I do not understand the graph equation

You need to find the x values on both lines and multiply them together to find the value for the new graph of f*g(x). For example at x=4, g(4)=0 and f(4)=4 so f*g(4)=0 (multiply the two values together). When x=6, g(6)=-1 and f(6)=6 so f*g(6)=-6. With these two values, you know that the new graph will pass through the two points (4, 0) and (6,-6) which only happens in Graph B.

Question one of both the multiplying and dividing questions seems to be missing the button that allows me to add an exponent to the problem

Use the "carat" on the "6" key by pressing SHIFT at the same time you press the 6. For example, x squared is x^2 and x cubed is x^3, etc.

The explanation for the last one doesn't make sense. Is there a simpler explanation?

It does make sense.... You need to find points that correspond to (f*g)(x) = f(x) * g(x). Sal creates a table of values for f(x) and g(x) from looking at the original graph. Le'ts do one ... Find f(4). If x = 4, then f(4) = 4 -- You find this by going right on the x-axis until you get to 4. Then, you go up until you hit the line that represents f(x). Then, you find the y-coordinate for this point. Find g(4). If x = 4, then g(4) = 0 -- You find this similar to how you found f(4) except you find the point that is on the g(x) graph and find its y-coordinate. Once you have f(4) and g(4), you can find f(4) * g(4) = 4 * 0 = 0 Thus the point for (f*g)(4) = (4, 0) You can compare this point and other points to determine which graph to pick. Hope this helps.

how do you multiply polynomials such as (3x^2+6x-2)(2x^2-9x+16)?

The parentheses indicate that each term in the second polynomial has to be multiplied by each term in the first polynomial. So, first of all, multiply the second polynomial by 3x^2, then by 6x, then by -2. Finally, combine like terms.

I'm just curious, but for the last question, what kind of function will lead me to those graph?

g(x) is the graph of sin, a trig function.

Main content

Algebra (all content)

Course: Algebra (all content) > Unit 7

Lesson 14: Combining functions

Multiplying and dividing functions

CCSS.Math:

HSF.BF.A.1b

Google Classroom

See how we can multiply or divide two functions to create a new function.

Just like we can multiply and divide numbers, we can multiply and divide functions. For example, if we had functions f and g, we could create two new functions: f, dot, g and start fraction, f, divided by, g, end fraction .

Multiplying two functions

Example

Let's look an example to see how this works.

Given that f, left parenthesis, x, right parenthesis, equals, 2, x, minus, 3 and g, left parenthesis, x, right parenthesis, equals, x, plus, 1, find left parenthesis, f, dot, g, right parenthesis, left parenthesis, x, right parenthesis.

Solution

The most difficult part of combining functions is understanding the notation. What does left parenthesis, f, dot, g, right parenthesis, left parenthesis, x, right parenthesis mean?

Well, left parenthesis, f, dot, g, right parenthesis, left parenthesis, x, right parenthesis just means to find the product of f, left parenthesis, x, right parenthesis and g, left parenthesis, x, right parenthesis. Mathematically, this means that left parenthesis, f, dot, g, right parenthesis, left parenthesis, x, right parenthesis, equals, f, left parenthesis, x, right parenthesis, dot, g, left parenthesis, x, right parenthesis.

Now, this becomes a familiar problem.

\begin{aligned} (f\cdot g)(x) &= f(x)\cdot g(x)&\gray{\text{Define.}} \\\\ &= \left(2x-3\right)\cdot\left(x+1\right) &\gray{\text{Substitute.}} \\\\ &= 2x^2+2x-3x-3&\gray{\text{Distribute.}} \\\\ &=2x^2-x-3&\gray{\text{Combine like terms.}} \end{aligned}

Note: We simplified the result to obtain a nicer expression, but this is not necessary.

Let's try some practice problems.

Problem 1

\begin{aligned} &c(y)=3y-4 \\\\ &d(y)=3-2y \end{aligned}

Find left parenthesis, c, dot, d, right parenthesis, left parenthesis, y, right parenthesis.

Problem 2

\begin{aligned} &m(x)=x^2-3x \\\\ &n(x)=x-5 \end{aligned}

Evaluate left parenthesis, m, dot, n, right parenthesis, left parenthesis, minus, 1, right parenthesis.

Dividing two functions

Dividing two functions works in a similar way. Here's an example.

Example

h, left parenthesis, n, right parenthesis, equals, 2, n, minus, 1 and j, left parenthesis, n, right parenthesis, equals, n, plus, 3.

Let's find left parenthesis, start fraction, j, divided by, h, end fraction, right parenthesis, left parenthesis, n, right parenthesis.

