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AP®︎/College Chemistry
Buffer capacity
The definition of buffer capacity, and an example showing why it depends on the absolute concentrations of the conjugate acid and base.
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- Athow do you get the value that [A]/[HA]=1.82? 2:25(29 votes)
- in the previous video this process is explained. But [A]/[HA]= 10^pH-pKa. She gave an example PH=5, and then we were able to find the pKa from the Ka value she provided. Pka=4.75. So 10^5-4.75=1.82(13 votes)
- So the buffer capacity simply depends on the concentrations [AH] and [A-], higher both concentrations are, higher is the buffer capacity is?(11 votes)
- Why do you have to use the henderson-hasselbach equation instead of calculating pH normally? Does it have to do with how the buffers behave?(6 votes)
- For buffer#2, what would happen if the [HA] concentration had been exactly 0.04M? You would have been left with 0M left for [HA]. The ratio of [A^-] to [HA] would be 0.13/0 and since you can't divide by zero, what would the pH change then be?(7 votes)
- In these simple buffer problems we assume that ALL of the added H+ or OH- reacts with the buffer components [A-] or [HA]. Well, this is not that straightforward. Actually, this assumption works only when the amount of added H+/OH- is much smaller than the amount of buffer components.
I.e. is your set up with 4M of {HA} and 4M {OH-] added, our assumption that 100% of [OH-] reacts with [HA] will simply not work: not all of the [OH-] will react and the solution of the problem won't be that simple.
That's why in all the model buffer problems it's important to note that the about of acid/base added is small compared to the amount of buffer components.(2 votes)
- Can someone help me with this question. 'What is the maximum amount of the acid that can be added to a buffer made by the mixing of 0.35 moles of sodium hydrogen carbonate with 0.50 moles of sodium carbonate? How much base can be added before the pH will begin to show a significant change?'(2 votes)
- It depends on what you mean by "a significant change".
The buffer capacity is defined as the amount of acid or base you can add without changing the pH by more than 1 pH unit.
I will define "significant change" as 1 pH unit.
The equation is
HCO₃⁻ + H₂O ⇌ H₃O⁺ + CO₃²⁻
*(1)* pH = pKₐ + log([CO₃²⁻]/[HCO₃⁻]) = pKₐ + log(0.50/0.35) = pKₐ + 0.155
If we add x mol of base until the pH increases by 1 unit, we have
*(2)* pH + 1 = pKₐ + log[(0.50+x)/(0.35-x)]
Subtract (1) from (2)
1 = log[(0.50+x)/(0.35-x)] - 0.155
1.155 = log[(0.50+x)/(0.35-x)]
(0.50+x)/(0.35-x) = 10^1.155 = 14.29
0.50+x = 14.29(0.35-x) = 5.00 - 14.29x
15.29x = 4.50
x = 4.50/15.29 = 0.294
∴ We can add 0.294 mol of base before the pH changes by 1 unit.
Check:
New pH = pKₐ + log(0.794/0.056) = pKₐ + 1.152
Old pH = pKₐ + 0.155
ΔpH = 1.152 - 0.155 = 0.997 ≈ 1(5 votes)
- hello, Im wondering if it's possible to compare buffer capacity of two totally different buffers with different initial pH?(2 votes)
- Is there a way to say a buffer has x buffer capacity or everything is just relative?(1 vote)
- Yes, buffer capacity is a specific number in moles.(2 votes)
- At, why can't I make a buffer solution whose concentration is greater than 1 M ? 10:21(1 vote)
- You definitely can.
I didn't hear Yuki say you can't, just that 0.1-1.0 M is a good range.
One possible problem with higher concentrations is that you might run into solubility problems.
You also can start having issues where the concentration is no longer a good approximation for the activity, which is what actually matters for most calculations. This makes doing calculations for concentrated solutions much more difficult.
