How to name bicyclic compounds. Numbering the chain and Identifying bridgehead carbons. Created by Jay.
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- At about10:00, couldn't you name the molecule 2,8-dimethylbicyclo[3.2.1]octane, because you can start from the closer bridgehead carbon instead of the one in the back?(27 votes)
- I like your thinking. If we were naming non-bicyclic compounds, you definitely would want the lowest number on each substituent. However, when naming bicyclic compounds, you must start at the bridgehead and move toward the largest ring. In this case the ring with 3 carbons and not 2 (or 1 for that matter). Notice that Jay does pick the numbering system with the lowest number possible (6 rather than 7).(48 votes)
- Shouldn't it be ''norborNane'' instead of "norborane"(11 votes)
- I checked your wiki reference and it says that Norbornane is also known as bicyclo[2.2.1]*hept*ane.rather than bicyclo[2.2.1]*oct*ane. Thanks for providing the link.(11 votes)
- What is the difference between bicyclo[4,2,1]octane and bicyclo[4,2,1]nonane? If the three variables in the bracket  are determined, I think the total number of carbons in the compound is also determined. Namely, if bicyclo[x,y,z]-ane, the total number of the compound is x+y+z+2. Am I wrong here?(9 votes)
- You are correct. There is no such compound as bicyclo[4.2.1]octane.(7 votes)
- 9:43. Looking at the bicyclo on the left...why couldn't you start from the bridge carbon and then go left and make the 6th carbon into the second? I'm guessing Counting on the longest carbon chain takes precedence over having the methyl on a lower carbon?(6 votes)
- Correct. Counting on the longest carbon chain takes precedence over having the methyl on a lower numbered carbon. But if the 6-methyl had been on C-7, the name would still be 6,8-dimethylbicyclo[3.2.1]octane. We would still start numbering by going around the largest bridge, but we would use the numbering in the crossed-out structure in order to get the lowest numbers.(5 votes)
- How exactly would you know where to "cut" to find out how many rings there are or is?(2 votes)
- Cut any place you want, as long as you do not create two separate pieces.(4 votes)
- can compounds exist with only 1 bridgehead carbon, i.e. can two (or more) cyclic compounds be
joined on their vertices to form a new compound?(2 votes)
- Spiro compounds have only one bridgehead carbon. For some pictures, see http://en.wikipedia.org/wiki/Spiro_compound(4 votes)
- Don't the methyl groups contain 1 carbon each
and instead of octane it will become decane?(2 votes)
- The base name counts the carbon atoms in the rings (8), so the base name is bicyclooctane.
The methyl groups are substituents, so the molecule is a dimethylbicyclooctane.(4 votes)
- How would you go about naming a molecule with multiple bridges or rings. For example, with 3 bridges across a 10 carbon ring system?(2 votes)
- This is easier to explain with diagrams and seeing examples. I'd recommend checking out p 27 of this pdf: http://goo.gl/Ea2wCB(2 votes)
- Hi I don't understand how you name the bicyclo compound 4-2-0
I know that you counted from the left excluding the bridgehead, and that number came to the number 4--what is the next longest chain? and then the shortest chain?(1 vote)
- The next longest is to the right...from the carbons he labels 1-8-7-6 (2 atoms in the chain excluding the bridgehead carbons), and the shortest is between carbons 1 & 6 (0 atoms including the bridgehead carbons)(3 votes)
- why is it needed to cut to make an open chain alkane?(2 votes)
- It seems like an arbitrary thing that might help you see how many rings there are. I’ve never see it before this video.(1 vote)
In the last few videos, we looked at the different conformations of cyclohexane. And obviously, cyclohexane is just one ring, so it'd be a monocyclic compound. The official IUPAC way of telling how many rings you have is how many cuts does it take to make an open chain alkane? So if I just made a cut between those two carbons, I have an open chain alkane. And it took me one cut to get there. So obviously, cyclohexane is monocyclic. What about if I had a cyclohexane ring, and then I had another ring fused to it like that? Obviously, there are two rings here, so this would be a bicyclic compound. Once again, if you were to use the IUPAC way of figuring out how many rings you have, you would make a cut here and a cut here, and now you have an open chain alkane. So it took you two cuts to get there, so you would classify this as a bicyclic molecule. Now, these are very easy, simple compounds. But for more complicated compounds, you'll need to remember that IUPAC rule to figure out how many rings you actually have. Let's go ahead and redraw that second molecule here. And let's look at it in some more detail. So I had a cyclohexane ring, and then I had another ring fused to it like that. Now, the carbons that are shared by both of these rings, so this carbon and this carbon, those are called your bridgehead carbons. Let's go ahead and write that. The bridgehead carbons. And when you're numbering your bicyclic compounds, you want to start at the bridgehead carbon, then number along the longest path, then the second longest path, and then finally the shortest path. So let's go ahead and do that. Let's start with the top bridgehead carbon. We'll make that number 1. And we're going to number along the longest path, so the longest path would be going left. So that's 1, 2, 3, 4, 5, and 6. And now, the second longest path. Well, we can just continue, and there'd be 7 and 8 since that's the second longest path. The third path, the shortest path, is usually the one between your bridgehead carbons. And there are no carbons between our bridgehead carbons. So we're done in terms of numbering our compound. The general formula for naming a bicyclo compound-- we've already determined this is a bicyclo compound, so you would have bicyclo here. And then in brackets, you would put the number of carbons in the longest path excluding the bridgehead carbon, which I will represent here with x. And then y is the number of carbons of the second longest path, excluding the bridgehead carbon. And then z is the number of carbons in the shortest path, excluding the bridgehead carbon. And then you finish everything off with the alkane. So how many carbons are there in this molecule? So for this example, let's go ahead and name it. We've already determined that it's a bicyclic compound, so we'll go ahead and write bicyclo here. And x, again, is the number of carbons in the longest path, excluding the bridgehead carbon. So we're going to find the longest path, which is on the left here, and we're going to ignore the bridgehead carbon. How many carbons where there? 