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## High school physics - NGSS

### Course: High school physics - NGSS>Unit 4

Lesson 3: Predictions using energy

# Calculating height using energy

Learn how you can calculate the maximum height of a launched object by using the total energy of a system. Energy that is conserved can be transferred within a system from one object to another changing the characteristics of each object, like position. Created by Sal Khan.

## Want to join the conversation?

• Okay so this is more of a math question than a physics question, but I'm hoping someone here can help me out.

For one of the quiz questions, I came up with the equation:

1/2*1200N/m*Δx^2=1/2*0.43kg*(15m/s)^2+0.43kg*9.8m/s^2*Δx

How would I solve for Δx with it being raised to the first power on one side and the second power on the other side of the equation?

I took Algebra 1 a while back so maybe I learned this and then forgot (I'm reviewing it now). I haven't had any trouble with this course yet. Do I need Algebra 2 or any other math classes to continue with it?
(1 vote) • Howdy Ryan,

Remember that any if we have any variable x raised to a power b, multiplied by that same variable raised to different power c, then the result will be x raised to b + c.
e.g.: x^b * x^c = x^(b + c)

For division, you do exactly the opposite. Instead of adding the exponents, you subtract.

So if you divided Δx by both sides of the equation, you would be left with Δx^2/Δx = Δx on the left-hand side and Δx/Δx = 1 on the other side.