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Course: MCAT > Unit 8
Lesson 9: Kinetic molecular theory of gasesBoltzmann's constant
Explore Ludwig Boltzmann's groundbreaking atomic theory and his constant's role in thermal physics. Understand the kinetic-molecular explanation of temperature, the ideal gas law, and the concept of entropy. Uncover the microscopic details of gas molecules and their impact on our understanding of heat energy. Created by David SantoPietro.
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- What if the pressure is in atmospheric pressure units or _mm of Hg column, what is the gas constant then??(3 votes)
- If u use atm as pressure unit,
R=0.0821 L atm K^−1 mol^−1
If u use mm of Hg,
R=62.33 L mmHg K^-1 mol^-1(7 votes)
- If heat is really just Kinetic Energy of gas molecules as he says at2:30, then how can heat be transferred through a vacuum like in space?(3 votes)
- Heat is not just Kinetic Energy. IMHO, I'd rather think of Heat as a form of energy, than thinking of is as a measure of how-much-things-vibrate .
Digging the physics behind, phonon is the best way to describe heat. :)
Heat can be transferred is one of three forms. Namely Conduction (solid-to-solid), Convection(liquid-to-liquid) or Radiation(thru vacuum). The first two are quite straightforward, but vacuum.. is a bit different(or shall I say.. special?).
I would like to use a light bulb as example. To turn on tungsten light bulb :
[1] Turn on the circuit
[2] Bulb will light up
[3] After a while the bulb surface and air at its surrounding gets hot.
In step [1], the Energy conversion is : Chemical Energy > Electrical Energy.
In [2], Electrical Energy > Heat Energy > Light Energy
In [3], Light Energy > Heat Energy(on bulb surface and on its surrounding).
In [2], the tungsten filament gets hot, then it radiates. it "radiates", means that the emitted light is within the human visibility spectrum (wavelength 390-700 nm).
At the same time, the tungsten doesn't (or very minimally) conduct heat via conduction or convection as the medium is vacuum. The heat was radiated as heat energy packets, in literature, referred as phonon.
In [3], every energy packets are absorbed by other material with mass and translated into vibration(or kinetic energy). :)
Heat is an interesting physical properties. Its application includes solar energy harvester and the natures photosynthesis (the only way for earth to get Sun's energy).
p/s : I had exactly the same question years back. I'd say that.. the real physics behind it no way straightforward, at least for me. Happy exploring. \(^_^)/(5 votes)
- just wanted to point out that the container at0:39is an optical illusion. Depending on your perspective, it looks cube, but there are two possible "orientations" of the cube. Neat!(2 votes)
- Why, when the Quantum Boltzmann distribution function is deduced from the canonical distribution, this canonical distribution can be applied to just one molecule, since, as we know, the physical physics studies the macrocoscopic bodies (with a very large number of atoms / molecules)?(1 vote)
- i hv a doubt regarding boyles law.
boyles law holds good for any gas at high temperature and low pressure but it also says this law is independent of the selection of scale of temperature since temperature is kept constant..
how? please explain....(1 vote)- Because all temperature scales are interconvertible (you can change from K to C to F), it does not matter which one you select for calculations as long as you use the same scale for all calculations in a single problem.(1 vote)
- The amount of heat energy required to raise the temperature of 1 g of Helium at NTP, from T1 K to T2 K is -(1 vote)
- Can we technically say that the Boltzmann constant is in SI base units of J/K*molecules? I assume that part was left out because in the microscopic ideal gas law we multiply it by N (number of molecules).(1 vote)
- Boltzman constant stand for gas, constant for single molecule?
as the unit of Boltzman constant is j/Molecule-Kelvn ?(1 vote)
Video transcript
- [Instructor] Let's talk
about Boltzmann's constant. It's named after, first of all,
this guy, Ludwig Boltzmann, who was a genius. He lived in the late
1800s and early 1900s, and he was the father
of modern atomic theory, one of the big proponents,
early proponents that the world is made out
of atoms and molecules. This sounds obvious to us now, but 120 years ago, it was
definitely not obvious and some of the smartest people of his day vehemently disagreed with Boltzmann and Boltzmann had to defend
these ideas over and over. And what I mean by atomic theory is this. If you had a container of, say, anything, could be a cube of metal,
let's just say it's a gas, let's say it's a container
and it's full of air. Well, it feels like the
air is continuous in here or like the gold, if
this was a cube of gold, the gold is continuous. But we know now, and Boltzmann knew, that it's really made out
of atoms and molecules. That wasn't obvious 120 years ago 'cause you can't see
the atoms and molecules. If this was a container
of steam, let's say, and you stuck your hand in here, so I took my hand, I put my hand in this container of steam, I'd notice it, I'd know
something was going on. My hand would start to feel hot. There's energy being transferred here, but it wasn't obvious what
exactly is the mechanism. Is this a new kind of energy? Is this one of our old kind
of energies just in disguise? Boltzmann's big claim and
groundbreaking idea was that this gas, if it's steam, let's say, is really made out of atoms and molecules. These gas molecules are
running around in here. There's just little particles in here. And what you're actually feeling are these particles striking your hand, so your hand's just getting
bombarded by these particles. But they're so small and
they're so many of them, you can't really tell
that there's particles. It just looks completely continuous. So for Boltzmann, this heat energy isn't really a new kind of energy at all. All this is, this heat
energy that you're feeling is just kinetic energy, and if it's steam, it's
just the kinetic energy in the H2O molecules flying around in here at some rapid speed. And the faster they go,
the greater the impact with your hand, which is
gonna transfer more energy. So the faster they go, the
hotter it feels in here. So, for Boltzmann, to say that something has a high temperature, if you said that the temperature is large, if it's hot outside, that's kind of redundant. We already had a word for that. We could just say if
