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# Strong acid–strong base titrations

The results of an acid–base titration can be summarized using a titration curve, which plots pH vs. volume of titrant added. For the titration of a strong acid with a strong base, the curve begins acidic and then turns basic after the equivalence point, which occurs at pH = 7. For the titration of a strong base with a strong acid, the curve is similar except that it begins basic and turns acidic. Created by Jay.

## Want to join the conversation?

- What is titration?(2 votes)
- In the most general sense, titration is an analytical method to determine the concentration of an analyte in solution. An analyte is any specific chemical we are interested in and are analyzing. There are different types of titrations, but the most common is acid-base titration. In this type of titration, we want to calculate the concentration of an acidic or basic analyte solution by using an acid-base neutralization reaction.

Aside from the analyte solution which we want to know the concentration of, we also prepare a titrant solution. A titrant is a standard solution which we know the volume and concentration of prior. For example, if the analyte solution was an acid, then the titrant solution would be a base. We would add enough base titrant to the acid analyte until we reached the equivalence point which is where the entirety of the acid analyte is neutralized by the base titrant. We identify the equivalence point either with a pH meter or color indicators which changes the solution’s color during certain pH changes. At the equivalence point we know the moles of the base titrant must equal the moles of acid titrant in order for the two to neutralize each other completely so we indirectly know how many moles of acid were originally present. If we know the moles of acid, and the volume of the analyte solution prior to the start of the titration, we can calculate the concentration of the acid solution.

Hope that helps.(4 votes)

- Is there anything with a pH of 0?(1 vote)
- Well, ya. Mathematically we can figure that out. pH is defined as the negative logarithm of the hydrogen ion concentration, or pH = -log([H^(+)]). So if we have a pH of 0.

pH = 0 = -log([H^(+)])

0 = -log([H^(+)])

0 = log([H^(+)])

10^(0) = [H^(+)]

1 = [H^(+)]

Therefore we just need a solution with a hydrogen ion concentration of 1 M to get a pH of 0.

Hope that helps.(2 votes)

- when we are solving M1V1= M2V2

why isn't V2 considered the total amount of volume present?

so why isn't it:

x(100)= (.20M)(150) ?(1 vote)- Well, using the total volume would only make sense if we were doing a true dilution. We’re not really doing that here, it’s a neutralization reaction between sodium hydroxide and hydrochloric acid. Both of their concentrations will decrease as they neutralize each other until they both become zero at the equivalence point. So at the total volume at the equivalence point of 150 mL, we don’t actually have 0.20 M sodium hydroxide since it was all consumed by the hydrochloric acid.

Instead what the final concentration and volume are are the amount of the titrant solution added to the analyte. Essentially the moles of sodium hydroxide since volume multiplied by molarity yields moles. And we’re equating this titrant information with the initial concentration and volume which represents the amount of acid analyte present before the titration. Again volume multiplied by molarity of yields moles of hydrochloric acid initially present. We’re saying both the acid and base’s moles are equal to each other at the equivalence point.

So if we know the amount of moles of base needed to neutralize all the acid, we know the amount of moles of acid we originally had. And if we have moles of acid, then we can divide by the initial volume of the acid to find the initial concentration of the acid before the titration began; which is the point of the titration.

Hope that helps.(1 vote)