Solution

By definition, left parenthesis, start fraction, j, divided by, h, end fraction, right parenthesis, left parenthesis, n, right parenthesis, equals, start fraction, j, left parenthesis, n, right parenthesis, divided by, h, left parenthesis, n, right parenthesis, end fraction.

We can now solve the problem.

\begin{aligned} \left(\dfrac{j}{h}\right)(n)&=\dfrac{j(n)}{h(n)}&\gray{\text{Define.}} \\\\ &= \dfrac{n+3}{2n-1}&\gray{\text{Substitute. }} \end{aligned}

Two important notes about this function:

This function is simplified in its current form.
The input n, equals, start fraction, 1, divided by, 2, end fraction is not a valid input for this function. This is because 2, n, minus, 1, equals, 0 at n, equals, start fraction, 1, divided by, 2, end fraction, and division by 0 is undefined.

Let's try some practice problems

Problem 3

\begin{aligned} &g(t)=t^2-4 \\\\ &h(t)=t+8 \end{aligned}

Find left parenthesis, start fraction, g, divided by, h, end fraction, right parenthesis, left parenthesis, t, right parenthesis.

Problem 4

\begin{aligned} &p(r)=5r-2 \\\\ &q(r)=r+2 \end{aligned}

Evaluate left parenthesis, start fraction, p, divided by, q, end fraction, right parenthesis, left parenthesis, 4, right parenthesis.

Problem 5

\begin{aligned} &f(x)=x+4 \\\\ &g(x)=x-3 \end{aligned}

For which value of x is left parenthesis, start fraction, f, divided by, g, end fraction, right parenthesis, left parenthesis, x, right parenthesis undefined?

An application

The distance and time that Jordan runs each day depends on the number of hours, h, that she works. The distance, D, in miles, and time, T, in minutes, that she runs are given by the functions D, left parenthesis, h, right parenthesis, equals, minus, 0, point, 5, h, plus, 8, point, 5 and T, left parenthesis, h, right parenthesis, equals, minus, 6, h, plus, 90, respectively.

Let function S represent the average speed at which Jordan runs on a day in which she works h hours.

Problem 6

Which of the following correctly defines function S?

(Choice A)
S, left parenthesis, h, right parenthesis, equals, start fraction, minus, 0, point, 5, h, plus, 8, point, 5, divided by, minus, 6, h, plus, 90, end fraction
(Choice B)
S, left parenthesis, h, right parenthesis, equals, left parenthesis, minus, 0, point, 5, h, plus, 8, point, 5, right parenthesis, left parenthesis, minus, 6, h, plus, 90, right parenthesis

Challenge problem

The graphs of y, equals, f, left parenthesis, x, right parenthesis and y, equals, g, left parenthesis, x, right parenthesis are plotted on the grid below.

Which is the graph of y, equals, left parenthesis, f, dot, g, right parenthesis, left parenthesis, x, right parenthesis?

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Leonardo Alfaro
Posted 7 years ago. Direct link to Leonardo Alfaro's post “I do not understand the g...”
I do not understand the graph equation
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(19 votes)
Answer
- Jan Chandler
  Posted 7 years ago. Direct link to Jan Chandler's post “You need to find the x va...”
  You need to find the x values on both lines and multiply them together to find the value for the new graph of f*g(x). For example at x=4, g(4)=0 and f(4)=4 so f*g(4)=0 (multiply the two values together). When x=6, g(6)=-1 and f(6)=6 so f*g(6)=-6. With these two values, you know that the new graph will pass through the two points (4, 0) and (6,-6) which only happens in Graph B.
  Comment on Jan Chandler's post “You need to find the x va...”
  (51 votes)
José Sánchez
Posted 6 years ago. Direct link to José Sánchez's post “in (t^2-4)/(t+8) why is s...”
in (t^2-4)/(t+8) why is simplified and we cannot resolve to t-0.5?
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(7 votes)
Answer
elanbogom
Posted 4 years ago. Direct link to elanbogom's post “this was very helpful 10/...”
this was very helpful 10/10
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(7 votes)
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Yanson Wang
Posted 5 years ago. Direct link to Yanson Wang's post “The explanation for the l...”
The explanation for the last one doesn't make sense. Is there a simpler explanation?
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(3 votes)
Answer
- Kim Seidel
  Posted 5 years ago. Direct link to Kim Seidel's post “It does make sense.... Yo...”
  It does make sense....
  You need to find points that correspond to (f*g)(x) = f(x) * g(x).
  Sal creates a table of values for f(x) and g(x) from looking at the original graph.
  Le'ts do one ...
  Find f(4). If x = 4, then f(4) = 4
  -- You find this by going right on the x-axis until you get to 4. Then, you go up until you hit the line that represents f(x). Then, you find the y-coordinate for this point.
  Find g(4). If x = 4, then g(4) = 0
  -- You find this similar to how you found f(4) except you find the point that is on the g(x) graph and find its y-coordinate.
  
