Introduction to UV/Vis spectroscopy and how this technique is used to analyze molecules with electrons in pi orbitals and nonbonding orbitals. Explore this through a sample analysis of the absorption spectrum of 1,3-Butadiene, discussing the concept of molecular orbitals and the energy difference between the highest occupied molecular orbital (HOMO) and the lowest unoccupied molecular orbital (LUMO). It also explores how energy and wavelength are inversely proportional. Created by Jay.
Want to join the conversation?
- Why do we only consider transitions for pi electrons? Is it because they are relatively easier to excite??(13 votes)
- At5:09, why did only ONE electron get moved into the higher excited state?(5 votes)
- Recall, that light has wave like properties and particle like properties AKA (photons). As light slams into the pie electron it is acting as a particle much like slamming marbles together. The KE of the photon is transfered to the pi electron causing it to jump to a higher energy state, thus ONE photon of light for ONE pie electron of the bond. Also, remember that this compound is conjugated which means in this particular case that there are 4 possible orbits for the electrons to travel too depending on their specific energy levels at a given time. They jump back and forth as energy leaves and comes in. With more energy there is a higher calling to jump to the LUMO (Lowest UNOCCUPIED molecular ORBIT). Hope this helps...(11 votes)
- If 1-3 butadiene absorbs in the UV region, it absorbs UV light, but won't it reflect other colors then and therefore not be colorless?(8 votes)
- Not necessarily, if the compound only has effect on UV light then it neither absorbs nor reflects visible light (like most amorphous substances). Also if the compound absorbs a photon it will usually then release that energy shortly after, the released photon will most likely be a wavelength in the UV spectrum.(5 votes)
- What are bonding and anti bonding molecular orbitals?(3 votes)
- Molecules have many different molecular orbitals with different energies.
If we start with empty orbitals and start adding electrons, they will go into the lowest-energy orbitals available. These are the bonding orbitals.
Each orbital can hold only two electrons, so the orbitals get higher in energy but are still bonding.
Eventually, we will reach orbitals where the addition of an electron neither increases nor decreases the energy of the molecule. (Think of lone pairs, which are nonbonding.
Once these orbitals are filled, the remaining one are so high in energy that adding an electron deceases the stability of the molecule. These are the antibonding orbitals.(13 votes)
- From9:10to9:30, why do nonbonding electrons have more energy than bonding electrons?(4 votes)
- Bonding electrons are between two nuclei. This is a low-energy situation.
Lone pairs are attracted to only one nucleus. This is a higher-energy situation.(7 votes)
- at9:42, why are there only two non-bonding electrons? Aren't there four?(2 votes)
- Yes, there are two nonbonding orbitals, and each contains two electrons.
He is just talking about an n→π* transition from one of these orbitals.(7 votes)
- I've seen lambda(subscript)VIS max before on science journals. What does this mean?(2 votes)
- It's usually written as λ_(max).
The VIS means that the spectrum was measured over the wavelengths of visible light (roughly 400 – 700 nm).
λ is the symbol for the wavelength of the light.
And max refers to the wavelength that had the greatest (maximum) absorption of the light.
The basic form of phenolphthalein has λ_max = 553 nm (green).
It preferentially absorbs green light, so we see the unabsorbed wavelengths , which are mostly in the red region.(5 votes)
- Why do we choose the wavelength of the highest absorption to do the experiment ?(2 votes)
- You could use any wavelength, but using the wavelength with the highest absorption will give you the least uncertainty in your measurement.(2 votes)
- How do uv camera or black lights work.(1 vote)
- UV cameras use light in the near UV region (200 – 380 nm). Special filters block the visible and IR wavelengths and let the UV through. The lenses are made of quartz or fluorite, because glass is opaque to UV. Film or digital sensors respond to the UV hitting them in the normal way.
A black light looks dark purple, but most of the light it emits is in the ultraviolet (UV) range.
