If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.

Main content

Surface integrals to find surface area


Suppose we have a plane P defined by the transformation T for minus, 2, is less than, u, is less than, 2 and minus, 1, is less than, v, is less than, 4.
T, left parenthesis, u, comma, v, right parenthesis, equals, left parenthesis, minus, 4, u, plus, 3, v, comma, 2, v, comma, u, plus, 2, v, right parenthesis
What is the surface area of P?
Choose 1 answer: