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Course: Physics library > Unit 17
Lesson 3: Quantum numbers and orbitalsThe quantum mechanical model of the atom
Introduction to the quantum mechanical model of the atom: Thinking about electrons as probabilistic matter waves using the de Broglie wavelength, the Schrödinger equation, and the Heisenberg uncertainty principle. Electron spin and the Stern-Gerlach experiment.
Key points
- Louis de Broglie proposed that all particles could be treated as matter waves with a wavelength lambda, given by the following equation:
- Erwin Schrödinger proposed the quantum mechanical model of the atom, which treats electrons as matter waves.
- Schrödinger's equation, H, with, hat, on top, \psi, equals, E, \psi, can be solved to yield a series of wave function \psi, each of which is associated with an electron binding energy, E.
- The square of the wave function, \psi, squared, represents the probability of finding an electron in a given region within the atom.
- An atomic orbital is defined as the region within an atom that encloses where the electron is likely to be 90% of the time.
- The Heisenberg uncertainty principle states that we can't know both the energy and position of an electron. Therefore, as we learn more about the electron's position, we know less about its energy, and vice versa.
- Electrons have an intrinsic property called spin, and an electron can have one of two possible spin values: spin-up or spin-down.
- Any two electrons occupying the same orbital must have opposite spins.
Introduction to the quantum mechanical model
"We must be clear that when it comes to atoms, language can only be used as in poetry." —Niels Bohr
Matter begins to behave very strangely at the subatomic level. Some of this behavior is so counterintuitive that we can only talk about it with symbols and metaphors—like in poetry. For example, what does it mean to say an electron behaves like a particle and a wave? Or that an electron does not exist in any one particular location, but that it is spread out throughout the entire atom?
If these questions strike you as odd, they should! As it turns out, we are in good company. The physicist Niels Bohr also said, "Anyone who is not shocked by quantum theory has not understood it." So if you feel confused when learning about quantum mechanics, know that the scientists who originally developed it were just as befuddled.
We will start by briefly reviewing Bohr's model of hydrogen, the first non-classical model of the atom.
Review of Bohr's model of hydrogen
As we have seen in a previous article on the Bohr model, the emission spectra of different elements contain discrete lines. The following image shows the visible region of the emission spectra for hydrogen.
The quantized emission spectra indicated to Bohr that perhaps electrons could only exist within the atom at certain atomic radii and energies. Recall that quantized refers to the fact that energy can only be absorbed and emitted in a range of allowable values rather than with any possible value. The following diagram of the Bohr model shows the electron existing in a finite number of allowed orbits or shells around the nucleus.
From this model, Bohr derived an equation that correctly predicted the various energy levels in the hydrogen atom, which corresponded directly to the emission lines in the hydrogen spectrum. Bohr's model was also successful at predicting the energy levels in other one-electron systems, such as start text, H, e, end text, start superscript, plus, end superscript. However, it failed to explain the electronic structure in atoms that contained more than one electron.
While some physicists initially tried to adapt Bohr's model to make it useful for more complicated systems, they eventually concluded that a completely different model was needed.
Wave-particle duality and the de Broglie wavelength
Another major development in quantum mechanics was pioneered by French physicist Louis de Broglie. Based on work by Planck and Einstein that showed how light waves could exhibit particle-like properties, de Broglie hypothesized that particles could also have wavelike properties.
De Broglie derived the following equation for the wavelength of a particle of mass start text, m, end text (in kilograms start text, k, g, end text), traveling at velocity start text, v, end text (in start fraction, start text, m, end text, divided by, start text, s, end text, end fraction), where lambda is the de Broglie wavelength of the particle in meters and h is Planck's constant, 6, point, 626, times, 10, start superscript, minus, 34, end superscript, start fraction, start text, k, g, end text, dot, start text, m, end text, squared, divided by, start text, s, end text, end fraction:
Note that the de Broglie wavelength and particle mass are inversely proportional. The inverse relationship is why we don't notice any wavelike behavior for the macroscopic objects we encounter in everyday life. It turns out that the wavelike behavior of matter is most significant when a wave encounters an obstacle or slit that is a similar size to its de Broglie wavelength. However, when a particle has a mass on the order of 10, start superscript, minus, 31, end superscript kg, as an electron does, the wavelike behavior becomes significant enough to lead to some very interesting phenomena.
Concept check: The fastest baseball pitch ever recorded was approximately 46.7 start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. If a baseball has a mass of 0.145 kg, what is its de Broglie wavelength?
Example 1: Calculating the de Broglie wavelength of an electron
The velocity of an electron in the ground-state energy level of hydrogen is 2, point, 2, times, 10, start superscript, 6, end superscript, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. If the electron's mass is 9, point, 1, times, 10, start superscript, minus, 31, end superscript kg, what is the de Broglie wavelength of this electron?