it's a high temperature, what we really mean is that
the average kinetic energy of the gas molecules outside is large. So, if a gas has a high temperature, the average kinetic energy
of those molecules is large. That's why it hurts when
they impact on your skin 'cause they're transferring kinetic energy to the molecules in your hand, and when your hand
absorbs too much energy, these molecules move around, your skin starts to get damaged, you can get burned. So this is often referred
to as the kinetic-molecular explanation of temperature. And the details of this theory were one of Ludwig Boltzmann's biggest contributions to science. But what does any of this have to do with Boltzmann's constant? Well, let's get rid of all of this. You've probably heard
of the ideal gas law, PV equals nRT. So, remember, T is the
temperature measured in Kelvin. P is the pressure, and I'm
gonna measure this pressure in, I'm gonna choose to measure it in Pascals. V is the volume, I'm gonna choose to
measure it in meters cubed. And n, little n, remember, little n is the number of moles of the gas. And if you've forgotten what moles are, n, the number of moles, is defined to be capital N, the number
of molecules in the gas, the total number of molecules in the gas, divided by a constant and
that constant's called Avogadro's number. And if you've forgotten Avogadro's number, Avogadro's number is 6.02
times 10 to the 23rd, and there's that many molecules per mole. So in every mole of a gas, what we mean by one mole of a gas is 6.02 times 10 to the 23rd molecules. And if you choose these units, this R, this gas constant, R
is called the gas constant, and it has a value, R has a value of 8.31 Joules per mole Kelvin. That's the gas constant
R with these units. But these are pretty
macroscopic quantities, pressure and volume and
temperature and moles. Even moles, talking about one or two moles is talking about a huge
number of molecules. You're kinda glossing over some
of the microscopic details, so an alternate way to
write the ideal gas law is P times V equals capital
N, so forget moles. Let's say we want to talk about how many molecules there are. Instead of writing little n, let's write big N, number of molecules. We'd need a different constant 'cause we're gonna multiply by the same T. So again, this T is still
temperature in Kelvin. P is still the pressure in Pascals. V is the volume, again, in meters cubed. N, instead of being the number of moles, is now the number of molecules, and that means we need
a new constant here. We need a different constant, and that constant's gotta
be really, really small. The rest of this stuff's the same. P times V and T are all the same. And all I did was I swapped
out little n, number of moles, for big N, number of molecules, so this is gonna be a huge
number we're plugging in into this spot now. Instead of plugging in like, say, two, if I were to plug in two moles
right here, the number two, down here, I'd plug in two times this. So I'd plug in 12.04 times 10 to the 23rd. Since this is a huge number, I need a constant that's really small because it's gotta balance out. We know that n times R
has gotta be the same as capital N times this constant because the rest of this is the same. This left hand side's the
same and the T's the same. So if this is all consistent and n times R has gotta be equal to N times this new constant, and that new constant
is Boltzmann's constant. It's a lowercase k with a B on it to denote Boltzmann's constant. So what's the value of
Boltzmann's constant? We can find it pretty easily. We know that little n times R has gotta equal big N
times Boltzmann's constant, so if we just solve this
for Boltzmann's constant, we're gonna get little
n over big N times R. But what's little n over big N? Just look up here, we can figure it out. Little n over big N, if I solve this for little n over big N, what I'm gonna get is, if I
divide both sides by big N, I get one over Avogadro's number. Little n over big N right
here is Avogadro's number, or one over Avogadro's number. So I get that one over Avogadro's number times the gas constant, this 8.31, is Boltzmann's constant. If you multiply that out, the
gas constant, which is 8.31 Joules per mole Kelvin, and divide by Avogadro's
number, which is 6.02 times 10 to the 23rd molecules per mole, you'll get Boltzmann's constant, which equals 1.38 times
10 to the negative 23rd Joules per Kelvin. This is Boltzmann's constant, this number right here
is Boltzmann's constant. Why do we care about Boltzmann's constant? Well, it allows us to write a more microscopically oriented version of the ideal gas law that focuses on number of molecules
instead of number of moles, and this number pops up all over statistical
and thermal mechanics. It's one of the most important constants in all of thermal physics, in fact. It was so important that on
Boltzmann's own gravestone, if you go to Boltzmann's grave, there's a bust and a gravestone, it doesn't actually look like a cross but there's a grave there with a big inscription and
there's an inscription. The big inscription is an equation, S equals Boltzmann's constant times log W. This was possibly his most
important contribution, and it says that the entropy of a system is equal to, this k's
Boltzmann's constant, we just talked about that. Log, it says l-o-g, but nowadays we use ln because really, they meant
the natural logarithm here and nowadays it's conventional
that l-o-g is log base 10 but this equation is really
referring to the natural log. And W, W's kinda
mysterious like entropy is. W is the number of microstates. So if you had a macroscopic system and you wanted to know microscopically what are all the ways I
can arrange my particles with given speeds and
distributions and positions such that it looks identical, the macroscopic state for
someone standing out here. They would look at this
thing and they'd be like, that's the exact same state. But the particles are doing
something different in here. It's just on a macroscopic
level identical. How many ways are there to do that and still make the macroscopic view identical for this person out here? That's what this is measuring, the number of microstates. And if you take Boltzmann's constant times the natural log of that number, it gives you an idea of the entropy. Entropy's very mysterious and interesting, has to do with the disorder or
available energy in a system. I don't have enough time
to describe it right now, but if you have time, you
should look into this. This is mysterious and confusing and wonderful at the same time.