## Video transcript

- [Instructor] Hydrochloric
acid is an example of a strong acid and sodium hydroxide is an example of a strong base. Let's say we are titrating an unknown concentration
of hydrochloric acid with a known concentration
of sodium hydroxide. Let's say it's .20 molar. Because we know the concentration
of sodium hydroxide, we call that the titrant. And because we don't know the concentration of hydrochloric acid, we call that the analyte. And when our strong
acid, hydrochloric acid, reacts with our strong
base, sodium hydroxide, the products are an aqueous solution of sodium chloride and water. As a quick review of
how to write the overall or the complete ionic equation for a strong acid-strong base reaction, remember that sodium
hydroxide being a strong base dissociates completely in aqueous solution to form sodium cations
and hydroxide anions. Hydrochloric acid being a strong acid will ionize completely in aqueous solution to form H+ ions and chloride anions. Sodium chloride is a soluble salt, so an aqueous solution. We would have sodium
cations and chloride anions. And of course, we would also have water. When writing the net ionic equation, we cross out these spectator ions. So since we have sodium cations
in left and on the right, we can cross out the sodium cations and the same with the chloride anions. So both of those are the spectator ions. What we're left with is
our net ionic equation. So one way to write the net ionic equation for a strong acid-strong base reaction is hydroxide anions plus
H+ cations form water. And our goal for the strong
acids-strong based titration is to find the concentration
of hydrochloric acid using a titration curve. Let's say we do our titration and we come up with this
as a titration curve. For titration curves, you put the pH on the y-axis
and the titrant on the x-axis. So in this case, we're adding base to our
solution of hydrochloric acid. And before we use our titration curve to find the concentration
of hydrochloric acid, let's go through the titration curve and look at some particulate diagrams. And as we look at particulate diagrams, keep in mind they're just
to help us understand what's going on in the actual solution, so they're are just a representation. And we're also gonna
leave out water molecules for clarity purposes. So let's think about this
point on our titration curve. So that's zero milliliters of base added, meaning we're starting only
with hydrochloric acid. So there are two H+ particles, and there are two
chloride anion particles. Next, we add in some sodium hydroxide. So the sodium cation is this
purple sphere right here, and the hydroxide anion
is over here as well. So we add in some sodium hydroxide to our solution of hydrochloric acid and for the hydroxide
anion that's neutralized by one of the H+ ions that's present. So the OH- and the H+ react to form H2O. And since we're leaving H2O out
of our particulate diagrams, we don't see it in this
second particulate diagram. What we do see in this
second particulate diagram are the chloride anions
that were initially present. So here they are. And the other H+ ion that
was initially present and the added sodium cation. And since there's still an
H+ cation left in solution, we haven't neutralized all of the acid that was initially present. So next, we add some
more sodium hydroxide. So here we're adding a sodium cation, and we're also gonna
add this hydroxide anion to our solution. The added hydroxide
anion will be neutralized by the H+ ion that's already present. They will form water. And since we're leaving water out of the particulate diagrams, we don't see water in this
third particulate diagram. What we do see in our third
particulate diagram here are the two chloride anions
that have always been with us in the titration. We had one sodium cation already present, and then we added one more sodium cation. So this third particulate
diagram represents the equivalence point of our titration. All of the acid that we
initially had present has been neutralized by the added base and we're left with an aqueous
solution of sodium chloride. So there are only sodium cations and chloride anions in solution. At 25 degrees Celsius, the pH of water is equal to seven. And since neither the sodium cation nor the chloride anion will react with water to change the pH, the pH at the equivalence point of a strong acid-strong
base titration is seven. And we can find the equivalence
point on our titration curve by going over to a pH of about seven here. And if we draw a little dash line, wherever that dash line
hits our titration curve, represents the equivalence point. So the first particulate diagram was before any base was added. So that's this point
on our titration curve. The third particulate
diagram is meant to represent the equivalence point, so this point on our titration curve. And our second particulate diagram was when we haven't neutralized all of the acid that's present. So that's in between those two points on the titration curve. Also notice how steep the graph is around the equivalence
point of this titration. Therefore, adding very small amounts of base around the equivalence point causes large changes in
the pH of the solution. Let's go back to our particulate diagram at the equivalence point, and let's add some more sodium hydroxide. So we add one more sodium cation and one more hydroxide anion. This time, since there's no more acid to neutralize the added hydroxide anion, in our fourth particulate diagram, here's our hydroxide anion. And one of these sodium cations is the one that we just added. And we still have the chloride
anions and the sodium cations that were present at
the equivalence point. So this fourth particulate
diagram represents the titration after the equivalence point
when we're adding excess base. And we can see on our titration curve, as we continue to add excess
base, the pH keeps increasing. Now that we've gone through
the particulate diagrams for our strong acid-strong base titration, let's get back to our original problem which was to find the
initial concentration of hydrochloric acid. And we can do that by figuring out how many milliliters of base were added to get to the equivalence point. So if we just drop down
here on our titration curve, we can see that after
50 milliliters of base have been added, the equivalence point has been reached. Therefore, it took 50 milliliters of our .20 molar solution
of sodium hydroxide to completely neutralize the hydrochloric acid that
was originally present. And if we know the initial volume of the hydrochloric acid solution, let's say it was 100 milliliters. We can calculate the concentration using the MV is equal to MV equation. So for our equation, let's think about acid
being on the left side. So we don't know the
concentration, the molarities, we make that x. And for the volume of the acid, it's 100 milliliters. So we plugged that into our equation. On the right side, let's think about this being the base. So we know the molarity of the base, it's .20 molar. And we also know the volume of base that was necessary to
reach the equivalence point which is 50 milliliters. Solving for x, we find that
x is equal to .10 molar. So that was the initial concentration of our hydrochloric acid solution. And notice on our titration curve, remember we started with
only hydrochloric acid. So we start with a very low pH if we're titrating a strong
acid with a strong base. As we add more and more
of the strong base, the pH increases. We've just looked at the titration curve of a strong acid with a strong base. Let's compare that
titration curve to this one which is the titration of a
strong base with a strong acid. Since we're starting with a strong base, notice how the initial pH is very high. And since we're adding acid
notice down here on the x-axis, it now says milliliters of acid added. As acid is added, we can see the pH dropping slowly. And as we approach the equivalence point, we see a large drop in pH
with small additions of acid. However, the pH at the equivalence point is still equal to seven. So if we find a pH of seven on the y-axis and go over to our titration curve, this point represents
the equivalence point. And we can drop down to the x-axis and we would see it took
20 milliliters of acid to neutralize the base
that was initially present. Finally, once we go past
the equivalence point, we can see as we add more and more acid, the pH keeps getting lower. So this titration curve of a
strong base with a strong acid is essentially the reverse of the first titration curve that we saw which was the titration of a
strong acid with a strong base.