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# Graphing linear equations — Basic example

Watch Sal work through a basic Graphing linear equations problem.

## Want to join the conversation?

• i want to know where can i get a video on statistics
i really need it as i lack in it

• In the math tab, there is a section called "Probability and statistics".
• I am confused why and how did sal know it was the first graph?
• Sal knew that the graph had to start at \$1000 because that is what the question said. That eliminated two of the possibilities that started at 0 and at \$500. Two down, two to go in about 10 seconds of your valuable time.
We can choose between the other two by calculating a couple of points and comparing to the graphs that remain. The words of the problem say that the bond increases at \$75 per year. Because the vertical scale is so large, we need a bunch of years to show a good enough increase to be able to read the difference.
At 75 per year, this would increase \$300 in 4 years (75 x 4 = 300). Add that to \$1000 to get \$1300 at the 4th year. The third graph example grows 900 in 4 years, (\$1900), while the first graph is right on track at under \$1500 in the 4th year. It looks really close to \$1300.
Choose graph one and `happy dance` on to the next question.
• i should probably concentrate alot more
• Yes, you must because it's math so yeah.
• When graphing an inequality do we shade the region with a solution or without a solution?
• If the inequality is „ or … then we draw a solid line. If the inequality is < or > then we draw a dotted line. After drawing the line, we need to shade the unwanted region. Rewrite the inequality 2 x – 3 y ≥ 6 as y ≤ x – 2. Since the inequality is ≤ , the wanted region is below the line. We shade below the line.
When graphing inequalities, you shade all areas that x and/or y can be. If the number is x, you shade left and right. If x is anywhere from -11 to ∞, then shade the area to the right of -11. If it is from -∞ to 5, shade the areas to the left of 5
(1 vote)
• yall from 8 years ago yall like grown ups
• In , Sal explains that "you want one of them to be 180". Why would that be? Why wouldn't it be 300? Is it because we're dealing mainly with time in the word problem?
• because every year, they increase by 75\$ only
• considering i have my psat on the 14th, I need help!