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Organic chemistry
Course: Organic chemistry > Unit 5
Lesson 5: Sn1 and Sn2- Identifying nucleophilic and electrophilic centers
- Curly arrow conventions in organic chemistry
- Intro to organic mechanisms
- Alkyl halide nomenclature and classification
- Sn1 mechanism: kinetics and substrate
- Sn1 mechanism: stereochemistry
- Carbocation stability and rearrangement introduction
- Carbocation rearrangement practice
- Sn1 mechanism: carbocation rearrangement
- Sn1 carbocation rearrangement (advanced)
- Sn2 mechanism: kinetics and substrate
- Sn2 mechanism: stereospecificity
- Sn1 and Sn2: leaving group
- Sn1 vs Sn2: Solvent effects
- Sn1 vs Sn2: Summary
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Intro to organic mechanisms
Identifying electrophiles and nucleophiles. Showing movement of electrons using curved arrows.
Want to join the conversation?
- AtIs chlorine a leaving group in this scenario simply because the attacking group is more electronegative than chlorine? 2:32(9 votes)
- Would someone please remind me why (at) the electron pair shifts first to the carboxylate oxygen and then back to reform the double bond to kick out the Cl- rather than the Cl- just leaving as the carboxylate attacks the carbonyl carbon of acetyl chloride? 3:59(4 votes)
- It's just a formalism really. When we get more experience we will show that all happen in one step.(5 votes)
- where did the Lithium go 11:00(2 votes)
- It just stayed in solution as lithium ions and is a spectator so it isn't important to know anything about the lithium in the reaction other than the fact that it became lithium ions.(5 votes)
- Chlorine is a nucleophile as well, right? because it is an are of high electron density. Why then is the assumption that O attacks the carbon and not that the Cl attacks the H?(3 votes)
- Generally, the weaker the conjugate base, the better the leaving group. Since CL- is a weaker conjugate base than O will ever be (because HCL is a strong acid), it more readily becomes a leaving group than oxygen.(1 vote)
- Around, why can't oxygen leave as a leaving group as oxide (2- ion)? 8:17(1 vote)
- The oxide anion is extremely reactive. It will bond with anything, even fluorine to form an oxygen fluoride, 3 of which are known according to Wikipedia. Oxygen doesn't normally bond with fluorine despite the electronegativity difference but the oxide anion will. So yeah, adding the oxide anion to fluorine will oxidize the oxygen but anyway, the oxide anion will bond to anything to become neutral and stable. It could react with the hydrogen ions to form water, it could bond to the carbon again, it could react with the acid itself and bond with it, it could react with the glass in the container.
So yeah, a very reactive anion is a very bad leaving group, even worse than a peroxide anion or hydroxide. Even fluoride is a better leaving group than the oxide anion.(4 votes)
- How many electrons does it take for an atom to have a negative one formal charge?(1 vote)
- It depends on the element.
Formal charge = valence electrons - lone pair electrons - number of bonds
If a carbon atom has 1 lone pair (=2 lone pair electrons) and 3 bonds it will have a -1 formula charge
FC = 4 - 2 - 3 = -1
But if nitrogen has the same it has a formal charge of 0
FC = 5 - 2 - 3
And if oxygen has the same it has a +1 formal charge
FC = 6 - 2 - 3 = +1(3 votes)
- AtWhy is it that oxygen tends to take back it's electrons to reform a carbonyl group? 5:32(2 votes)
- At around, would the carbon anion attack H3O+ forming an alcohol and water instead of attacking the carbon on the benzene group? I suppose the H3O+ groups are more in the solvent so that the chance it meet carbon anion is higher. 7:30(1 vote)
- Hydronium is the solution the whole reaction is occurring in.(2 votes)
- Example two: For the first step: How do we know the δ- C attacks the δ+ C shown, rather than the δ- O attacking the δ+ Li, or either one of the δ- atoms attacking the hydronium?(2 votes)
- Can a molecule act as both a nucleophile and an electrophile, as per the requirement?(1 vote)
Video transcript
- [Instructor] In the last
video, we learned about nucleophiles and electrophiles. And in this video, we're gonna look at some simple organic chemistry mechanisms and learn to identify the
electrophiles and nucleophiles and also think about how to show the movement of electrons
during a mechanism. Remember from general chemistry that mechanisms show the steps by which a reaction occurs, and so, for this reaction, let's look at this alkyl
halide on the left here. We know that chlorine
is more electronegative than this carbon, so the chlorine is going to
withdraw some electron density away from that carbon, which
makes it partially positive. From the last video, we know that since this carbon is partially positive, this is the electrophilic
center of this compound. If we look at hydroxide ion,
which we could have gotten from something like sodium hydroxide, we know that this
negatively charged oxygen would be the nucleophilic portion. So hydroxide is gonna
act like a nucleophile, and this carbon on our alkyl halide is gonna act like an electrophile. We know that opposite charges attract, so the negatively charged oxygen is going to be attracted to the partially positively charged carbon
