Making conclusions in a z test for a proportion

Antonia read an article that said $26\mathrm{\%}$‍ of Americans can speak more than one language. She was curious if this figure was higher in her city, so she tested $H_0:p=0.26$‍ vs. $H_{\text{a}}:p>0.26$‍, where $p$‍ represents the proportion of people in her city that can speak more than one language.

Antonia took a sample of $120$‍ people in her city found that $35\mathrm{\%}$‍ of those sampled could speak more than one language. The test statistic for these results was $z\approx 2.25$‍, and the corresponding P-value was approximately $0.01$‍. Assume that the conditions for inference were met.