Under a UV light, white clothes and UV paints emit a bright glow. They all contain phosphors — substance that absorb UV energy and re-emit it as visible light.(3 votes)
- Min10:30>> What is the experimentally observed UV/Vis spectrum of ethanal, given that Jay mentions two wavelengths, ~180nm and ~290nm? Does the spectrum have two peaks? Or is it a mixture of the two? Thank you(1 vote)
- There are two peaks.
The intense peak at ~180 nm corresponds to the transition of a π electron to an antibonding π orbital.
A much weaker peak at ~290 nm corresponds to the transition of a lone pair electron on O to an antibonding π orbital.(2 votes)
- [Voiceover] Different molecules can absorb different wavelengths of light and if a molecule happens to absorb light in the ultraviolet or the visible region of the electromagnetic spectrum we can find the wavelength or wavelengths of light that are absorbed by that compound by using a UV/Vis spectrophotometer. Now essentially what that does is it shines light with a range of wavelengths. The wavelengths range from approximately 200 nanometers all the way up to 800 nanometers. We shine that range of wavelengths of light through a sample of the compound and you get an absorption spectrum. Here is an absorption spectrum for this molecule, for 1,3-Butadiene. Now if we look over here we can see that this molecule absorbs most strongly right about here and if we drop down we can see what wavelength of light is absorbed most strongly by the compound. And we see that's just under 220 nanometers. It turns out out to be 217 nanometers. We call this lambda max. The wavelength of light absorbed by this molecule is about 217 nanometers. It absorbs in the UV region therefore Butadiene does not have any color, it's colorless. Let's look at the dot structure a little bit more carefully here. We have four carbons and all four of these carbons, each one is sp2 hybridized. Which means each one of those carbons has a p orbital. So we're talking about four p orbitals here or four atomic orbitals. And when you're dealing with molecular orbital theory, four atomic orbitals recombine to form four molecular orbitals. Two bonding molecular orbitals and two antibonding molecular orbitals. Let's go over here and let's look at the four molecular orbitals and we're going to focus in on the left side first. The bonding molecular orbitals are lower in energy than the antibonding ones. So this orbital and this orbital, these are our bonding molecular orbitals here and this one and this one are the antibonding molecular orbitals. And you can see energy, right? So energy is increasing and so the antibonding molecular orbitals are higher in energy. Let's look at the dot structure again for Butadiene and let's see how many pi electrons we have. So here are two pi electrons and here are two pi electrons. So a total of four pi electrons. When you're thinking about molecular orbitals, you can think about electron configurations. So we have four electrons and where do we put those electrons? We're going to put them in the lowest energy orbitals first. And we're also going to pair our spins. So four electrons, we're going to put two into this bonding molecular orbital and we paired our spins. And then two into this bonding molecular orbital. So the four pi electrons go into the bonding molecular orbitals when you're talking about the ground state. So here's the ground state of Butadiene. So next we shine light on Butadiene and the molecule's going to absorb energy from the light. Let's look at that here, so there's a difference in energy between the orbitals and in particular we're concerned about these two orbitals right here so there's a difference in energy between these two orbitals. This orbital down here, this is occupied by electrons and it's higher in energy than this orbital. So this is the highest occupied molecular orbital. So highest occupied molecular orbital or HOMO. This orbital right here is unoccupied. The antibonding molecular orbital right now is unoccupied and it's lower in energy than this antibonding molecular orbital. So this is the lowest unoccupied molecular orbital. When you're talking about a molecule absorbing energy, we're considered about the HOMO, the highest occupied molecular orbital and the LUMO, the lowest unoccupied molecular orbital. The energy difference between those two orbitals is what we're thinking about. So the molecule absorbs energy and a pi electron absorbs energy from the light and is promoted to a higher energy level. Let me go ahead and write over here. Now we're talking about the excited state so we shine light on the molecule. This is the excited state of Butadiene and these two pi electrons stay there. One of these pi electrons stays here and one of the pi electrons absorbs the energy from the light and is promoted to a higher energy level. So I'm saying this one right here was promoted to a higher energy level. It goes from