Introduction to titration
Titration is a procedure for determining the concentration of a solution. And so let's say we're starting with an acidic solution. So in here let's say we have some hydrochloric acid. So we have come HCl. And we know the volume of HCL, let's say we're starting with 20.0 milliliters of HCl. But we don't know the concentration right? So question mark here for the concentration of HCl. We can find out that concentration by doing a titration. Next we need to add a few drops of an acid base indicator. So to this flask we're also going to add a few drops of an acid base indicator. We're gonna use phenolphthalein. And phenolphthalein is colorless in acid but turns pink in the presence of base. And since we have our phenolphthalein in acid right now we have a clear solution. There's no color to it. Up here we're gonna have our standard solution right? We're gonna have a known concentration of sodium hydroxide. So let's say we have a solution of sodium hydroxide and the concentration is zero point one zero zero molar. And we're ready to start our titration. So we allow the sodium hydroxide to drip into our flask containing our HCl and our indicator. And the acid in the base will react, right? So we get an acid base neutralization reaction. HCl plus NaOH right? If we think about the products, this would be OH minus, this would be H plus, H plus and OH minus give us H2O. And our other product we would have Na plus and Cl minus, which give us NaCl, or sodium chloride. So let's say we add a certain volume of base right? So now this would be higher, and we see our solution turn light pink. Alright so let's say we see our solution turn light pink and it stays light pink. That means that all of the acid has been neutralized by the base. And we have a tiny amount of excess base present, and that's causing the acid base indicator to remain pink. So a tiny excess of base means we've neutralized all of the acid present. And where the indicator changes color, this is called the end point of a titration, alright? So when our solution changes color, that's the end point of our titration. And here we stop and we check and see the volume of base that we used in our titration. So if we started right here, if we started with that much base, let's say we ended down here, alright? So we still have a little bit of base left. And this would be the volume of base that we used in the titration. Alright so we have a change in volume here, and let's say that it's 48.6 milliliters. So it took 48.6 milliliters of our base to completely neutralize the acid that we had present. And so we can now calculate the concentration of the HCl. Alright so let's go ahead and do that, and let's start with the concentration of sodium hydroxide. Alright we know that we started with point one zero zero molar solution of sodium hydroxide. So point one zero zero molar. And molarity is equal to mols over liters. Alright so this is equal to mols over liters. And our goal is to figure out how many mols of base that we used to neutralize the acid that was present. Alright so we can take our volume here, 48.6 mililiters and we can convert that into liters. Alright so just move your decimal place three places to the left. So one, two, three. So that's point zero four eight six liters. So this is equal to mols over zero point zero four eight six liters. And so let's get some more space. Alright let me just rewrite this really quickly. Zero point one zero zero is equal to X over zero point zero four eight six. So we're just solving for X, and X represents the mols of sodium hydroxide that were necessary to neutralize the acid that we had present. Alright so when you solve for X, you get zero point zero zero four eight six mols of sodium hydroxide used in our titration. Next you look at the balanced equation for what happened . So if I look at my balanced equation alright there's a one here and there's a one here. So we have a one to one mol ratio. And the equivalence point is where just enough of your standard solution has been added to completely react with the solution that's being titrated. And at the equivalence point, all of the acid has been neutralized. Right? So it's completely reacted. And since we have a one to one mol ratio, if I used this many mols of sodium hydroxide, that must be how many mols of HCl that we had present in our original solution. So therefore, I can go ahead and write that I must have had zero point zero zero four eight six mols of HCl present in the flask before we started our titration. Right and I knew that because of the one to one mol ratio. Remember our goal was to find the concentration of HCl. The original concentration. And concentration, molarity is equal to mols over liters. So now I know how many mols of HCl I had, and my original volume of HCl was 20 milliliters right? So right up here we had 20 milliliters. So I need to convert that into liters. So I move my decimal place one two three. So I get point zero two liters. So now our final step here to calculate the concentration of HCl, right so the concentration of HCl is equal to how many mols of HCl we have, which is zero point zero zero four eight six mols, over liters of solution. And we had 20 milliliters which is equal to zero point zero two zero zero liters. Alright so now we can take out our calculator and do this calculation to find the concentration of HCl that we started with. Point zero zero four eight six, all right and we're gonna divide that by point zero two zero zero. And we get zero point two four three for our answer. So the concentration of HCl is equal to zero point two four three molar. So we've solved for the original concentration of HCl. There's a shortcut way to do this problem, and the shortcut way would be to do the molarity times the volume of the acid is equal to the molarity times the volume of the base used. So MV is equal to MV. So let's say we have the acid over here on the left, and the base over here on the right. So the molarity of the acid is what we're trying to find. So I'll just make that X. The volume of the acid that we started with, you can just leave this in milliliters if you want, 20 point zero milliliters is how much of the acid we started with. And for the base, we knew the concentration of the base that we used in our titration right? It was zero point one zero zero molar. And we also knew the volume of base that we used to completely neutralize the acid. We used 48.6 milliliters. And notice how the mLs would cancel out here. Right and we can just go ahead and do the math and solve for X. So we get out the calculator, and we need to multiply 48.6 times point one zero zero. Alright and so we get four point eight six obviously. And then if we divide by 20 we will get our answer of zero point two four three. So X is equal to zero point two four three molar. And this shortcut way works pretty well when you're dealing with a strong acid and a strong base and a one to one molar relationship. Alright in the next video we'll do a problem where the mol ratio is no longer one to one.
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