do it with slightly more complicated expressions. And so, another way of expressing what we just did is we could also write something like a plus b times a minus b is going to be equal to what? Well, it's going to be equal to a squared minus b squared. The only difference between what I did up here and what I did over here is instead of an x, I wrote an a; and instead of a y, I wrote a b. So, given that, let's see if we can expand and then combine like terms for, if I'm multiplying these two expressions. Say I'm multiplying three plus 5x to the fourth times three minus 5x to the fourth. Pause this video, and see if you can work this out. Alright, well, there's two ways to approach it. You could just approach it exactly the way that I approached it up here, but we already know that when we have this pattern where we have something plus something times that same original something minus the other something, well that's going to be of the form of this thing squared minus this thing squared. And remember, the only reason why I'm applying that is I have a three right over here and here, so the three is playing the role of the a. So, let me write that down, that is our a. And then the role of the b is being played by 5x to the fourth. So, that is our b right over there. So, this is going to be equal to a squared minus b squared. But our a is three, so it's going to be equal to three squared, minus, and then our b is 5x to the fourth, minus 5x to the fourth squared. Now, what does all of this simplify to? Well, this is going to be equal to, three squared is nine, and then minus 5x to the fourth squared. Let's see, 5 squared is 25. And then x to the fourth squared, well, that is just going to be x to the fourth times x to the fourth, which is just x to the eighth. Another way to think about it are exponent properties. This is the same thing as 5 squared times x to the fourth squared. If I raise something to an exponent and then raise that to another exponent, I multiply the exponents. And there you have it. Let's do another example. Let's say that I were to ask you, what is 3y squared plus 2y to the fifth times 3y squared minus 2y to the fifth? Pause this video, and see if you can work that out. Well, we're going to do it the same way. You could, of course, always just try to expand it out the way we did originally. But we could recognize here that, hey, I have an a plus a b times the a minus a b. So, that's going to be equal to our a squared. So, what's 3y squared? Well, that's going to be 9y to the fourth minus our b squared. Well, what's 2y to the fifth squared? Well, 2 squared is four, and y to the fifth squared is y to the five times two, y to the 10th power. And there's no further simplification that I could do here. I can't combine any like terms. And so, we are done here as well.