We can substitute Planck's constant and the mass and velocity of the electron into de Broglie's equation:
The wavelength of our electron, 3, point, 3, times, 10, start superscript, minus, 10, end superscript meters, is on the same order of magnitude as the diameter of a hydrogen atom, ~1, times, 10, start superscript, minus, 10, end superscript meters. That means the de Broglie wavelength of our electron is such that it will often be encountering things with a similar size as its wavelength—for instance, a neutron or atom. When that happens, the electron will be likely to demonstrate wavelike behavior!
The quantum mechanical model of the atom
Standing waves
A major problem with Bohr's model was that it treated electrons as particles that existed in precisely-defined orbits. Based on de Broglie's idea that particles could exhibit wavelike behavior, Austrian physicist Erwin Schrödinger theorized that the behavior of electrons within atoms could be explained by treating them mathematically as matter waves. This model, which is the basis of the modern understanding of the atom, is known as the quantum mechanical or wave mechanical model.
The fact that there are only certain allowable states or energies that an electron in an atom can have is similar to a standing wave. We will briefly discuss some properties of standing waves to get a better intuition for electron matter waves.
You are probably already familiar with standing waves from stringed musical instruments. For example, when a string is plucked on a guitar, the string vibrates in the shape of a standing wave such as the one shown below.
Notice that there are points of zero displacement, or nodes, that occur along the standing wave. The nodes are marked with red dots. Since the string in the animation is fixed at both ends, this leads to the limitation that only certain wavelengths are allowed for any standing wave. As such, the vibrations are quantized.
Schrödinger's equation
How are standing waves related to electrons in an atom, you may ask?
On a very simple level, we can think of electrons as standing matter waves that have certain allowed energies. Schrödinger formulated a model of the atom that assumed the electrons could be treated at matter waves. While we won't be going through the math in this article, the basic form of Schrödinger's wave equation is as follows:
\psi is called a wave function; H, with, hat, on top is known as the Hamiltonian operator; and E is the binding energy of the electron. Solving Schrödinger's equation yields multiple wave functions as solutions, each with an allowed value for E.
Interpreting exactly what the wave functions tell us is a bit tricky. Due to the Heisenberg uncertainty principle, it is impossible to know for a given electron both its position and its energy. Since knowing the energy of an electron is necessary for predicting the chemical reactivity of an atom, chemists generally accept that we can only approximate the location of the electron.
How do chemists approximate the location of the electron? The wave functions that are derived from Schrödinger's equation for a specific atom are also called atomic orbitals. Chemists define an atomic orbital as the region within an atom that encloses where the electron is likely to be 90% of the time. In the next section, we will discuss how electron probabilities are determined.
Orbitals and probability density
The value of the wave function \psi at a given point in space—x, comma, y, comma, z—is proportional to the amplitude of the electron matter wave at that point. However, many wave functions are complex functions containing i, equals, square root of, minus, 1, end square root, and the amplitude of the matter wave has no real physical significance.
Luckily, the square of the wave function, \psi, squared, is a little more useful. This is because the square of a wave function is proportional to the probability of finding an electron in a particular volume of space within an atom. The function \psi, squared is often called the probability density.
The probability density for an electron can be visualized in a number of different ways. For example, \psi, squared can be represented by a graph in which varying intensity of color is used to show the relative probabilities of finding an electron in a given region in space. The greater the probability of finding an electron in a particular volume, the higher the density of the color in that region. The image below shows the probability distributions for the spherical 1s, 2s, and 3s orbitals.
Notice that the 2s and 3s orbitals contain nodes—regions in which an electron has a 0% probability of being found. The existence of nodes is analogous to the standing waves we discussed in the previous section. The alternating colors in the 2s and 3s orbitals represent regions of the orbital with different phases, which is an important consideration in chemical bonding.
Another way of picturing probabilities for electrons in orbitals is by plotting the surface density as a function of the distance from the nucleus, r.
The surface density is the probability of finding the electron in a thin shell with radius r. This is called a radial probability graph. On the left is a radial probability graph for the 1s, 2s, and 3s orbitals. Notice that as the energy level of the orbital increases from 1s to 2s to 3s, the probability of finding an electron farther from the nucleus increases as well.
Shapes of atomic orbitals
So far we have been examining s orbitals, which are spherical. As such, the distance from the nucleus, r, is the main factor affecting an electron's probability distribution. However, for other types of orbitals such as p, d, and f orbitals, the electron's angular position relative to the nucleus also becomes a factor in the probability density. This leads to more interesting orbital shapes, such as the ones in the following image.
