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# Function notation example

Sal uses function notation to help Frank figure out how much water he can put in his balloon. Created by Sal Khan.

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• At don't you multiply each of the terms by three to get 4 as a whole number, not divide?
• no because you would have to multiply the other side too and if you did that you would get the wrong answer
• why did he divide 27 by 3 at instead of 4 divided by 3?
• You are free to do it in which ever order is easier for you (as long as you observe PEDMAS).
In this example we have 3³=27 and 4/3.
If you did 4/3 first, then you would have to work with 1.33333333333 (inaccurate), or the mixed fraction "1 and 1/3" and multiply those by 27.

So now you have to multiply 27 by 1.33333333333 or "1 and 1/3" that to get the answer. Can you do that in your head?

Sal noticed that 27 is divisible by 3, that is 3x9=27, and with that he can simplify the expression by removing a factor of 3 from the 3 in 4/3 and 27 to get 4 and 9 to get 36 - easy to do in your head.

You also could have taken the factor of 3 out of 3³ and 4/3, to get 3² and 4 to get 9 and 4 to get 36 - also easy to do in your head.

So you can do it in the order that is easiest for you - the goal is always to reduce careless errors.
• besides just water balloons, where does function notation come in handy?
• Function notation in maths is analogous to the list of ingredients you get given in a recipe. It won't tell you how to make the cake but it will tell you what ingredients you'll need to get when you go shopping! It's used practically in physics, and is one of the key elements in computer programming. It's particularly useful when you're looking at messy relationships with multiple variables. as it provides a quick idea of which variables are important in determining something's value.
• How do you compute the area of a rectangle as a function of it's width given its perimeter.
• Let w denote the width and h the height of the rectangle in question. Given the perimeter P, we may write P = 2w + 2h. Hence h = P/2 - w. The area as a function of its width is then given by
A(w) = wh = w(P/2 - w).
• I'm not sure if I'm right...
So since this is a function, would the radius be the input/domain?
• hi, can someone help me with this problem I got? I don't know why my answer was wrong.
f(x)=-x-4. find f(-4)
a.0 (this was the correct answer)
b.-8 (this was the answer I got)
c. 4
d. 8
• In this case, you would simply need to plug in -4 into the equation. So, f(-4)=-(-4)-4. This equals zero because you have a negative times -4, which equals positive 4. Then, you subtract 4, which equals 0! I think you forgot about the negative. Let me know if this helps!
• I need help with evaluating functions
• At , why doesn't Sal solve 36(3.14)? Why does he leave it as 36Pi?