  Once you have f(4) and g(4), you can find f(4) * g(4) = 4 * 0 = 0
  Thus the point for (f*g)(4) = (4, 0)
  
  You can compare this point and other points to determine which graph to pick.
  Hope this helps.
  Comment on Kim Seidel's post “It does make sense.... Yo...”
  (9 votes)
Nour Ali
Posted 4 years ago. Direct link to Nour Ali's post “why do we have to do this”
why do we have to do this
Button navigates to signup pageComment on Nour Ali's post “why do we have to do this”
(6 votes)
Answer
Michael Stehn
Posted 6 years ago. Direct link to Michael Stehn's post “Question one of both the ...”
Question one of both the multiplying and dividing questions seems to be missing the button that allows me to add an exponent to the problem
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(5 votes)
Answer
- Judith Gibson
  Posted 6 years ago. Direct link to Judith Gibson's post “Use the "carat" on the "6...”
  Use the "carat" on the "6" key by pressing SHIFT at the same time you press the 6.
  For example, x squared is x^2 and
  x cubed is x^3, etc.
  Comment on Judith Gibson's post “Use the "carat" on the "6...”
  (2 votes)
21exallb
Posted 5 years ago. Direct link to 21exallb's post “how do you multiply polyn...”
how do you multiply polynomials such as (3x^2+6x-2)(2x^2-9x+16)?
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(1 vote)
Answer
- Judith Gibson
  Posted 5 years ago. Direct link to Judith Gibson's post “The parentheses indicate ...”
  The parentheses indicate that each term in the second polynomial has to be multiplied by each term in the first polynomial.
  So, first of all, multiply the second polynomial by 3x^2, then by 6x, then by -2.
  Finally, combine like terms.
  Button navigates to signup page
  (5 votes)
Elise Tong
Posted 6 years ago. Direct link to Elise Tong's post “a(t)=(t−k)(t−3)(t−6)(t+3)...”
a(t)=(t−k)(t−3)(t−6)(t+3)a, left parenthesis, t, right parenthesis, equals, left parenthesis, t, minus, k, right parenthesis, left parenthesis, t, minus, 3, right parenthesis, left parenthesis, t, minus, 6, right parenthesis, left parenthesis, t, plus, 3, right parenthesis is a polynomial function of ttt, where kkk is a constant. Given that a(2)=0a(2)=0a, left parenthesis, 2, right parenthesis, equals, 0, what is the absolute value of the product of the zeros of aaa?
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(3 votes)
Answer
- Jerry Nilsson
  Posted 6 years ago. Direct link to Jerry Nilsson's post “𝑡 = 2 ⇒ 𝑎(2) = (2 − 𝑘)...”
  𝑡 = 2 ⇒ 𝑎(2) = (2 − 𝑘)(2 − 3)(2 − 6)(2 + 3) = 20(2 − 𝑘)
  
  𝑎(2) = 0 ⇔ 20(2 − 𝑘) = 0 ⇔ 𝑘 = 2
  
  So, 𝑎(𝑡) = (𝑡 − 2)(𝑡 − 3)(𝑡 − 6)(𝑡 + 3), which has zeros 𝑡 = −3, 𝑡 = 2, 𝑡 = 3 and 𝑡 = 6.
  
  |(−3) ∙ 2 ∙ 3 ∙ 6| = 108
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  (1 vote)
hajin son
Posted 7 years ago. Direct link to hajin son's post “I'm just curious, but for...”
I'm just curious, but for the last question, what kind of function will lead me to those graph?
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(1 vote)
Answer
- StarryNight
  Posted 7 years ago. Direct link to StarryNight's post “g(x) is the graph of sin,...”
  g(x) is the graph of sin, a trig function.
  Comment on StarryNight's post “g(x) is the graph of sin,...”
  (4 votes)
Mateo Aguirre
Posted 6 years ago. Direct link to Mateo Aguirre's post “How do you do squared for...”
How do you do squared for practice problem #1?
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(2 votes)
Answer
- Kim Seidel
  Posted 6 years ago. Direct link to Kim Seidel's post “(c*d)(y) = (3y-4)(3-2y) Y...”
  (c*d)(y) = (3y-4)(3-2y)
  You need to multiply 2 binomials. You use FOIL or extended distribution.
  See this video for an example: https://www.khanacademy.org/math/algebra/introduction-to-polynomial-expressions/multiplying-binomials-2/v/multiplying-binomials
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  (1 vote)