Main content
Precalculus
Course: Precalculus > Unit 1
Lesson 3: Invertible functionsDetermining if a function is invertible
Sal analyzes the mapping diagram of a function to see if the function is invertible.
Want to join the conversation?
Doesn't the first function not work, since it fails the vertical line test?(7 votes)
The vertical line test only works when you have a graph of a function within the coordinate plane.
In this video, the "graphs" are really just mapping tables/picture. The oval on the right has the input/domain values . The oval on the left has all the output/range values. Each arrow depicts a relationship between an input value and an output value. The way to determine if you have a function from these mappings is to see of any input value has more than one arrow.(15 votes)
So one-to-one functions are invertible. Many-to-one functions are not invertible. What about one-to-many functions, can that be possible? I presume many-to-one and many-to-many are NOT invertible.
And, what is the difference between range, co-domain, and image?(2 votes)
What you call a one-to-many function is not a function. A relation is only a function if each input has a single, definite output or set of outputs. Many-to-many relations are not functions for the same reason.
Many-to-one functions, like y=x^2 are not typically invertible unless we restrict the domain. So if we amend that we only want our outputs to be positive, we can invert y=x^2 to get y=√x. It's just that we will only get positive numbers.
And, codomain is the set of all possible numbers our function could map to. In high school, that's almost always the set of real numbers, R.
The image is the set of numbers actually mapped to. So the image of y=sin(x) is the interval [-1,1]. The image is always a subset of the codomain.
Range is a synonym for either image or codomain. Which one it's a synonym for varies between schools and people, but I think that in American high schools, it usually refers to the image.(7 votes)
So are all parabolas not invertible then? Since each "y" in the range would correspond to two "x"s in the domain?(1 vote)
Almost.
It is true that parabolas that open upwards or downwards are not invertible,
but parabolas that open left or right are invertible, since each "y" in the range would only correspond to one "x" in the domain.(3 votes)
How you determine if a function is invertible(1 vote)- A function is invertible if for each output value you have only one input value.(3 votes)
how do u solve the function f(x)=x^3 for proving that its an one-one function (i.e injective function)(1 vote)- Let's assume that it is invertible. If it is invertible let's try to find the form of the inverse. So we have:
f(x)=x^3=y or
x^3=y or
x=y^(1/3)
We state the function g(y)=y^(1/3). Since the symbol of the variable does not matter we can make g(x)=x^(1/3). If f and g are truly each other's inverse then f(g(x))=x for any x that belongs to the domain of g. Truly:
f(g(x))= (x^(1/3))^3=x^((1/3)*3)=x^1=x
So f is invertible. If f invertible it is also 1-1.(2 votes)
- 3:54so does this mean for a function to have a inverse, first it needs to be a linear(or if it's not linear, run a horizontal line(I don't know, I don't really know what it's called) then there can only be a single x value for a single y value) function so that for a single y value their can only be a single x value as well?
e.g. linear: y=3x+5
not linear(but single x for a single y): y=2^x +3(1 vote)- All non-horizontal linear functions are invertible, but a function does not need to be linear in order to have an inverse. There are many non-linear functions that are also invertible, such as exponential functions.
Formally speaking, there are two conditions that must be satisfied in order for a function to have an inverse.
1) A function must be injective (one-to-one). This means that for all values x and y in the domain of f, f(x) = f(y) only when x = y. So, distinct inputs will produce distinct outputs.
2) A function must be surjective (onto). This means that the codomain of f is equal to the range of f.
Any function that satisfies both of these conditions is called bijective and will always have an inverse.(2 votes)
What kind of functions would be like the not invertible ones in the video? Why would different inputs ever produce the same output?(1 vote)
As an example the y = x² function gives the same output (y) for x and -x. For instance (-4)² = 4² = 16.(2 votes)
help!!
determine if f(x) = x-1 (if x≥3), f(f(x+3)) (if x<3)
(ps. how will it look like if i drew f(f(x+3)) (if x<3) as a graph?)(1 vote)
The graph for f(f(x+3)) will be the same as the graph of f((x+3) - 1) which is same as graph of (x+2) - 1 which is the same as (x+1).(2 votes)
- How about determine if f (x) = 2x-3 has inverse fuctions(1 vote)
- As you can see the f(x) is a one-one function as it f(x) can only have value for each input given(value of x), and if x can take values from negative infinityto infinity then f(x) will also range from negative infinity to infinity(as infinity multiplied by or added by a integer makes no difference) therefore f(x) have the same co-domain and range which indicates that it is onto. And if a function is onto and one-one it is invertible.(1 vote)
- Is it possible to find the value of p if g(x)=-2x^2 + p, given that g(p)=-28.(1 vote)
I agree with KSeidel: when you solve p^2 - 0.5p - 28 = 0, you get (p+3.5)(p-4)=0(1 vote)
3:54Video transcript
- [Voiceover] "f is a finite function
whose domain is the letters a to e. The following table lists the output
for each input in f's domain." So if x is equal to a then, so if we input a into our function then we output -6. f of a is -6. We input b we get three,
we input c we get -6, we input d we get two,
we input e we get -6. "Build the mapping diagram for f
by dragging the endpoints of the segments in the graph below so that they pair
each domain element with its correct range element.
Then, determine if f is invertible." Alright, so let's see
what's going on over here. Let me scroll down a little bit more. So in this purple oval, this
is representing the domain of our function f and this is the range. So the function is going to, if you give it a member of the domain it's going to map from
that member of domain to a member of the range. So, for example, you
input a into the function it goes to -6. So a goes to -6, so I drag
that right over there. b goes to three, c goes to -6, so it's already interesting that we have multiple
values that point to -6. So this is okay for f to be a function but we'll see it might
make it a little bit tricky for f to be invertible. So let's see, d is points
to two, or maps to two. So you input d into our
function you're going to output two and then finally e maps to -6 as well. e maps to -6 as well. So, that's a visualization
of how this function f maps from a through e to members of the range but also ask ourselves 'is
this function invertible?' And I already hinted at it a little bit. Well in order fo it to
be invertible you need a, you need a function that could take go from each of these points to, they can do the inverse mapping. But it has to be a function. So, if you input three
into this inverse function it should give you b. If you input two into
this inverse function it should output d. If you input -6 into
this inverse function, well this hypothetical inverse function. what should it do? Well you can't have a function
that if you input one, if you input a number it could
have three possible values, a, c, or e, you can only map to one value. So there isn't, you actually can't set up an inverse function that does this because it wouldn't be a function. You can't go from input -6
into that inverse function and get three different values. So this is not invertible. Let's do another example. So here, so this is the same drill. We have our members of our
domain, members of our range. We can build our mapping diagram. a maps to -36, b maps to nine. c maps to -4, d maps to 49, and then finally e maps to 25. e maps to 25. Now is this function invertible? Well let's think about it. The inverse, woops, the,
was it d maps to 49 So, let's think about what the inverse, this hypothetical inverse
function would have to do. It would have to take each
of these members of the range and do the inverse mapping. So if you input 49 into
our inverse function it should give you d. Input 25 it should give you e. Input nine it gives you b. You input -4 it inputs c. You input -36 it gives you a. So you could easily construct
an inverse function here. So this is very much, this
is very much invertible. One way to think about it is these are a, this is a one to one mapping. Each of the members of the domain correspond to a unique
member of the range. You don't have two members of the domain pointing to the same member of the range. Anyway, hopefully you
found that interesting.