on the alkyl halide. And we say that the nucleophile
attacks the electrophile, so I could draw a curved arrow showing the movement of two electrons over here to this carbon. At the same time, these two electrons come off onto the chlorine. So the chlorine had three lone
pairs of electrons around it, let me go ahead and draw those in. We're gonna add in an extra
lone pair of electrons, and let me highlight those
electrons in magenta. So these two electrons
come off onto the chlorine, so I'll make these this pair. And that gives the chlorine
a negative one charge, so this is the chloride anion and we call this a leaving group. So we're gonna form a
bond between the oxygen and this partially positive carbon, so let me say that this lone
pair of electrons on the oxygen is gonna form a bond between
the oxygen and that carbon. So, on our product, on this alcohol, those two electrons must be
these two electrons right here in this bond that formed. So that's a simple organic
chemistry mechanism. We had only one step,
the nucleophile attacked and the leaving group
left, all in the same step. The goal is not to
understand every single thing about this organic chemistry mechanism in great detail right now. Our goal right now is just to appreciate how nucleophiles and electrophiles are used in organic chemistry mechanisms and start to get a feeling
for how these curved arrows show the movement or flow of electrons. Let's look at another
organic chemistry mechanism, and we're gonna start by identifying our nucleophile and our electrophile. So let's look at this compound first. We know that oxygen is more
electronegative than carbon, so this oxygen is going to
withdraw some electron density from this carbon. And this chlorine is
gonna do the same thing because chlorine is more
electronegative than carbon too. So this carbon is
electron deficient, right, it is partially positive, and that can act as an electrophile. On the right, we have the acetate anion, which could come from sodium acetate, and this oxygen has a
negative one formal charge, so the oxygen is the nucleophilic center of our acetate anion. And our acetate anion
can act as a nucleophile. Opposite charges attract, so this negatively charged oxygen is attracted to this
positively charged carbon. And we can say that the nucleophile
attacks the electrophile and I draw a curved arrow to show the movement
of these two electrons. Now, I can't show a bond directly from this oxygen to this carbon until I take these pi electrons
and move them off onto the top oxygen here because remember, carbon can never exceed an octet of electrons around it. So let me draw the movement of
all of those electrons here. So let's draw, let's draw everything in. So we now would have an
oxygen at the top here with three lone pairs of electrons, which give this oxygen a
negative one formal charge. So if I'm showing movement of electrons, I'm saying that two electrons from here moved off onto the oxygen, which gives it a negative
one formal charge. I still have this chlorine
attached to this carbon, so let me draw in that chlorine down here. So this had three lone pairs
of electrons around it. And now we formed a new bond, right, we formed a bond between this oxygen and this carbon. And let me highlight these
two electrons in red. So those two electrons in red form a bond between that oxygen and this carbon, and this oxygen still has
two lone pairs of electrons around it like that. And now let's draw in the
rest of this over here, so we have a carbonyl,
so let me draw that in, put in my lone pairs of electrons. And then, we have a methyl
group coming off like that. So the first step of this mechanism is a nucleophilic attack, so
let me write first step here. The nucleophile attacks the electrophile. And it turns out this
is a two step mechanism, and in the second step of this mechanism, we're gonna get loss of a leaving group. So let's say a lone pair
of electrons on this oxygen moves back in to reform a carbonyl, but we cannot exceed an octet
of electrons to this carbon. So that must mean that these two electrons come off onto chlorine, come
off onto our leaving group, which would be the chloride anion. Let me draw in those electrons here, which gives the chlorine
a negative charge. So the electrons in, let's make them, let's make them blue here, so these electrons in blue
come off onto the chlorine to form the chloride anion,
which is our leaving group. So we get loss of a leaving group and we reform our carbonyl, which gives us our final product. Again, don't worry too much about the details of the mechanism. Our goal is to identify our
nucleophile, electrophile and appreciate our electron flow and start to think about
different steps of a mechanism. Nucleophilic attack is a very common one, so is loss of a leaving group. Let's look at one more
organic chemistry mechanism. We're gonna start by
identifying our nucleophile and our electrophile. Let's look at this compound first. We know that oxygen is more
electronegative than this carbon so the oxygen is going to
withdraw some electron density away from that carbon,
