Hi! The work = change in energy equation here is confusing me. Is that work energy theorem? Does work equal change in total energy, or only change in kinetic energy? I've also seen something about how work done by the non-conservative forces is change in energy? Are these all correct, and just reiterations of the same principle? What is the relationship between them? It's different everywhere I look and one source never seems to address the equation given in the other sources. Thanks!

The Work Energy theorem states, work equals the change in kinetic energy. Also, from the Conservation of Energy equation, Ki+Ui+Wext=Kf+Uf, if you rearrange it, you get Wext=ΔE (total).

In the Common Mistakes section, should it be cos90 = 0 ?

Yes you can write as cos 90=0 by rounding. But it is preferably used as -1. The exact value is equal to -0.44807361612.

why does negative sign means that it is giving energy to its surrounding? is the sign not for our ease only?..(i mean we assume that object moving toward left is negative and toward right is positive.)

When work is negative, the force on the object is the opposite direction of the direction it is moving, so we can assume the object is slowing down. This kinetic energy must be going somewhere. So it is possible the energy is going to the object's surroundings, but it could also be going to potential energy. Work is not a vector. It can be positive or negative the way temperature can be positive or negative. It is not an arbitrary convention.

Main content

Class 11 Physics (India)

Course: Class 11 Physics (India) > Unit 10

Lesson 1: Introduction to work

Introduction to work review

Google Classroom

Review the key concepts and skills for energy and work. Understand how work is the area under a force vs. displacement graph and how force and displacement produce work.

Key terms

Term (symbol)	Meaning
Energy ( $E$ ‍)	Measurement of the ability to do work. SI unit is joule ( $J$ ‍).
Work ( $W$ ‍)	Change in energy by the transfer of energy from one system to another. Scalar quantity with units of joules ( $J$ ‍).
Joules ( $J$ ‍)	SI unit for energy. Applying a net force of $1 N$ ‍ to an object over a displacement of $1 m$ ‍ requires $1 J$ ‍ of energy. $1 J = 1 N \cdot 1 m = 1 kg \cdot \frac{m^{2}}{s^{2}}$ ‍

Equations

Equation	Symbol breakdown	Meaning in words
$W = F d \cos θ$ ‍	$W$ ‍ is work done on an object, $F$ ‍ is the magnitude of force on the object, $d$ ‍ is the magnitude of the object’s displacement, and $θ$ ‍ is the angle between the vectors of force $F$ ‍ and displacement $d$ ‍.	Work is the product of an object’s displacement and the component of force exerted parallel to the direction of the object’s motion.
$W = Δ E$ ‍	$W$ ‍ is work and $Δ E$ ‍ is the change of energy.	Work is the change of energy for a system.

How to find work from a Force vs. displacement graph

The force applied to an object can be graphed as a function of the position of the object. Work is the area under the curve of the force vs. position graph. Areas above the position axis are positive work and areas below the axis are negative work. If the force is not constant, we can divide the graph into sections with simpler shapes and add up the work in each section. To find the total work done on the object in the force vs. position graph in Figure 1 over displacement

d_{1} + d_{2}

, the areas of

A_{1}

and

A_{2}

can be added together.

Figure 1. Work is the area under a force vs. displacement graph. This graph can be analyzed as two separate areas.

A_{1}

is a rectangle of height

F_{o}

and width

d_{1}

A_{2}

is a triangle of height

F_{o}

and base

d_{2}

. The total work done on the object over

d_{1} + d_{2}

\begin{aligned} W_{t o t a l} & = A_{1} + A_{2} \\ = F_{o} d_{1} + \frac{1}{2} F_{o} d_{2} \end{aligned}

For worked examples of finding work from a force vs. displacement graph, watch our video about calculating work from force vs. displacement graphs.

Common mistakes and misconceptions

1) People forget that forces acting perpendicular to displacement do zero work. Since

\cos 90^{\circ} = 0

, no work occurs when force

F

and displacement

d

are perpendicular even though a perpendicular force can change the object’s direction of motion. For example, if a box is pulled across the level floor, the floor does zero work on the box even though the box is moving. This is because the normal force is perpendicular to the horizontal displacement of the box.

2) People forget what the sign of work means. Positive work on a system means it receives energy from its surroundings. Negative work on a system means it gave energy to its surroundings. Negative work occurs when the force has a component in the direction opposite the displacement.

Learn more

For deeper explanations of work, see our video with example problems about work.

To check your understanding and work toward mastering these concepts, check out the exercises in this tutorial: work from force vs. position graphs and calculating work from a force.