The p orbitals are shaped like dumbbells that are oriented along one of the axes—x, comma, y, comma, z. The d orbitals can be described as having a clover shape with four possible orientations—with the exception of the d orbital that almost looks like a p orbital with a donut going around the middle. It's not even worth attempting to describe the f orbitals!
Electron spin: the Stern-Gerlach experiment
The last quantum phenomenon we will discuss is that of electron spin. In 1922, German physicists Otto Stern and Walther Gerlach hypothesized that electrons behaved as tiny bar magnets, each with a north and south pole. To test this theory, they fired a beam of silver atoms between the poles of a permanent magnet with a stronger north pole than south pole.
According to classical physics, the orientation of a dipole in an external magnetic field should determine the direction in which the beam gets deflected. Since a bar magnet can have a range of orientations relative to the external magnetic field, they expected to see atoms being deflected by different amounts to give a spread-out distribution. Instead, Stern and Gerlach observed the atoms were split cleanly between the north and south poles. Watch the following awesome video to see the hypothesis and experiment in action!
These experimental results revealed that unlike regular bar magnets, electrons could only exhibit two possible orientations: either with the magnetic field or against it. This phenomenon, in which electrons can exist in only one of two possible magnetic states, could not be explained using classical physics! Scientists refer to this property of electrons as electron spin: any given electron is either spin-up or spin-down. We sometimes represent electron spin by drawing electrons as arrows pointing up, \uparrow, or down, \downarrow.
One consequence of electron spin is that a maximum of two electrons can occupy any given orbital, and the two electrons occupying the same orbital must have opposite spin. This is also called the Pauli exclusion principle.
Summary
- Louis de Broglie proposed that all particles could be treated as matter waves with a wavelength lambda given by the following equation:
- Erwin Schrödinger proposed the quantum mechanical model of the atom, which treats electrons as matter waves.
- Schrödinger's equation, H, with, hat, on top, \psi, equals, E, \psi, can be solved to yield a series of wave function \psi, each of which is associated with an electron binding energy, E.
- The square of the wave function, \psi, squared, represents the probability of finding an electron in a given region within the atom.
- An atomic orbital is defined as the region within an atom that encloses where the electron is likely to be 90% of the time.
- The Heisenberg uncertainty principle states that we can't know both the energy and position of an electron. Therefore, as we learn more about the electron's position, we know less about its energy, and vice versa.
- Electrons have an intrinsic property called spin, and an electron can have one of two possible spin values: spin-up or spin-down.
- Any two electrons occupying the same orbital must have opposite spins.
Want to join the conversation?
Why is the spin number expressed as +1/2 or -1/2, rather than just +1 or -1 ?(96 votes)
In the spin quantum number the electrons are represented either by +1/2 or -1/2, and as shown in the quantum numbers video it is said that the electrons in this type, i.e the spin number can move in two directions ,one towards the left and one towards the right, so as electrons possess like charges(-ve) and because they might be travelling in the opposite directions and finally when they come close to each other they repel, so the electron almost covers 1/2 the circular orbit so probably that is why it is assigned the value +1/2 and -1/2.(4 votes)
referring to the image on orbital shapes,
why do the p,d,f orbitals have such "out of the blue" shapes? how were these shapes found out or calculated?(15 votes)
The shapes have been calculated from Schrodinger's equation.
Moreover , the shapes represent the region where the probability of finding the electrons is maximum. The orbitals have NO physical BOUNDARY.(26 votes)
I've some questions on this statement:
The square of the wave function represents the probability of finding an electron in a given region within the atom.
Why function square related to probability?(16 votes)
It's mostly a function in mathematics. It would be like asking "what is the average distance of a cosine wave from the center?" - and this might seem easy at first until you realize that the gradient of the wave function keeps changing. Mathematically, the average distance, or in this case the energy or probability of finding the electron, is just the square root of the wave property.(16 votes)
- So the formula for de Broglie equation says that
lambda= h/mv
and..the v of a stationary object will be 0,
so by mathematical solving it means that the wavelength of a stationary object is infinite?
is this the correct thinking or is there some other theory for a stationary object's wavelength?(13 votes)
Isn't to do with the fact that the velocity is not quite 0? if you know it is exactly 0 then the uncertainty in the position is infinite as well (momentum is a function of velocity, so delta P = 0 -> delta V = 0 -> delta X = inf) therefore it has an equal probability of being anywhere. If you take the infinite wavelength interpretation, then it would be nearly 0 (1/inf) but constant everywhere. The square (probability function) shows that it has an equal chance of being anywhere.