the HOMO to the LUMO and it had to absorb a specific amount of energy in order to do that. So it had to absorb the right amount of energy in order to make that transition. We know that energy came from the light and we also know the energy of a photon of light is equal to h, where h is Planck's constant, times the frequency of light which is new. Over here for the absorption spectrum, we have everything in wavelengths so we need to write the energy in terms of a wavelength. We know that the frequency of light and the wavelength of light are related by the speed of light is equal to the wavelength times the frequency. The frequency is equal to the speed of light over the wavelength and we can take that, frequency is equal to c over lambda, and plug it into here. Now we have the energy, the energy is equal to h times c over lambda. This is really important; energy and wavelength are inversely proportional to each other. You can think about one wavelength giving you a specific amount of energy. This energy difference between the HOMO and the LUMO corresponds to a wavelength and if we go over here to the absorption spectrum for Butadiene we're talking about a wavelength of 217 nanometers. At first it might be a little bit confusing because it looks like we have a very broad range of wavelengths that are absorbed here. Don't worry about that too much, this just results from the different vibrations and rotations of the molecule which can change the energy differences slightly and so we don't see one exact wavelength, we end up seeing this broad band of wavelengths being absorbed here. So what you do is, you just look for the one that's absorbed most strongly and think about that as being the wavelength that corresponds to the energy difference between these two orbitals here. So that's how to think about it. Let's look at another molecule here, instead of Butadiene let's look at this molecule, so we have ethanal. Here is our dot structure and if we look at this molecule we know we have two pi electrons here for ethanal. So two pi electrons. We know that those electrons are going to go into the bonding molecular orbital. So let me draw a line right here on this diagram. This is our bonding molecular orbital down here. We're talking about two pi electrons. Let's put in our two pi electrons into here. Let me just go ahead and change colors up here. Up here is our antibonding molecular orbital which we call pi star. So there is an energy difference between the bonding molecular orbital and the antibonding molecular orbital. This is delta E and we talked about the fact that this corresponds to a certain wavelength of light. Ethanal can have, when it promotes one of these pi electrons up, it can have a pi to pi star transition. So the molecule is going to absorb energy and the energy-- Let me use a different color here. The energy corresponds to a wavelength of light so this energy difference between our two orbitals. It turns out that this pi to pi star transition is approximately 180 nanometers which is below the range of what you're usually measuring when you're using a UV/Vis spectrophotometer. But we have another possibility here too. Let me go ahead and highlight a lone pair of electrons here on the oxygen. We have a lone pair so we have non-bonding electrons. Non-bonding electrons occupy a non-bonding orbital which is actually a little bit higher in energy than our bonding molecular orbital. So another possibility, we call this n right here. This is a non-bonding orbital so non-bonding orbital here. And we can put some electrons into that orbital. So we put those two electrons into the non-bonding orbital. And we can have a different type of transition. We're still talking about a pi star, an antibonding molecular orbital right here. We can have a n to pi star transition. We can have a n to pi star transition as well since we have a carbonyl compound. We're not just talking about pi electrons here. We can think about a non-bonding electron here. And let's think about this energy difference. This energy difference is smaller than before. So this energy difference is smaller than this energy difference. What would happen to the wavelength of light that's absorbed? If we have a smaller energy difference, energy and wavelength are inversely proportional so this must be a longer wavelength. So this absorbs light at a different wavelength, a higher wavelength, and it turns out to be-- Let me go ahead and change colors here. So this energy transition corresponds to a wavelength of light that's approximately 290 nanometers. This n to pi star transition, a smaller difference in energy corresponding to a higher wavelength. This is an important concept. As you decrease the energy difference between your orbitals, you're going to increase the wavelength of light that's absorbed. We'll talk much more about that in the next few videos because that's where the idea of color comes in.