1, 2, 3, and 4. So we'll go ahead and put a 4 here. y was the number of carbons in the second longest path. Well, that was over here where we had this carbon and this carbon. Again, excluding the bridgehead carbon. So that would get a 2. And finally, the shortest path, which was how many carbons are there between my bridgehead carbons. And there are, of course, 0 carbons between my bridgehead carbons. So if there's 0 carbons between your bridgehead carbons, obviously your bridgehead carbons are bonded directly together, which we can see in the dot structure. Finally, how many carbons are there total? There are 8, and we know that means octane. So the final name for this molecule is bicyclo[4.2.0.]octane. Let's do another one following our general formula here for naming a bicyclo compound. So let's take a cyclohexane ring. And let's make this a bridgehead carbon. And we're actually going to put a carbon between our bridgehead carbons like that. Now, this is hard to see when it's drawn this way. So usually, you'll see it drawn a little bit differently. Usually you'll see it drawn with a little bit more three-dimensionality to it. So hopefully we can do that here. So it looks something like this. So let's find our bridgehead carbons here. So we know that this is a bridgehead carbon, this is a bridgehead carbon. Those correspond to these guys over here. And how many cuts would it take to turn this into an open chain alkane? Well, let's go ahead and look at the drawing on the left. And if we cut it right here, and we cut it here, we can see it's now an open chain compound. So it took two cuts, so it's bicyclo. Let's go ahead and put those bonds back in there like that. So it's a bicyclo compound. So we can go ahead and start naming it as a bicyclo compound. We need to go ahead and number it, so let's start with our bridgehead carbon. So we'll start with this is our bridgehead carbon. Find the longest path. Well, it doesn't matter if I go left or right here, since it's the same length each way around. So I'll just go to the right. So 1, 2, 3, 4. Second longest path, so I'm going to keep on going this way, so 5 and 6. And then finally, the shortest path, which is the one carbon in between my two bridgehead carbons, which would then get a 7, so seven total carbons. All right, so when I'm naming this, I need to put my brackets in here. And I put the number of carbons in the longest path, excluding the bridgehead carbon here. So how many carbons were my longest path, excluding the bridgehead? Here's 1 and here is 2, so I'm going to go ahead and put a 2 in here. And then I go to my second longest path. Well, that was over on this side. And there are also two carbons on my second longest path. Obvious, it's the same length as the other one. So it's 2, 2. And then my shortest path, how many carbons are there in my shortest path, not counting my bridgehead carbon? There's one. So I go ahead and put a 1 here. And so I have bicyclo[2.2.1]. And then my total number of carbons is 7. So this is a bicycloheptane molecules. So bicyclobicyclo[2.2.1]heptane would be the official IUPAC name for this molecule. This molecule turns up a lot in nature. So much so, that it actually has its own common name. This is also called norborane. So let's go ahead and write that here. So this is norborane, again, a structure found often in nature. All right, let's do one more example here. And let's make it look similar to that norborane molecule. So we'll have it go like this. So it definitely is a little bit tricky to draw these molecules here. So let's put some substituents on this molecule. So I'm going to attempt to draw the same molecule over here. And we're going to take a look at two different ways to number it and see which one turns out to be correct. So here I have the exact same molecule on both sides here. And let's see how to do this. So let's first find our bridgehead carbons. So here are my bridgehead carbons right here. Now, when I start numbering, I could start at either one of those bridgehead carbons. So if I identify my bridgehead carbons over on this one, I could start numbering with either of these be number one. So let's just make this number 1 here. So if that's number 1, I next go to my longest path. So that would be going to the right here. So this would give me a 2 for this carbon, a 3 for this carbon, a 4 for this carbon, a 5 for this carbon. Next, the second longest path. Well, I can just keep going, make that a 6, make this a 7. And then finally, my shortest path, which is up here at the top. So that would be 8 total carbons for my parent name. On the dot structure on the left, again, the exact same dot structure. This time, I'm going to start with the opposite bridgehead carbons. So I'm going to start with this bridgehead carbon. And then follow the same rule. So the longest path, which would be to the right here. So 2, 3, 4, 5, 6, 7, and then 8. So which one of these numbering systems is the correct one? Remember, our goal is to get the lowest number possible for our substituents. And if I look at the example on the right, I have a methyl group in the 7 position and a methyl group in the 8 position. The example on the left has a methyl group in the 6 position and a methyl group in the 8 position. Since I want to give my lowest number possible to my substituent, I'm going to not number it the way on the right. So I'm going to go with the way on the left here. So let's go ahead and start naming it. We already know this is a bicyclo compound. And we have two methyl groups, one at 6 and one at 8. So we could start naming it by saying 6,8-dimethyl. And then we know this is a bicyclo compound, so bicyclo. And then in the brackets, we're going to do the longest path first, excluding the bridgehead carbon. So the longest path is on the right. How many carbons are there in the longest path? There are three excluding the bridgehead carbon, so we'll go ahead and put a 3 in here. Next, the second longest path, excluding the bridgehead carbon. Well, that was these two right here. So next, there'll be a 2. And then finally, the shortest path excluding our bridgehead carbon. There's only one carbon in our shortest path. So we put that in there. And then, there were 8 total carbons, so it is octane. So the final IUPAC name for this molecule is 6,8-dimethylbicyclo[3.2.1.]octane.