which makes this carbon partially positive. So that's the electrophilic
center of this compound. In the first step, we're
adding propyl lithium, and we know that carbon is more electronegative than lithium. So carbon's gonna pull these
two electrons closer to it, giving this carbon a
partially negative charge. Or since the electronegativity
difference is so great, we can take those two
electrons in that bond and put them on that carbon. So we have three carbons
here, and let me draw them in, and we have two electrons on that carbon. Let me highlight those
electrons in magenta. So these two electrons in magenta go onto that carbon here, which gives this carbon a
negative one formal charge. And we have a carbanion. Since we have a negatively charged carbon, this carbanion is an
excellent nucleophile, and this is going to attack
the electrophilic portion that we already identified. So opposite charges attract and the negative charge is
attracted to the positive charge. And in the first step of our mechanism, our nucleophile attacks our electrophile. Now, we can't just show a
bond between those two carbons because that would give 10
electrons around this carbon, right, that would exceed
an octet of electrons. So we have to show some
electrons going somewhere else. We can take these two electrons and move them off onto our oxygen. So in our first step, our nucleophile attacks our electrophile, and we form a carbon-carbon bond. So we also have an oxygen here with three lone pairs
of electrons around it, which give it a negative
one formal charge, so we can follow some of those electrons, let me make them blue here. So these electrons come
off onto our oxygen, giving the oxygen a
negative one formal charge. I'm going to form a bond
between our two carbons, and this is where people
get messed up a little bit because counting carbons
can sometimes be difficult. We need to account for three
carbons on our nucleophile, and we also are going to form a bond. So if you look at our product over here, it gives us a clue as to how to draw that. We have three carbons,
one, two, and three, and the electrons in magenta
are forming this bond in here. So let's go ahead and draw
that on our intermediate. Alright, so we have our
three carbons accounted for, let me highlight those,
so one, two, and three. And then, the electrons in
magenta, right, these electrons form a bond between this
carbon and this carbon, so the electrons in magenta form a bond between those two carbons. This is our intermediate. So our first step is nucleophilic attack. In the second step, we have
a source of protons here. So I'm using the hydronium ion, so let me draw that in really fast. So we have H three O plus, so positive formal charge on the oxygen. And the second step of this mechanism is acid-base chemistry. It's a proton transfer. This negatively charged
oxygen on our intermediate acts as a base and takes a proton. So let's say it's this
lone pair of electrons takes a proton from H three O plus, leaving these electrons
behind on the oxygen. So let me highlight
those electrons in red, so these electrons in red
are gonna take this proton. So let's say that the electrons
in red form this bond, and here was the proton that we took. So we form an alcohol as
our final product here. Again, our goal is just to appreciate nucleophiles and electrophiles, and this is a reaction that
comes much later in the course. The last thing that I wanted
to talk about in this video is something I'm calling
the Schwartz principles. And Dr. Schwartz was my
organic chemistry professor in college, and he was by far the best teacher that I've ever had. One day, he said to me, "Organic chemistry is only five things." You need to know valence electrons. You need to understand electronegativity. You need to know your acid-base chemistry. You need to know about oxidation-reduction reactions, or redox. And finally, you need to understand nucleophiles and electrophiles. Let's go back to that previous mechanism and see how it actually has all five of the Schwartz principles. First, let's talk about valence electrons. So when we're showing these
curved arrows in our mechanisms, like this curved arrow
or that curved arrow, we're showing the movement
of valence electrons. We used electronegativity a lot. That's how we figured out our nucleophile and our electrophile. The third Schwartz principle
was acid-base chemistry. Well, that was the second
step of this mechanism, right? So the second step of the
mechanism was acid-base chemistry, and you see acid-base reactions a lot in organic chemistry mechanisms. The fourth principle was redox. This is actually a redox reaction. If you assign some oxidation states, you'll see that our starting
compound is reduced, right? This ketone is reduced to an alcohol. And finally, nucleophile and electrophile. Obviously, that was the
first step of our mechanism and something that we've been focusing on. So you don't necessarily have to have all five things in one mechanism. This one just happens
to have all five things, and so, I wanted to talk
about the Schwartz principles. And if you understand those
five concepts really well, mechanisms will be a lot easier for you.