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Alice
Posted 6 years ago. Direct link to Alice's post “Hi! The work = change in ...”
Hi! The work = change in energy equation here is confusing me. Is that work energy theorem? Does work equal change in total energy, or only change in kinetic energy? I've also seen something about how work done by the non-conservative forces is change in energy? Are these all correct, and just reiterations of the same principle? What is the relationship between them? It's different everywhere I look and one source never seems to address the equation given in the other sources. Thanks!
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(6 votes)
Answer
- Zyce
  Posted 6 years ago. Direct link to Zyce's post “The Work Energy theorem s...”
  The Work Energy theorem states, work equals the change in kinetic energy. Also, from the Conservation of Energy equation, Ki+Ui+Wext=Kf+Uf, if you rearrange it, you get Wext=ΔE (total).
  Comment on Zyce's post “The Work Energy theorem s...”
  (7 votes)
shreya31dps
Posted 5 years ago. Direct link to shreya31dps's post “why does negative sign me...”
why does negative sign means that it is giving energy to its surrounding? is the sign not for our ease only?..(i mean we assume that object moving toward left is negative and toward right is positive.)
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(1 vote)
Answer
- Alexander Wu
  Posted 5 years ago. Direct link to Alexander Wu's post “When work is negative, th...”
  When work is negative, the force on the object is the opposite direction of the direction it is moving, so we can assume the object is slowing down. This kinetic energy must be going somewhere. So it is possible the energy is going to the object's surroundings, but it could also be going to potential energy.
  
  Work is not a vector. It can be positive or negative the way temperature can be positive or negative. It is not an arbitrary convention.
  Comment on Alexander Wu's post “When work is negative, th...”
  (7 votes)
Quang Ngoc
Posted 4 years ago. Direct link to Quang Ngoc's post “In the Common Mistakes se...”
In the Common Mistakes section, should it be cos90 = 0 ?
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(3 votes)
Answer
- Aniruddha.K.Mulgund
  Posted 3 years ago. Direct link to Aniruddha.K.Mulgund's post “Yes you can write as cos ...”
  Yes you can write as cos 90=0 by rounding. But it is preferably used as -1. The exact value is equal to -0.44807361612.
  Button navigates to signup page
  (2 votes)
IZH1
Posted 3 years ago. Direct link to IZH1's post “Why don't you, when you h...”
Why don't you, when you have a slanted force vector, break the vector down into its parallel and perpendicular parts, and then use the part that is parallel with the direction of motion in your work equation, instead of using the magnitude of the force?
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(3 votes)
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Zoe LeVell
Posted 3 years ago. Direct link to Zoe LeVell's post “Why do joules not account...”
Why do joules not account for differentiating surface frictions?
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(2 votes)
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- Sukhada
  Posted 4 months ago. Direct link to Sukhada's post “Friction in engines and m...”
  Friction in engines and machines contributes to energy loss, which is what wears out the parts in a car (hence the need for lubricating oil). Friction is a non-conservative force, meaning energy is transferred to new forms not useful to the system (but doesn't disappear from the universe, see conservation of energy).
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  (1 vote)
sanchudan
Posted 4 years ago. Direct link to sanchudan's post “If a body is diagonally i...”
If a body is diagonally in air we have to take k.e or p.e to find work done
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(2 votes)
Answer
- Sukhada
  Posted 4 months ago. Direct link to Sukhada's post “Depends- is it attached t...”
  Depends- is it attached to a string, or is it falling down?
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  (1 vote)
Victor Chavez
Posted 10 months ago. Direct link to Victor Chavez's post “When do you find the area...”
When do you find the area under the force vs distance graph to find work and when do you simply use the formula w=Fd?
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(1 vote)
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spedghost
Posted 18 days ago. Direct link to spedghost's post “no no no no no no”
no no no no no no
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(1 vote)
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Vector Inc.
Posted 3 years ago. Direct link to Vector Inc.'s post “I know how to use simple ...”
I know how to use simple shapes to find the area under functions on position vs. time graphs, but how could we use calculus to find the work for a function that might have fluctuating values of work? I already know calculus, and that integrals would be needed here, but I'm interested to see an actual application of them. What would the bounds look like, and how would we go about solving it?
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(0 votes)
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ucheoma emelonye
Posted 3 years ago. Direct link to ucheoma emelonye's post “how do you know whether o...”
how do you know whether or not to do addition or subtraction and how do you graph work
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- firdaus
  Posted 3 years ago. Direct link to firdaus's post “if the area is under the ...”
  if the area is under the x-axis, so then it will be negative. we just add all the work to get net work, but since it is negative work ( which means the force is opposite with the direction ) , it will look like subtraction because W+(-W)=W-W
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  (0 votes)