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Course: LSAT > Unit 1
Lesson 5: Analytical Reasoning – Worked examples- Ordering setup | Overview | Rules and deductions
- Ordering setup | Given info–basic 1 | Worked example
- Ordering setup | Given info–basic 2 | Worked example
- Ordering setup | Given info–could be true | Worked example
- Ordering setup | Given info–cannot be true 1 | Worked example
- Ordering setup | Given info–cannot be true 2 | Worked example
- Ordering setup | Given info–must be true | Worked example
- Ordering setup | New info–could be true 1 | Worked example
- Ordering setup | New info–could be true 2 | Worked example
- Ordering setup | New info–could be true 3 | Worked example
- Ordering setup | Completely determines | Worked example
- Ordering setup | New info-must be true | Worked example
- Grouping setup | Overview | Rules and deductions
- Grouping setup | Given info–basic | Worked example
- Grouping setup | Given info–could be true | Worked example
- Grouping setup | Given info–must be false | Worked example
- Grouping setup | Given info–must be true 1 | Worked example
- Grouping setup | Given info–must be true 2 | Worked example
- Grouping setup | New info–could be true 1 | Worked example
- Grouping setup | New info–could be true 2 | Worked example
- Grouping setup | New info–must be true | Worked example
- Grouping setup | "Completely determines" | Worked example
- Mixed setup | Overview | Rules and deductions
- Mixed setup | Given info–basic | Worked example
- Mixed setup | Given info–could be true 1 | Worked example
- Mixed setup | Given info–could be true 2 | Worked example
- Mixed setup | Given info–must be true | Worked example
- Mixed setup | Given info–cannot be true | Worked example
- Mixed setup | New info–could be true | Worked example
- Mixed setup | New info–must be true 1 | Worked example
- Mixed setup | New info–must be true 2 | Worked example
- Mixed setup | Rule substitution | Worked example
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Ordering setup | Given info–cannot be true 2 | Worked example
Example video showing how to approach a "Given info: cannot be true" question on an ordering setup from the analytical reasoning section of the LSAT.
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Can't you just say that, because G must be before L, H, and F given the diagram, there is no way it can be 3rd? Since it must have at least 3 behind it..? Seems simpler(3 votes)- You could, that's what she means by "missing some of the deductions." People who took that extra moment to think about about the implications of the rules/deductions probably would've seen that.(1 vote)
So can we add every deduction that we make from these CANNOT questions into our initial setup? (Considering that the deduction was achieved with no temporary rule)(1 vote)
Video transcript
- [Instructor] Before
you tackle this question don't forget to watch the setup video in which we created the initial
diagram that you see here. So the question is which
one of the following can not be the monument
that was begun in 603? So we're looking for a monument that can't ever be in 603 based on
the rules of the setup. Looking at our initial
diagram we marked that H couldn't be in 603. Unfortunately, that
isn't one of the choices. So that means that there's
a deduction that we could have made up front, but we didn't. And if you recall in the setup video, I told you that everything
is solvable even if you miss a deduction here or there. So we're gonna see that
concept in action right now. We're going to test each
choice quickly with our pencil, and then only one of the choices will make us break the rules,
that will be our answer. Choice A is S, can S be in 603? Well let's try it. If S is in 603 then GM would
be the pair that's in 601. We could make L be second,
F be fourth and H be fifth, and that works just fine. B is M, can M be in 603? Well if M is in 603 then
that forces GS to be the pair that's first. L could be second, F could be
fourth and H could be fifth in this situation, so this is fine too. C, can L be in 603? Well if we put L in 603,
lots of possibilities are open to us, we just have
to make one of them work and we can move onto the next choice. Let's put G and S into one, M into two, F into four and H into five. Okay, that works so we can move on. D, can G be in 603? Well if we put G into 603,
that would put M and F as the pair in one. L would have to be fourth
in order to be after G and then F would have
to be fifth in order to be later than L. Well, there's no room for H now. And we could have seen
that in our initial setup but as you can see, it's
not a terribly huge deal that we didn't. So we don't have to beat ourselves up, it certainly may have saved
some time to see initially that G can't be later than
602 due to being followed by L, F and H in some order. But you know what, we solved
this just fine anyway. And as a bonus we now know
that G can never be in 603, so for the remainder of the questions we can keep this new deduction in mind. For the record, E is wrong
because F can be in 603. It could be GM in one, L in
two, F in three, S in four and H in five. So the answer here is D.