See below for details:
http://www.chemicalforums.com/index.php?topic=2578.0
And much more detail:
https://chemistry.stackexchange.com/questions/65367/when-can-i-use-concentration-instead-of-activity(1 vote)
- I was wondering what would happen to the buffer capacity if the buffer concentration was dilutes 10 times less(1 vote)
- The buffer capacity would decrease as the concentration of its ions would decrease.(1 vote)
- Then how about a buffer range? What is it? Is it the same as buffer capacity? Thanks!(1 vote)
Video transcript
- [Voiceover] Let's talk
about buffer capacity. Buffer capacity is a property of a buffer and it tells you how much acid or base you can add
before the pH starts changing. Basically, as your buffer capacity goes up, which I'm going to abbreviate BC, as your buffer capacity goes up, you can add more of your acid or base before the pH starts changing a lot. That might seem like a pretty vague and qualitative definition,
so let's go through an example to see what that might look like exactly. The example we're gonna look at is going to be using
an acetic acid buffer. So acetic acid is CH three COOH. And we're gonna abbreviate
that in this talk using HA. And this is an aqueous solution and that is reversibly reacting to form H plus ion and CH three COO minus, or acetate. And so we're gonna abbreviate
acetate in this talk as A minus. So more information about
this particular buffer. Acetic acid, the Ka is equal to 1.8 times 10 to the minus five. And if we take the negative log of that, that will give us the pKa, which is also useful. And the pKa of acetic acid is 4.74. So that'll tell us a lot about
the behavior of this buffer. And the last thing we need to know for predicting the behavior of our buffer is what the ratio is
between our HA and A minus. So we're going to be
looking at a buffer where A minus over HA, this ratio, is equal to 1.82. Based on this ration,
we can calculate the pH. So the initial pH of our buffer before we do anything to it, before we add any acid or we add any base, the initial pH of our
buffer we can calculate using the Henderson–Hasselbalch equation. And so that equation tells
that pH is equal to pKa plus log of A minus concentration, or acetate, over acetic
acid concentration. And if you're not 100% confident
with using this equation, or you want to know where it comes from, we actually have separate videos on it, so I would recommend checking those out. In this video, we're just going
to use this equation as is. So if we plug in our values here, we get that the initial pKa is equal to 4.74, our pKa, plus log of 1.82, which is our ratio of A minus over HA. So then we know our initial pH is equal to 5.00. What we're gonna do next
is we're gonna look at two different buffers, and both of them are going
to be made with acetic acid and with acetate. And we're gonna call them
buffer one and buffer two. So buffer one has a ratio of A minus NHA that is 1.82. So the pH is going to be five. And the A minus concentration, before we do anything to it, before we add anything, is 0.90 molar. And the HA concentration is going to be 0.49 molar. And our second buffer that
we're gonna compare it to we will call buffer two. And buffer two also has the
same ratio of acid to base, except this time both concentrations are gonna be 10 times
smaller than buffer one. So our A minus concentration
is 0.090 molar. And our acetic acid
concentration is 0.049 molar. And what we're gonna do
here is we're gonna see what happens to the pH of both of these, So they both start out with a pH of five, but how much do they change when we add... We're going to add 0.04 moles of a strong base, sodium hydroxide, to one liter buffer. So when you do that, well it's a buffer. We know that it's going
to resist the pH change, but what exactly is happening? What's the reaction that
goes on when you add this in? So when you add your strong base, which is going to
dissociate to form OH minus, it's going to react with
the acid in your buffer. So our acid is CH three COOH. And we always assume that a strong base is going to react irreversibly. So one-sided arrow with a weak acid. So what happens is this proton is going to react with OH
minus and we're gonna get H two O, or water. And we're gonna make CH three COO minus. So that's our base. And so we can see that the hydroxide is going to react one to
one with our weak acid and it's gonna produce one
equivalent of our base. So now we can use this information to calculate what happens to our buffer when we add .04 moles of sodium hydroxide. What's gonna happen is it's gonna react with our acid. Which means the concentration
of the acetic acid is gonna go down by .04 molar. Our new concentration after it's reacted is gonna be 0.45 molar. Sorry, I tried to do that in my head. And what happens to our
concentration of the base? Remember that when the acid
reacts with sodium hydroxide we actually make more base, So we have to adjust the
concentration of A minus upward. It actually makes .04 molar acetate when this reaction happens. So our new concentration
of our acetate ion is 0.94 molar. So these are our final concentrations. We can no plug them back in to the Henderson–Hasselbalch
equation to get the pH. So the pH of buffer one, I'll put a little subscript one, is going to be 4.74, the pKa, plus log of 0.94 molar divided by 0.45 molar. And if we plug that into our calculator, we get that the pH after
we add that hydroxide is 5.06. So it's a little bit higher. It went up by .06. That makes sense. We do imagine it would be higher. If you add base, it becomes more basic and the pH should go up. But it didn't change a whole lot, because it's a buffer. Now let's compare that with
what happens to buffer two. We add .04 mole sodium
hydroxide to buffer two. Our acetic acid concentration
is gonna go down by .04 molar. So our new concentration
of HA is .009 molar. By the same reaction,
our base concentration is gonna go up, since when the acid reacts,
it makes more conjugate base. So we're gonna have to add 0.04 molar to A minus concentration. And so the new concentration
is going to be 0.13 molar. And we can plug those concentrations into the Henderson–Hasselbalch equation and we get that pH of our buffer two is equal to 4.74, our pKa, plus log of 0.13 molar divided by 0.009 molar. And so that would be, if we
plugged this into our calculator this is equal to 1.16. So if we add that together with our pKa, we get that the new pH is 5.90 molar. So the pH changed a whole lot more for buffer two than for buffer one. The pH went up by .9 instead of by .06. So if we were comparing
the buffer capacities of both of these buffers, we would say that buffer one, well, the buffer changes less when you add the same amount of acid or base. So buffer one has the
higher buffer capacity. Since you don't want these concentrations, A minus and HA, to be too low, the general rule of thumb is that you want your concentrations of HA and A minus between 0.10 molar and 1.0 molar. And by following that rule of thumb, you can make a buffer where you don't have to worry too much about adding too much acid or base before you pH changes, since that's usually why
you're making a buffer in the first place.