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Course: Class 11 Physics (India) - Hindi > Unit 6
Lesson 1: Newton's law of gravitation (Hindi)- Introduction to gravity (Hindi)
- Mass and weight clarification (Hindi)
- Gravity for astronauts in orbit (Hindi)
- Would a brick or feather fall faster? (Hindi)
- Acceleration due to gravity at the space station (Hindi)
- Space station speed in orbit (Hindi)
- Introduction to Newton's law of gravitation (Hindi)
- Gravitation part 2 (Hindi)
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Introduction to gravity (Hindi)
Basics of gravity and the Law of Universal Gravitation. Created by Ram Prakash.
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- How did we find the value of G?(1 vote)
- The numerical value of the Universal Gravitational Constant (G) was determined by the Cavendish experiment.
In this experiment, he attached a string (of known Torsional Constant 𝜏) to the ceiling, and to that string, he attached a rod with 2 spheres whose mass(m1) was known. Then he brought 2 spheres whose masses were also known(m2, m2>m1), close to the respective masses. When brought extremely close, the sphere and the mass on the rod experienced a gravitational force, causing the rope to twist (creating torsion).
𝐹=𝐺𝑚𝑀/𝑑²
At Equilibrium, the magnitude of gravitational torque and restoring torque will be equal.
⇒ 𝐹𝐿 = 𝜏𝜃
⇒(𝐺𝑀𝑚/𝑑²)𝐿=𝜏𝜃
⇒ 𝐺=𝜏𝜃𝑑²/𝐿𝑀𝑚
Upon putting the appropriate values we find:
G=6.67×10^−11𝑁 m²/kg²(1 vote)