So, if you know with 0 uncertainty what the velocity is, then you have no idea where it is, and all future involvement of the particle is pretty much irrelevant (how is the electron going to diffract around an atom if the electron is in a different galaxy?). As we can't physically measure to perfect accuracy, there is an uncertainty in both measurements of the degree that we know it's probably stationary and it's probably 'over there'. With this uncertainty, the velocity is almost definitely not 0. (1 value in a range of reals is like trying to throw a dart at a dartboard with an infinitely thin wire and hitting the wire). For another layer, you can take the fact that you can never cool anything down to exactly 0K (-273.15C) (although you can get close) and so nothing will ever have 0 velocity.(21 votes)
In reference to Shrodinger's Equation, what's the difference between the V (wave function symbol) on the left side of the equation and the right? There must be some difference, or else they would cancel.(5 votes)
You can't cancel out the ψ's like that because Hψ is not H times ψ but rather H operating on ψ (that's what the ^ over the H indicates).
The Hamiltonian operator H is actually
H = -ℏ²/2m * d²/dx² + U(x)
so the time independent Schrodinger equation is actually
-ℏ²/2m * d²ψ/dx² + U(x)ψ = Eψ
solving for E gives the allowable energy states of the system.(20 votes)
On Schrödinger's equation, what exactly is the Hamiltonian operator?
How do we work with it mathematically and what would be its physical interpretation?(10 votes)
This has to do with Laplacian operator (partial derivative) of a wave function.
Here's the formula http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/sch3d.html (I can't type out the partial derivative operator -__-")
The h-bar in the equation is defined by h/(2pi)(8 votes)
I have a really blurry picture of what it means for small particles to behave as both particles and waves. What does it exactly mean when we say that small particle have characteristics of both waves and particle ?(3 votes)- I think I can safely say that nobody understands quantum mechanics.
- Feynman
So you are right on track! :)
But to be more pedagogical, you can view them as different behaviors in different situations. When behaving as particles, they show all what we "expect" them to based on our experiences. But under different conditions, they behave as waves, where in these "waves" are equations that determine, in a simple sense, the probability of the particle to be at a particular place at a particular time. Since these equations are not the classic Newtonian equations, their predictions often create the strange outcomes we usually see. (See the double slit experiment to understand the differing behaviors.)(11 votes)
Does anyone know exactly what "spin" is? If a particle has "spin", it doesn't actually physically spin/turn/rotate, right?
In the article, it said that the opposite "spins" of electrons are determined by how the react in a magnetic field. But does this explain what it means for other particles - other leptons, quarks, hadrons - to have spin? What is spin? Please help!(2 votes)- Spin is just a property that electrons (and other particles) have. It got named spin back when people were working with the Bohr model and trying to extend it to atoms beyond hydrogen. Just as Bohr imagined that the atoms were little planets revolving around the nucleus as though it were a sun, other scientists tried to extend that idea by imagining that the little planets, just like real planets, had spin. Using this concept actually helped a bit, just like Bohr's imagination of little orbits helped a bit, but again, the electrons are not like little planets: they don't revolve around the nucleus, and they don't rotate on their axes. Still, they have a property that works sort of like an orbit (orbitals) and they have a property that works sort of like rotation about an axis (spin). But there is no point in trying to answer "what is electron spin" by referring to some familiar object like a ball or a planet, because electrons are not balls or planets, they are their own thing, and you just have to accept that they have a property whose effects we understand very well, and we happen to have named it spin. "What is spin" doesn't have any deeper answer than does the question "what is charge". It's just a characteristic that particles have or don't have, and we know what the effect is of having or not having that property.
We have other properties like this for other particles. A quark can be an up quark or a down quark. "Up" and "down" don't have any meaning other than to identify the type of quark. THere's nothing "up-ish" about an up quark. THere's a top quark and a bottom quark. There's a charmed quark and a strange quark. There's nothing unusually strange about the strange quark. It's just the name that we've given a quark that has certain properties.
IN the field of quantum chromodynamics, we say that particles have a color. They don't really have a color, we just use that idea because it's sort of helpful, just like using the idea of positive and negative for charges is helpful.(9 votes)
Do nodes of the 1s, 2s, 3s... subshells overlap?
(wrt to the graph shown above, it seems they do)
If yes, do the nodes of another subshell also overlap,
[in fact, if the probability of finding an electron is 0, shouldn't the nodes always overlap(even if multiple subshells /orbitals pass through)?](2 votes)- Atomic orbitals are defined by energy levels not positions. The electron clouds that are depicted are usually where there is a 90% chance of finding the electron at that energy level. The electron clouds for different energy levels do have overlaps.(5 votes)
Can we specify type of the wave in schrodinger wave? like transversal or longitudinal(3 votes)
I never thought about it before. Its interesting question.
My guess is that it is transverse. though, to honest, there is so much dispute about the wave function and what it actually is, maybe we need to answer that quesiton before we can say tranverse, longitudinal or.... something else?(3 votes)
